, SOLUTION MANUAL FOR Steel Design 7th Edition Segui
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, STEEL DESIGN [7TH EDITION]
William T. Segui and Sayed M. Soleimani
CHAPTER 1 – INTRODUCTION
1.5-1
(a) 𝐴 = 𝜋(0.550)2 /4 = 0.2376 in.2
𝑃𝑢 28,500
𝐹𝑢 = = = 120,000 psi = 120 ksi
𝐴 0.2376
Fu = 120 ksi (827.4 MPa)
2.300−2.030
(b) 𝑒 = × 100 = 13.3%
2.030
e = 13.3%
(c) 𝐴𝑓 = 𝜋(0.430)2 /4 = 0.1452 in.2
𝐴𝑓 −𝐴𝑜 0.1452−0.2376
Change = × 100 = × 100 = −38.9%
𝐴𝑜 0.2376
Reduction = 38.9%
1.5-2
𝐴 = 𝜋(0.5)2 /4 = 0.1963 in.2
𝑃 13.5
𝑓= = = 68.77 ksi
𝐴 0.1963
Δ𝐿 4.66 × 10−3
𝜀= = = 2.33 × 10−3
𝐿 2
𝑓 68.77
𝐸= = = 29,500 ksi
𝜀 2.33 × 10−3
E = 29,500 ksi (203.4 GPa)
[1-1]
© 2026 Cengage Learning®. All Rights Reserved. May not be scanned, copied, or duplicated,
or posted to a publicly accessible website, in whole or in part.
,1.5-3
𝐴 = 𝜋(0.510)2 /4 = 0.2043 in.2
𝑃 250
For 𝑃 = 250 lb, 𝑓 = 𝐴 = 0.2043 = 1224 psi
Spreadsheet results:
(a)
(b)
(c)
E = slope = 31,600 ksi (217.9 GPa)
[1-2]
© 2026 Cengage Learning®. All Rights Reserved. May not be scanned, copied, or duplicated,
or posted to a publicly accessible website, in whole or in part.
,1.5-4
𝐴 = 𝜋(0.5)2 /4 = 0.1963 in.2
𝑓 𝑃/𝐴 𝑃 𝐿
𝐸= = = ⋅ = 1,392(4/0.1963) = 28,400 ksi
𝜀 Δ𝐿/𝐿 Δ𝐿 𝐴
E = 28,400 ksi (195.8 GPa)
1.5-5
𝐴 = 𝜋(3/8)2 /4 = 0.1104 in.2
𝑃 550
For 𝑃 = 550 lb, 𝑓 = 𝐴 = 0.1104 = 4,982 psi
Δ𝐿 350 × 10−6
𝜀= = = 175 × 10−6
𝐿 2
Spreadsheet results:
(a)
[1-3]
© 2026 Cengage Learning®. All Rights Reserved. May not be scanned, copied, or duplicated,
or posted to a publicly accessible website, in whole or in part.
,(b)
15,000
(c) 𝐸 = slope = 500×10−6 = 30,000,000 psi = 30,000 ksi
E = 30,000 ksi (206.8 GPa)
(d)
Fy ≈ 44,000 psi ≈ 44 ksi (≈ 303 MPa)
[1-4]
© 2026 Cengage Learning®. All Rights Reserved. May not be scanned, copied, or duplicated,
or posted to a publicly accessible website, in whole or in part.
,1.5-6
Spreadsheet results:
(a)
[1-5]
© 2026 Cengage Learning®. All Rights Reserved. May not be scanned, copied, or duplicated,
or posted to a publicly accessible website, in whole or in part.
,(b)
80−50
(c) 𝐸 = slope = 0.0025−0.0015 = 30,000 ksi
E = 30,000 ksi (206.8 GPa)
(d)
Fpl ≈ 85 ksi (≈ 586 MPa)
Fy ≈ 116 ksi (≈ 800 MPa)
[1-6]
© 2026 Cengage Learning®. All Rights Reserved. May not be scanned, copied, or duplicated,
or posted to a publicly accessible website, in whole or in part.
