Phys 165 Module 10 Exam
An electron in a hydrogen atom jumps from the n = nine energy degree to the n = 4 strength
degree. Answer in 4 sig figs?
What become the power of the electron while inside the n = 9 degree?
What changed into the strength of the electron while it moved to the n = four electricity degree?
What became the power of the photon emitted while the electron jumped from the n = 9 to the n
= 4 energy stage? - ANS-1) En= -thirteen.60 eV/n^2
E9=-thirteen.60 eV/ 9^2
-0.1679 eV --- *-zero.168eV*
2) n= -thirteen.60eV/n^2 E4= -13.60eV/four^2 Answer in four Sig Figs/eV
-thirteen.^2 = *-.Eighty five eV*
three) E9-E4 Answer in 4 Sig Figs/eV
ΔE= E9 - E4
ΔE= (-zero.1679) - (-zero.Eighty five) = 0.682
(0.682) x (1.6x10^-19) = *1.091x10^-19J*
At 1.30 x 10^14 Hz, the energy given off by a blackbody is 1.51 x 10^-17 J.
A. What is the power of this sort of photons of this frequency emitted?
B. How many photons of this frequency are emitted?
Show your paintings. - ANS-Use formula E=hf.
U= h x f
U= (6.62x10^-34) x (1.3x10^14)
*U= 8.606x10^-20 J*
Use method E=nhf revised as n=E/hf. Answer in photons
n= E/ h x f
n= (1.51x10^17 )/ (6.62x10^-34) x (1.3x10^14)
(6.62x10^-34) x (1.3x10^14) = 8.606x10^-20
(1.51x10^-17) / (eight.606x10^20) = *a hundred seventy five Photons*
In the Compton effect, mild is *scattered* off an electron.
True or False: As a end result of this scattering, the *mild's frequency* increases. - ANS-*False*
Light frequency: decreases
, Wavelength: will increase
- all of the scattered X-rays expanded in wavelength.
In the Compton impact, mild is scattered off an electron. What is mild performing like?
A) A particle
B) Electromagnetic wave
C) Both a wave and a particle
D) Neither a wave nor a particle - ANS-A) A particle
The discovery of the electron is credited to which test?
A) The Rutherford Gold Foil Experiment
B) J. J. Thompson's Cathode Ray Tube Experiment
C) The Compton Scattering Experiment
D) The Millikan Oil Drop Experiment - ANS-B) JJ Thompson's Cathode Ray Tube Experiment
The mild from a violet laser has a frequency of seven.20 x 1014 Hz.
What is the wavelength of this mild?
What is the momentum of this light? - ANS-1) Lambda=v/f c=three.00x10^8; f is given answer in
m
(3x10^8) / (7.20x10^14) = *4.17x10^-7m*
2) p= h/lambda in which h is 6.63x10^-34J and lambda is answer from preceding query answer
in kgm/s
P= hf/ c
P = (6.63x10^-34 JxS) x (7.20x10^14) / (3x10^8)
P = *1.59x10^-27 kgm/s*
There were five fashions of the atom defined on this model, put them in the best order. -
ANS-I.P.P.B.E.
*First:* Atom is indivisible
Atoms had been notion to be the smallest part of a substance that still retained the residences
of that substance. It additionally supposed that the atom had no substructure.
*Second:* Plum Pudding Theory or Chocolate Chip Cookie Dough Theory
(cake/ cookie = protons +)
(plum/ chips = electrons -) "stuck in area"
*Third:* Planetary Model
gold sheet
(middle nucleus = middle +)
(electrons around it = -)
(atoms typically open space)
An electron in a hydrogen atom jumps from the n = nine energy degree to the n = 4 strength
degree. Answer in 4 sig figs?
What become the power of the electron while inside the n = 9 degree?
What changed into the strength of the electron while it moved to the n = four electricity degree?
What became the power of the photon emitted while the electron jumped from the n = 9 to the n
= 4 energy stage? - ANS-1) En= -thirteen.60 eV/n^2
E9=-thirteen.60 eV/ 9^2
-0.1679 eV --- *-zero.168eV*
2) n= -thirteen.60eV/n^2 E4= -13.60eV/four^2 Answer in four Sig Figs/eV
-thirteen.^2 = *-.Eighty five eV*
three) E9-E4 Answer in 4 Sig Figs/eV
ΔE= E9 - E4
ΔE= (-zero.1679) - (-zero.Eighty five) = 0.682
(0.682) x (1.6x10^-19) = *1.091x10^-19J*
At 1.30 x 10^14 Hz, the energy given off by a blackbody is 1.51 x 10^-17 J.
A. What is the power of this sort of photons of this frequency emitted?
B. How many photons of this frequency are emitted?
Show your paintings. - ANS-Use formula E=hf.
U= h x f
U= (6.62x10^-34) x (1.3x10^14)
*U= 8.606x10^-20 J*
Use method E=nhf revised as n=E/hf. Answer in photons
n= E/ h x f
n= (1.51x10^17 )/ (6.62x10^-34) x (1.3x10^14)
(6.62x10^-34) x (1.3x10^14) = 8.606x10^-20
(1.51x10^-17) / (eight.606x10^20) = *a hundred seventy five Photons*
In the Compton effect, mild is *scattered* off an electron.
True or False: As a end result of this scattering, the *mild's frequency* increases. - ANS-*False*
Light frequency: decreases
, Wavelength: will increase
- all of the scattered X-rays expanded in wavelength.
In the Compton impact, mild is scattered off an electron. What is mild performing like?
A) A particle
B) Electromagnetic wave
C) Both a wave and a particle
D) Neither a wave nor a particle - ANS-A) A particle
The discovery of the electron is credited to which test?
A) The Rutherford Gold Foil Experiment
B) J. J. Thompson's Cathode Ray Tube Experiment
C) The Compton Scattering Experiment
D) The Millikan Oil Drop Experiment - ANS-B) JJ Thompson's Cathode Ray Tube Experiment
The mild from a violet laser has a frequency of seven.20 x 1014 Hz.
What is the wavelength of this mild?
What is the momentum of this light? - ANS-1) Lambda=v/f c=three.00x10^8; f is given answer in
m
(3x10^8) / (7.20x10^14) = *4.17x10^-7m*
2) p= h/lambda in which h is 6.63x10^-34J and lambda is answer from preceding query answer
in kgm/s
P= hf/ c
P = (6.63x10^-34 JxS) x (7.20x10^14) / (3x10^8)
P = *1.59x10^-27 kgm/s*
There were five fashions of the atom defined on this model, put them in the best order. -
ANS-I.P.P.B.E.
*First:* Atom is indivisible
Atoms had been notion to be the smallest part of a substance that still retained the residences
of that substance. It additionally supposed that the atom had no substructure.
*Second:* Plum Pudding Theory or Chocolate Chip Cookie Dough Theory
(cake/ cookie = protons +)
(plum/ chips = electrons -) "stuck in area"
*Third:* Planetary Model
gold sheet
(middle nucleus = middle +)
(electrons around it = -)
(atoms typically open space)
