NSG 527 FINAL EXAM LATEST 2026/2027 | Already Graded
A Questions & Verified Answers | Pass Guaranteed - A+
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Section 1: Cellular & Genetic Foundations (Questions 1-15)
1. A 45-year-old patient with chronic alcoholism presents with hepatomegaly and
elevated liver enzymes. Liver biopsy reveals enlarged hepatocytes with increased
cytoplasmic volume. Which cellular adaptation is MOST likely present?
A. Hyperplasia
B. Hypertrophy
C. Atrophy
D. Metaplasia
Correct Answer: B. Hypertrophy [CORRECT]
Rationale: Alcohol-induced hepatomegaly results from cellular enlargement
(hypertrophy) as hepatocytes increase in size to metabolize toxins and handle increased
metabolic demand. Hyperplasia (A) involves increased cell number, not size. Atrophy
(C) is decrease in cell size. Metaplasia (D) is change in cell type. This demonstrates
understanding of adaptive cellular responses to stress per NSG 527 pathophysiology
foundations and Wilkes University emphasis on alcohol-related organ damage
mechanisms.
2. A patient with emphysema has destruction of alveolar walls with loss of elastic
recoil. Which type of cellular death is PRIMARILY responsible for the tissue
destruction?
A. Apoptosis
B. Necrosis
C. Autophagy
D. Pyroptosis
Correct Answer: B. Necrosis [CORRECT]
,Rationale: Emphysema involves enzymatic destruction of alveolar walls by neutrophil
elastase and macrophage metalloproteinases, resulting in necrotic cell death with
inflammation and tissue damage. Apoptosis (A) is programmed cell death without
inflammation. Autophagy (C) is cellular self-digestion for recycling. Pyroptosis (D) is
inflammatory programmed death mediated by caspase-1. The unregulated,
inflammatory nature of alveolar destruction aligns with necrosis per NSG 527
respiratory pathophysiology.
3. In the intrinsic pathway of apoptosis, which mitochondrial protein is released
into the cytosol to initiate caspase activation?
A. Cytochrome c
B. Bcl-2
C. Caspase-8
D. Fas ligand
Correct Answer: A. Cytochrome c [CORRECT]
Rationale: Cytochrome c is released from damaged mitochondria during intrinsic
apoptosis, binding Apaf-1 to form the apoptosome and activate caspase-9. Bcl-2 (B) is
anti-apoptotic and prevents cytochrome c release. Caspase-8 (C) initiates extrinsic
apoptosis via death receptors. Fas ligand (D) is an extrinsic pathway activator. This
molecular mechanism is fundamental to NSG 527 cellular biology and understanding
therapeutic targets for cancer and neurodegenerative diseases.
4. A patient with Li-Fraumeni syndrome develops multiple primary cancers at a
young age. Which tumor suppressor gene is defective in this condition?
A. RB1
B. TP53
C. BRCA1
D. APC
Correct Answer: B. TP53 [CORRECT]
,Rationale: Li-Fraumeni syndrome results from germline mutations in TP53, encoding
p53, the "guardian of the genome." p53 regulates cell cycle arrest, DNA repair, and
apoptosis in response to cellular stress. RB1 (A) causes retinoblastoma. BRCA1 (C)
increases breast/ovarian cancer risk. APC (D) causes familial adenomatous polyposis.
This demonstrates genetic basis of cancer predisposition syndromes per NSG 527
genetics competencies and Wilkes University doctoral-level pathophysiology.
5. Which histone modification is associated with gene activation and increased
transcription?
A. DNA methylation at CpG islands
B. Histone deacetylation
C. Histone acetylation
D. Histone methylation at H3K9
Correct Answer: C. Histone acetylation [CORRECT]
Rationale: Histone acetylation neutralizes positive charges on lysine residues, reducing
histone-DNA interaction and allowing transcription factor access, thereby activating
gene expression. DNA methylation (A) and histone deacetylation (B) generally repress
transcription. H3K9 methylation (D) is associated with gene silencing. This epigenetic
mechanism is critical for understanding gene regulation, cancer development, and
therapeutic targets (HDAC inhibitors) per NSG 527 advanced pathophysiology.