, STEEL DESIGN [7TH EDITION]
William T. Segui and Sayed M. Soleimani
CHAPTER 2 – CONCEPTS IN STRUCTURAL STEEL DESIGN
2-1
D = 9 kips (49 kN), 𝐿𝑟 = 5 kips (22 kN), 𝑆 = 6 kips (27 kN), 𝑅 = 7 kips (31 kN), 𝑊 = 8 kips
(36 kN)
(a)
1: 1.4𝐷 = 1.4(9) = 12.6 kips (1.4(49) = 68.6 kN)
3: 1.2𝐷 + 1.6𝑅 + 0.5𝑊 = 1.2(9) + 1.6(7) + 0.5(8) = 26 kips (1.2(49) + 1.6(31) +
0.5(36) = 126.4 kN)
4: 1.2𝐷 + 1.0𝑊 + 0.5𝑅 = 1.2(9) + 1.0(8) + 0.5(7) = 22.3 kips (1.2(49) + 1.0(36) +
0.5(31) = 110.3 kN)
R u = 26 kips (126.4 kN) (combination 3)
(b)
ϕR n = 26 kips (126.4 kN)
𝜑𝑅𝑛 26 126.4
(c) 𝑅𝑛 = = 0.90 = 28.9 kips ( 0.90 = 140.4 kN)
𝜑
R n = 28.9 kips (140.4 kN)
(d)
3: 𝐷 + 𝑅 = 9 + 7 = 16 kips (49 + 31 = 80 kN)
6. 𝐷 + 0.75(0.6 𝑊) + 0.75(𝑅) = 9 + 0.75(0.6)(8) + 0.75(7) = 17.9 kips (49 +
0.75(0.6)(36) + 0.75(7) = 70.45 kN)
[2-1]
© 2026 Cengage Learning®. All Rights Reserved. May not be scanned, copied, or duplicated,
or posted to a publicly accessible website, in whole or in part.
, R a = 17.9 kips (70.45 kN) (combination 6)
(e) 𝑅𝑛 = Ω𝑅𝑎 = 1.67(17.9) = 29.9 kips (1.67(70.45) = 117.65 kN)
Rn = 29.9 kips (117.65 kN)
2-2
D = 9 kips (49 kN), 𝐿𝑟 = 5 kips (22 kN), 𝑆 = 6 kips (27 kN), 𝑊 = 8 kips (36 kN)
(a)
1: 1.4𝐷 = 1.4(9) = 12.6 kips (1.4(49) = 68.6 kN)
3: 1.2𝐷 + 1.6𝐿𝑟 + 0.5𝑊 = 1.2(9) + 1.6(5) + 0.5(8) = 22.8 kips (1.2(49) + 1.6(22) +
0.5(36) = 112 kN)
4: 1.2𝐷 + 1.0𝑊 + 0.5𝐿𝑟 = 1.2(9) + 1.0(8) + 0.5(5) = 21.3 kips (1.2(49) + 1.0(36) +
0.5(22) = 105.8 kN)
R u = 22.8 kips (112 kN) (combination 3)
(b)
ϕR n = 22.8 kips (112 kN)
𝜑𝑅𝑛 22.8 112
(c) 𝑅𝑛 = = 0.90 = 25.3 kips (0.90 = 124.4 kN)
𝜑
R n = 25.3 kips (124.4 kN)
(d)
3: 𝐷 + 𝐿𝑟 = 9 + 5 = 14 kips (49 + 22 = 71 kN)
[2-2]
© 2026 Cengage Learning®. All Rights Reserved. May not be scanned, copied, or duplicated,
or posted to a publicly accessible website, in whole or in part.
Important Notes
The file includes the complete test bank, organized chapter by chapter.
A sample of selected pages has been provided for preview.
All available appendices and Excel files (if included in the original resources) are
provided.
We continuously update our files to ensure you receive the latest and most accurate
editions.
New editions are added regularly – stay connected for updates!
✅ Why Buy From Us?
📚 Complete & organized chapter-by-chapter – no missing content, no guessing.
⚡ Instant digital delivery – get your file the moment you pay, no waiting.
