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Simple Harmonic Motion and Oscillation Complete Notes Physics 1010

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These notes cover oscillation and simple harmonic motion in a structured way. The content starts with definitions of periodic motion and SHM. It derives the core equation of motion, F equals minus kx and the differential form. It explains displacement in sine and cosine form. Velocity and acceleration relations are derived. Maximum velocity equals A omega and maximum acceleration equals A omega squared Energy analysis includes kinetic, potential, and total energy. Total energy remains constant and equals half k A squared The document explains superposition of two SHM in same and perpendicular directions. It derives amplitude and phase relations. Lissajous figures are discussed for phase difference cases. Damping is covered with real system behavior. The damped equation includes velocity dependent force. Three cases are explained. Underdamped shows oscillation with decreasing amplitude. Critically damped returns fastest without oscillation. Overdamped returns slowly without oscillation Decay time, logarithmic decrement, and quality factor are derived. Quality factor equals omega divided by two gamma. Forced oscillation is explained with external driving force. Resonance condition gives maximum amplitude. Phase relation and frequency response are derived. Bandwidth equals two gamma.

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Institution
Physics 1010
Course
Physics 1010

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Oscillation
Physics




1 Basics
Definitions : Periodic motion refers to any motion that repeats itself at regular intervals of time.
Oscillation is a specific type of periodic motion that involves an object moving back and forth about a
central point. And SHM(Simple Harmonic Motion) is special type of oscillatory motion which moves
under a restoring force. Mathematically
∴ F ∝ −x
F = −kx
ma + kx = 0
d2 x
m + kx = 0
dt2
d2 x k
+ x=0
dt2 m
k
Now if we take ω 2 = m
d2 x
+ ω2 x = 0
dt2
This is known as the differential equation of SHM. To solve it we put x = Aeαt
∴ Aα2 eαt + Aω 2
α2 + ω 2 = 0
α = ±iω
Now the general solution is
∴ x = A1 eiωt + A2 e−iωt
x = A1 (cos ωt + i sin ωt) + A2 (cos ωt − i sin ωt)
x = (A1 + A2 ) cos ωt + (A1 − A2 )i sin ωt
x = A cos ωt + B sin ωt
From here we can get the phase amplitude form
x = A sin(ωt + ϕ) or x = A cos(ωt + δ)

1.1 Kinematics and Dynamics :
1.1.1 Velocity and Acceleration:
For velocity we differentiate the displacement equation
dx
∴ = Aω cos(ωt + ϕ)
dt
v = Aω cos(ωt + ϕ) (1)
Now for acceleration we differentiate equation (1)
dv
∴ = −Aω 2 sin(ωt + ϕ)
dt

1

, a = −Aω 2 sin(ωt + ϕ)

Now
vmax = Aω and amax = Aω 2
Hence
amax
ω=
vmax

1.1.2 Energy :
Kinetic energy for SHM
1 1 1 k 1
KE = mv 2 = mA2 ω 2 cos2 (ωt + ϕ) = mA2 cos2 (ωt + ϕ) = kA2 cos2 (ωt + ϕ)
2 2 2 m 2
Potential energy of SHM
1 2 1
PE = kx = kA2 sin2 (ωt + ϕ)
2 2
Total energy

∴ T E = P E + KE
1 1
= kA2 sin2 (ωt + ϕ) + kA2 cos2 (ωt + ϕ)
2 2
1 2 2
= kA sin (ωt + ϕ) + cos2 (ωt + ϕ)

2
1
= kA2
2
To simplify further
1
TE = mω 2 A2
2
1
= m × (2πf )2 A2
2
= 2mπ 2 f 2 A2

Thus
1
E ∝ A2 and E ∝ f 2 and E ∝
T2
Obtaining equations of motion from Total Energy Equation
1 2 1
∴ TE = kx + mv 2
2 2 
d d 1 2 1 2
(T E) = kx + mv
dt dt 2 2
1 dx 1 dv
0 = k × 2x × + m × 2v ×
2 dt 2 dt
d2 x
kxv + mv 2 = 0
dt
d2 x k
vm( 2 + x) = 0
dt m
d2 x
+ ω2 x = 0
dt2

1.2 Superposition :
It is the phenomenon where a single particle is subjected to two or more harmonic oscillation simul-
taneously. Instead of choosing one path the particle follows a resultant path. Though it has some
limitation
1. Only applicable for small oscillation.
2. 2 SHM must have same nature.


2

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Institution
Physics 1010
Course
Physics 1010

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Uploaded on
April 30, 2026
Number of pages
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Written in
2025/2026
Type
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