6. A patient with cystic fibrosis has a mutation in the CFTR gene. Which type of
mutation is MOST commonly responsible for this disease?
A. Missense mutation
B. Nonsense mutation
C. Frameshift mutation
D. Splice site mutation
Correct Answer: A. Missense mutation [CORRECT]
, Rationale: The most common CFTR mutation, ΔF508, is a deletion of phenylalanine at
position 508—a missense mutation (specifically, an in-frame deletion of 3 nucleotides)
that causes protein misfolding and degradation. While other mutation types occur,
ΔF508 accounts for ~70% of CF cases. This demonstrates understanding of genotype-
phenotype relationships and molecular basis of autosomal recessive disorders per NSG
527 genetics competencies.
7. During DNA replication, which enzyme synthesizes the leading strand
continuously in the 5' to 3' direction?
A. DNA ligase
B. DNA polymerase III
C. DNA helicase
D. Primase
Correct Answer: B. DNA polymerase III [CORRECT]
Rationale: DNA polymerase III is the primary replicative polymerase that synthesizes
DNA continuously (leading strand) and discontinuously (lagging strand, Okazaki
fragments) in the 5'→3' direction. DNA ligase (A) joins Okazaki fragments. DNA helicase
(C) unwinds the double helix. Primase (D) synthesizes RNA primers. This central dogma
knowledge is foundational for NSG 527 genetic pathophysiology and understanding
replication errors leading to mutations.
8. A patient with Huntington's disease demonstrates earlier onset and more
severe symptoms than their affected parent. Which genetic phenomenon explains
this pattern?
A. Incomplete penetrance
B. Variable expressivity
C. Anticipation
D. Genomic imprinting
Correct Answer: C. Anticipation [CORRECT]
A Questions & Verified Answers | Pass Guaranteed - A+
Graded
Section 1: Cellular & Genetic Foundations (Questions 1-15)
1. A 45-year-old patient with chronic alcoholism presents with hepatomegaly and
elevated liver enzymes. Liver biopsy reveals enlarged hepatocytes with increased
cytoplasmic volume. Which cellular adaptation is MOST likely present?
A. Hyperplasia
B. Hypertrophy
C. Atrophy
D. Metaplasia
Correct Answer: B. Hypertrophy [CORRECT]
Rationale: Alcohol-induced hepatomegaly results from cellular enlargement
(hypertrophy) as hepatocytes increase in size to metabolize toxins and handle increased
metabolic demand. Hyperplasia (A) involves increased cell number, not size. Atrophy
(C) is decrease in cell size. Metaplasia (D) is change in cell type. This demonstrates
understanding of adaptive cellular responses to stress per NSG 527 pathophysiology
foundations and Wilkes University emphasis on alcohol-related organ damage
mechanisms.
2. A patient with emphysema has destruction of alveolar walls with loss of elastic
recoil. Which type of cellular death is PRIMARILY responsible for the tissue
destruction?
A. Apoptosis
B. Necrosis
C. Autophagy
D. Pyroptosis
Correct Answer: B. Necrosis [CORRECT]
,Rationale: Emphysema involves enzymatic destruction of alveolar walls by neutrophil
elastase and macrophage metalloproteinases, resulting in necrotic cell death with
inflammation and tissue damage. Apoptosis (A) is programmed cell death without
inflammation. Autophagy (C) is cellular self-digestion for recycling. Pyroptosis (D) is
inflammatory programmed death mediated by caspase-1. The unregulated,
inflammatory nature of alveolar destruction aligns with necrosis per NSG 527
respiratory pathophysiology.
3. In the intrinsic pathway of apoptosis, which mitochondrial protein is released
into the cytosol to initiate caspase activation?