📅 Always up to date – we track new editions so you always get the latest version.
💬 Friendly support – real humans ready to help, anytime you need us.
🔒 Safe & secure – thousands of satisfied students trust us every semester.
🛡️Our Guarantees
💰 Money-Back Guarantee: Not satisfied? We offer a full refund – no questions asked.
🔄 Wrong File? No Problem: Contact us and we will replace it immediately with the
correct version, free of charge.
⏰ 24/7 Support: We are always here – reach out anytime and expect a fast response.
Contact Email:
, STEEL DESIGN [7TH EDITION]
William T. Segui and Sayed M. Soleimani
CHAPTER 1 – INTRODUCTION
1.5-1
(a) 𝐴 = 𝜋(0.550)2 /4 = 0.2376 in.2
𝑃𝑢 28,500
𝐹𝑢 = = = 120,000 psi = 120 ksi
𝐴 0.2376
Fu = 120 ksi (827.4 MPa)
2.300−2.030
(b) 𝑒 = × 100 = 13.3%
2.030
e = 13.3%
(c) 𝐴𝑓 = 𝜋(0.430)2 /4 = 0.1452 in.2
𝐴𝑓 −𝐴𝑜 0.1452−0.2376
Change = × 100 = × 100 = −38.9%
𝐴𝑜 0.2376
Reduction = 38.9%
1.5-2
𝐴 = 𝜋(0.5)2 /4 = 0.1963 in.2
𝑃 13.5
𝑓= = = 68.77 ksi
𝐴 0.1963
Δ𝐿 4.66 × 10−3
𝜀= = = 2.33 × 10−3
𝐿 2
𝑓 68.77
𝐸= = = 29,500 ksi
𝜀 2.33 × 10−3
E = 29,500 ksi (203.4 GPa)
[1-1]
© 2026 Cengage Learning®. All Rights Reserved. May not be scanned, copied, or duplicated,
or posted to a publicly accessible website, in whole or in part.
,1.5-3
𝐴 = 𝜋(0.510)2 /4 = 0.2043 in.2
𝑃 250
For 𝑃 = 250 lb, 𝑓 = 𝐴 = 0.2043 = 1224 psi
Spreadsheet results:
(a)
(b)
(c)
E = slope = 31,600 ksi (217.9 GPa)
[1-2]
© 2026 Cengage Learning®. All Rights Reserved. May not be scanned, copied, or duplicated,
or posted to a publicly accessible website, in whole or in part.
,1.5-4
𝐴 = 𝜋(0.5)2 /4 = 0.1963 in.2
𝑓 𝑃/𝐴 𝑃 𝐿
𝐸= = = ⋅ = 1,392(4/0.1963) = 28,400 ksi
𝜀 Δ𝐿/𝐿 Δ𝐿 𝐴
E = 28,400 ksi (195.8 GPa)
1.5-5
𝐴 = 𝜋(3/8)2 /4 = 0.1104 in.2
𝑃 550
For 𝑃 = 550 lb, 𝑓 = 𝐴 = 0.1104 = 4,982 psi
Δ𝐿 350 × 10−6
𝜀= = = 175 × 10−6
𝐿 2
Spreadsheet results:
(a)
[1-3]
© 2026 Cengage Learning®. All Rights Reserved. May not be scanned, copied, or duplicated,
or posted to a publicly accessible website, in whole or in part.
,(b)
15,000
(c) 𝐸 = slope = 500×10−6 = 30,000,000 psi = 30,000 ksi
E = 30,000 ksi (206.8 GPa)
(d)
Fy ≈ 44,000 psi ≈ 44 ksi (≈ 303 MPa)
[1-4]
© 2026 Cengage Learning®. All Rights Reserved. May not be scanned, copied, or duplicated,
or posted to a publicly accessible website, in whole or in part.
,1.5-6
Spreadsheet results:
(a)
[1-5]
© 2026 Cengage Learning®. All Rights Reserved. May not be scanned, copied, or duplicated,
or posted to a publicly accessible website, in whole or in part.
