Solution Manual for College Physics 11th Edition by Serway | ISBN 1305952308

Solution Manual for College Physics 11th Edition
by Serway | ISBN 1305952308



QUICK QUIZZES


2.1 (a) g ; 200 yd g; (b) 0 (c) 0


(a) False. g;The g;car g;may g;be g;slowing g;down, g;so g;that g;the g;direction

of its acceleration is opposite the direction of its
g; g; g; g; g; g; g; g; g;



g; velocity.

(b) True. g;If g;the g;velocity g;is g;in g;the g;direction g;chosen g;as g;negative, g;a

positive acceleration causes a decrease in speed.
g; g; g; g; g; g; g;




(c) True. g;For g;an g;accelerating g;particle g;to g;stop g;at g;all, g;the g;velocity

g; and acceleration must have opposite signs, so that the speed is
g; g; g; g; g; g; g; g; g; g;



decreasing. If this is the case, the particle will eventually
g; g; g; g; g; g; g; g; g; g;



g; come to rest. If the acceleration remains constant, however,
g; g; g; g; g; g; g; g;



g; the particle must begin to move again, opposite to the
g; g; g; g; g; g; g; g; g;



g; direction of its original velocity. If the particle comes to rest
g; g; g; g; g; g; g; g; g; g;



g; and then stays at rest, the acceleration has become zero at the
g; g; g; g; g; g; g; g; g; g; g;



g; moment the motion stops. This is the case for a braking car—
g; g; g; g; g; g; g; g; g; g; g;



the acceleration is negative and goes to zero as the car
g; g; g; g; g; g; g; g; g; g;

,comes to rest.
g; g;

,The velocity-vs-time graph (a) has a constant slope, indicating a constant
g; g; g; g; g; g; g; g; g; g;



g; acceleration, which is represented by the acceleration-vs.-time graph
g; g; g; g; g; g; g;



(e).
g;




Graph (b) represents an object whose speed always increases, and
g; g; g; g; g; g; g; g; g;



does so at an ever-increasing rate. Thus, the acceleration must be
g; g; g; g; g; g; g; g; g; g; g;



g; increasing, and the acceleration-vs-time graph that best indicates
g; g; g; g; g; g; g;



g; this behaviour is (d).
g; g; g;




Graph (c) depicts an object which first has a velocity that
g; g; g; g; g; g; g; g; g; g;



g; increases at a constant rate, which means that the object’s
g; g; g; g; g; g; g; g; g;



acceleration is constant. The motion then changes to one at
g; g; g; g; g; g; g; g; g; g;



g; constant speed, indicating that the acceleration of the object
g; g; g; g; g; g; g; g;



g; becomes zero. Thus, the best match to this situation is graph (f).
g; g; g; g; g; g; g; g; g; g; g;




Choice (b). According to graph b, there are some instants in time when
g; g; g; g; g; g; g; g; g; g; g; g;



g; the object is simultaneously at two different x-coordinates. This is
g; g; g; g; g; g; g; g; g;



physically impossible.
g; g;




(a) The g;blue g;graph g;of g;Figure g;2.14b g;best g;shows g;the g;puck’s g;position

as a function of time. As seen in Figure 2.14a, the distance
g; g; g; g; g; g; g; g; g; g; g; g;



the puck has traveled grows at an increasing rate for
g; g; g; g; g; g; g; g; g; g;



approximately three time intervals, grows at a steady rate
g; g; g; g; g; g; g; g; g;



g; for about four time intervals, and then grows at a
g; g; g; g; g; g; g; g; g;



diminishing rate for the last two intervals.
g; g; g; g; g; g; g;




(b) The g;red g;graph g;of g;Figure g;2.14c g;best g;illustrates g;the g;speed g;(distance

, traveled per time interval) of the puck as a function of time. It
g; g; g; g; g; g; g; g; g; g; g; g;



shows the puck gaining speed for approximately three time
g; g; g; g; g; g; g; g; g;



g; intervals, moving at constant speed for about four time
g; g; g; g; g; g; g; g;



intervals, then slowing to rest during the last two intervals.
g; g; g; g; g; g; g; g; g; g;




(c) The g;green g;graph g;of g;Figure g;2.14d g;best g;shows g;the g;puck’s

acceleration as a function of time. The puck gains velocity
g; g; g; g; g; g; g; g; g; g;



(positive acceleration) for approximately three time intervals,
g; g; g; g; g; g; g;



g; moves at constant velocity (zero acceleration) for about four
g; g; g; g; g; g; g; g;



g; time intervals, and then loses velocity (negative acceleration)
g; g; g; g; g; g; g;



g; for roughly the last two time intervals.
g; g; g; g; g; g;




Choice (e). The acceleration of the ball remains constant while it is in
g; g; g; g; g; g; g; g; g; g; g; g;



g; the air. The magnitude of its acceleration is the free-fall
g; g; g; g; g; g; g; g; g;




acceleration, g
g; g; g; 9.80 m/s2.
g; g;




Choice (c). As it travels upward, its speed decreases by 9.80 m/s
g; g; g; g; g; g; g; g; g; g; g;



during each second of its motion. When it reaches the peak of
g; g; g; g; g; g; g; g; g; g; g; g;



g; its motion, its speed becomes zero. As the ball moves
g; g; g; g; g; g; g; g; g;



g; downward, its speed increases by g; g; g; g;



9.80 m/s each second.g; g; g;




Choices (a) and (f). The first jumper will always be moving with a
g; g; g; g; g; g; g; g; g; g; g; g;



g; higher velocity than the second. Thus, in a given time interval, the
g; g; g; g; g; g; g; g; g; g; g;



first jumper covers more distance than the second, and the
g; g; g; g; g; g; g; g; g; g;



g; separation distance g;