A. Cytochrome c
B. Bcl-2
C. Caspase-8
D. Fas ligand
Correct Answer: A. Cytochrome c [CORRECT]
Rationale: Cytochrome c is released from damaged mitochondria during intrinsic
apoptosis, binding Apaf-1 to form the apoptosome and activate caspase-9. Bcl-2 (B) is
anti-apoptotic and prevents cytochrome c release. Caspase-8 (C) initiates extrinsic
apoptosis via death receptors. Fas ligand (D) is an extrinsic pathway activator. This
molecular mechanism is fundamental to NSG 527 cellular biology and understanding
therapeutic targets for cancer and neurodegenerative diseases.
4. A patient with Li-Fraumeni syndrome develops multiple primary cancers at a
young age. Which tumor suppressor gene is defective in this condition?
A. RB1
B. TP53
C. BRCA1
D. APC
Correct Answer: B. TP53 [CORRECT]
,Rationale: Li-Fraumeni syndrome results from germline mutations in TP53, encoding
p53, the "guardian of the genome." p53 regulates cell cycle arrest, DNA repair, and
apoptosis in response to cellular stress. RB1 (A) causes retinoblastoma. BRCA1 (C)
increases breast/ovarian cancer risk. APC (D) causes familial adenomatous polyposis.
This demonstrates genetic basis of cancer predisposition syndromes per NSG 527
genetics competencies and Wilkes University doctoral-level pathophysiology.
5. Which histone modification is associated with gene activation and increased
transcription?
A. DNA methylation at CpG islands
B. Histone deacetylation
C. Histone acetylation
D. Histone methylation at H3K9
Correct Answer: C. Histone acetylation [CORRECT]
Rationale: Histone acetylation neutralizes positive charges on lysine residues, reducing
histone-DNA interaction and allowing transcription factor access, thereby activating
gene expression. DNA methylation (A) and histone deacetylation (B) generally repress
transcription. H3K9 methylation (D) is associated with gene silencing. This epigenetic
mechanism is critical for understanding gene regulation, cancer development, and
therapeutic targets (HDAC inhibitors) per NSG 527 advanced pathophysiology.
6. A patient with cystic fibrosis has a mutation in the CFTR gene. Which type of
mutation is MOST commonly responsible for this disease?
A. Missense mutation
B. Nonsense mutation
C. Frameshift mutation
D. Splice site mutation
Correct Answer: A. Missense mutation [CORRECT]
, Rationale: The most common CFTR mutation, ΔF508, is a deletion of phenylalanine at
position 508—a missense mutation (specifically, an in-frame deletion of 3 nucleotides)
that causes protein misfolding and degradation. While other mutation types occur,
ΔF508 accounts for ~70% of CF cases. This demonstrates understanding of genotype-
phenotype relationships and molecular basis of autosomal recessive disorders per NSG
527 genetics competencies.
7. During DNA replication, which enzyme synthesizes the leading strand
continuously in the 5' to 3' direction?
A. DNA ligase
B. DNA polymerase III
C. DNA helicase
D. Primase
Correct Answer: B. DNA polymerase III [CORRECT]
Rationale: DNA polymerase III is the primary replicative polymerase that synthesizes
DNA continuously (leading strand) and discontinuously (lagging strand, Okazaki
fragments) in the 5'→3' direction. DNA ligase (A) joins Okazaki fragments. DNA helicase
(C) unwinds the double helix. Primase (D) synthesizes RNA primers. This central dogma
knowledge is foundational for NSG 527 genetic pathophysiology and understanding
replication errors leading to mutations.
8. A patient with Huntington's disease demonstrates earlier onset and more
severe symptoms than their affected parent. Which genetic phenomenon explains
this pattern?
A. Incomplete penetrance
B. Variable expressivity
C. Anticipation
D. Genomic imprinting
Correct Answer: C. Anticipation [CORRECT]