,(b)
80−50
(c) 𝐸 = slope = 0.0025−0.0015 = 30,000 ksi
E = 30,000 ksi (206.8 GPa)
(d)
Fpl ≈ 85 ksi (≈ 586 MPa)
Fy ≈ 116 ksi (≈ 800 MPa)
[1-6]
© 2026 Cengage Learning®. All Rights Reserved. May not be scanned, copied, or duplicated,
or posted to a publicly accessible website, in whole or in part.
, STEEL DESIGN [7TH EDITION]
William T. Segui and Sayed M. Soleimani
CHAPTER 2 – CONCEPTS IN STRUCTURAL STEEL DESIGN
2-1
D = 9 kips (49 kN), 𝐿𝑟 = 5 kips (22 kN), 𝑆 = 6 kips (27 kN), 𝑅 = 7 kips (31 kN), 𝑊 = 8 kips
(36 kN)
(a)
1: 1.4𝐷 = 1.4(9) = 12.6 kips (1.4(49) = 68.6 kN)
3: 1.2𝐷 + 1.6𝑅 + 0.5𝑊 = 1.2(9) + 1.6(7) + 0.5(8) = 26 kips (1.2(49) + 1.6(31) +
0.5(36) = 126.4 kN)
4: 1.2𝐷 + 1.0𝑊 + 0.5𝑅 = 1.2(9) + 1.0(8) + 0.5(7) = 22.3 kips (1.2(49) + 1.0(36) +
0.5(31) = 110.3 kN)
R u = 26 kips (126.4 kN) (combination 3)
(b)
ϕR n = 26 kips (126.4 kN)
𝜑𝑅𝑛 26 126.4
(c) 𝑅𝑛 = = 0.90 = 28.9 kips ( 0.90 = 140.4 kN)
𝜑
R n = 28.9 kips (140.4 kN)
(d)
3: 𝐷 + 𝑅 = 9 + 7 = 16 kips (49 + 31 = 80 kN)
6. 𝐷 + 0.75(0.6 𝑊) + 0.75(𝑅) = 9 + 0.75(0.6)(8) + 0.75(7) = 17.9 kips (49 +
0.75(0.6)(36) + 0.75(7) = 70.45 kN)
[2-1]
© 2026 Cengage Learning®. All Rights Reserved. May not be scanned, copied, or duplicated,
or posted to a publicly accessible website, in whole or in part.
, R a = 17.9 kips (70.45 kN) (combination 6)
(e) 𝑅𝑛 = Ω𝑅𝑎 = 1.67(17.9) = 29.9 kips (1.67(70.45) = 117.65 kN)
Rn = 29.9 kips (117.65 kN)
2-2
D = 9 kips (49 kN), 𝐿𝑟 = 5 kips (22 kN), 𝑆 = 6 kips (27 kN), 𝑊 = 8 kips (36 kN)
(a)
1: 1.4𝐷 = 1.4(9) = 12.6 kips (1.4(49) = 68.6 kN)
3: 1.2𝐷 + 1.6𝐿𝑟 + 0.5𝑊 = 1.2(9) + 1.6(5) + 0.5(8) = 22.8 kips (1.2(49) + 1.6(22) +
0.5(36) = 112 kN)
4: 1.2𝐷 + 1.0𝑊 + 0.5𝐿𝑟 = 1.2(9) + 1.0(8) + 0.5(5) = 21.3 kips (1.2(49) + 1.0(36) +
0.5(22) = 105.8 kN)
R u = 22.8 kips (112 kN) (combination 3)
(b)
ϕR n = 22.8 kips (112 kN)
𝜑𝑅𝑛 22.8 112
(c) 𝑅𝑛 = = 0.90 = 25.3 kips (0.90 = 124.4 kN)
𝜑
R n = 25.3 kips (124.4 kN)
(d)
3: 𝐷 + 𝐿𝑟 = 9 + 5 = 14 kips (49 + 22 = 71 kN)
[2-2]
© 2026 Cengage Learning®. All Rights Reserved. May not be scanned, copied, or duplicated,
or posted to a publicly accessible website, in whole or in part.
