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DSC1630 Exam Revision May/June Past Papers & Answers 2026 |Introductory Financial Mathematics|

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This exam revision paper is more than just a set of questions and answers. It’s designed to help you understand how each answer is reached, so you’re not just memorising but actually learning the concepts behind them. The solutions are clear, accurate, and supported by reliable academic references. It also includes predicted questions that are likely to appear, giving you a practical sense of what to expect and how to approach them with confidence. Whether you’re revising last minute or using it to strengthen your understanding over time, it’s structured in a way that aligns with what examiners look for. The explanations are straightforward and focused, making it easier to follow and apply. If you take the time to work through it properly, achieving high grades is a realistic outcome.

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DSC1630: INTRODUCTORY FI-
NANCIAL MATHEMATICS
May/June Examination 2026 — Comprehensive Revision Guide

⋆ ⋄ ⋆ ⋄ ⋆ ⋄ ⋆ ⋄ ⋆

Decision Sciences — Financial Mathematics




Exam Revision Guide


DSC1630
Module Code:
Introductory Financial Mathematics
Module Name:
May/June Examination 2026
Paper / Exam:
May/June 2023 -May/June 2025
Papers Covered:
30 MCQ, 100 Marks, 2 hrs 30 min
Format:



Work through every question. Understand the method, not just the answer.




Exam Revision Notes | DSC1630 | 2026

,DSC1630 | Introductory Financial Mathematics May/June Exam Revision



Key Formulae for DSC1630


Key Concept
Simple Interest: S = P (1 + rt) I = P rt

Simple Discount: P = S(1 − dt) where d = discount rate
 mt
jm
Compound Interest: S = P 1 + m

Continuous Compounding: S = P ert
 m
Effective Rate: ieff = 1 + jm
m
−1 ieff (cont) = er − 1

Nominal from Effective: jm = m (1 + ieff )1/m − 1
 

(1 + i)n − 1
Future Value of Ordinary Annuity: F = R ·
i
1 − (1 + i)−n
Present Value of Ordinary Annuity: P = R ·
i
Annuity Due (multiply by (1 + i)): Fdue = Ford · (1 + i)
R
Perpetuity: P =
i
C/2 1 − (1 + z)−n 100
Bond All-In Price: P = · + where z = j2 /2, f =
(1 + z)f z (1 + z)n+f
d/days-in-half-year
n
X Ct
NPV: N P V = Accept if N P V > 0
(1 + r)t
t=0
IRR: Rate at which N P V = 0




Page 2 of 22

,DSC1630 | Introductory Financial Mathematics May/June Exam Revision



PAPER A — MAY/JUNE 2025 EXAMINATION

30 questions · 100 marks · Duration: 2 hours 30 minutes · Programmable calculator permitted




Question 1 (2025) Simple Interest



Question: The amount of money you have to invest at a simple interest rate of 15% per
annum to earn R5 250 interest after three years is:

[1] R3 620.69 [2] R10 000.00 [3] R5 249.48 [4] R122 500.00 [5] R11 666.67


Answer: Correct answer: [5] R11 666.67
I
Formula: I = P rt, so P =
rt

5 250 5 250
P = = = R11 666.67
0.15 × 3 0.45

• r = 15% = 0.15, t = 3 years, I = R5 250
• Rearrange I = P rt to get P = I/(rt)

Exam Tip
In simple interest problems, interest I = P rt is not compounded. Always check
whether the question gives you I (interest only) or S (accumulated amount = P +
I). Here I is given directly.




Question 2 (2025) Simple Discount



Question: A bank’s simple discount rate is 12% per annum. You need to pay the bank
R5 000 in six months’ time. The amount of money that you will receive from the bank
now is:

[1] R4 700.00 [2] R4 716.98 [3] R4 724.56 [4] R5 300.00 [5] R5 319.15


Answer: Correct answer: [1] R4 700.00
Formula: P = S(1 − dt)




Page 3 of 22

, DSC1630 | Introductory Financial Mathematics May/June Exam Revision





P = 5 000 1 − 0.12 × 0.5 = 5 000 × 0.94 = R4 700.00

• S = R5 000 (future value / face value), d = 0.12, t = 6/12 = 0.5 years
• Simple discount deducts interest upfront from the future value

Watch Out
Simple discount and simple interest are different. With simple interest P = S/(1 +
rt), giving R4 716.98 — that is option [2], which is a common trap. Use P = S(1−
dt) for discount.




Question 3 (2025) Finding Simple Interest Rate



Question: Jacob invests R8 350 in an account that pays simple interest. After six years,
the accumulated sum is R12 859. The simple interest rate per year, rounded to two deci-
mal places, is:

[1] 0.75% [2] 45.09% [3] 1.08% [4] 9.00% [5] none of the above


Answer: Correct answer: [4] 9.00%


S/P − 1 12 859/8 350 − 1 1.54 − 1 0.54
S = P (1 + rt) =⇒ r = = = = = 0.09
t 6 6 6

r = 9.00% per year.

• Always isolate r: r = (S − P )/(P × t)
• r = (12 859 − 8 350)/(8 350 × 6) = 4 509/50 100 = 0.09




Question 4 (2025) Compound Interest — Accumulated Amount



Question: The accumulated amount that Mabe will receive after 38 months if she de-
posits R13 300 into an account where money is worth 11.35% per year compounded every
two months is:

[1] R14 117.08 [2] R15 690.19 [3] R18 080.24 [4] R18 865.83 [5] R18 988.31




Page 4 of 22

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