CHEM 103 General Chemistry I Portage
Learning Modules 1-6 & Final Exam
ACTUAL EXAM 2026/2027 | Portage CHEM
103 Complete | Verified Q&A | Pass
Guaranteed - A+ Graded
Total Questions: 125 | Time Suggested for Full Set: 3 hours
MODULE 1 EXAM: Measurement, Significant Figures, Dimensional Analysis, Density,
Temperature Conversions (15 Questions)
Q1 (Module 1): How many significant figures are in the measurement 0.0040500 L?
A. 3
B. 4
C. 5
D. 6
Correct Answer: C [CORRECT]
Rationale: Leading zeros are never significant. The significant digits begin at the 4. The captive zero
between 4 and 5 is significant. The trailing zeros after the decimal (the last two zeros) are significant
because they are after a non-zero digit and after the decimal point. Therefore: 0.0040500 has significant
figures: 4, 0, 5, 0, 0 → 5 significant figures.
Q2 (Module 1): Convert 68.0 °F to degrees Celsius.
A. 15.0 °C
B. 20.0 °C
C. 24.0 °C
D. 154.4 °C
Correct Answer: B [CORRECT]
Rationale: Use the formula °C = (°F – 32) × 5/9. Substitute 68.0: (68.0 – 32) = 36.0. Then 36.0 × 5/9 =
36.0 × 0.5556 = 20.0 °C. The result to three significant figures is 20.0 °C.
,Q3 (Module 1): A liquid has a density of 0.785 g/mL. What is the mass of 45.0 mL of this liquid?
A. 0.0174 g
B. 35.3 g
C. 57.3 g
D. 45.8 g
Correct Answer: B [CORRECT]
Rationale: Density formula rearranged: mass = density × volume. Mass = (0.785 g/mL) × (45.0 mL) =
35.325 g. Rounded to three significant figures (limited by 45.0 mL having three and 0.785 having three)
is 35.3 g.
Q4 (Module 1): *CALCULATION+ Convert 2.45 × 10⁻? km to nanometers (nm).
A. 2.45 × 10⁻;; nm
B. 2.45 × 10⁻; nm
C. 2.45 × 10¹ nm
D. 2.45 × 10A nm
Correct Answer: D [CORRECT]
Rationale: Step 1: Convert km to m: 2.45 × 10⁻? km × (10= m/1 km) = 2.45 × 10⁻< m. Step 2: Convert m to
nm: 2.45 × 10⁻< m × (10C nm/1 m) = 2.45 × 10A nm. Alternatively: km → m → nm involves 10= × 10C =
10;<, so 2.45 × 10⁻? × 10;< = 2.45 × 10A nm.
Q5 (Module 1): [SELECT-ALL-THAT-APPLY] Which of the following are SI base units?
A. Meter (m)
B. Gram (g)
C. Kelvin (K)
D. Liter (L)
E. Mole (mol)
F. Second (s)
Correct Answers: A, C, E, F [CORRECT]
Rationale: The seven SI base units are: meter (m) for length, kilogram (kg) for mass, second (s) for time,
kelvin (K) for temperature, mole (mol) for amount of substance, ampere (A) for electric current, and
candela (cd) for luminous intensity. Gram (B) is a derived metric unit (10⁻= kg), not a base unit. Liter (D)
is a derived volume unit (10⁻= m=).
Q6 (Module 1): [ORDERED RESPONSE] Rank the following measurements from LEAST precise to MOST
precise:
, 1. 25 mL (graduated cylinder)
2. 25.0 mL (buret)
3. 25.00 mL (volumetric pipet)
4. 25 mL (beaker)
A. 4 → 1 → 2 → 3
B. 1 → 4 → 3 → 2
C. 3 → 2 → 1 → 4
D. 2 → 3 → 1 → 4
Correct Answer: A [CORRECT]
Rationale: Precision is indicated by the number of decimal places (significant figures) and the quality of
the measuring device. Beakers (4) have ±5-10% error and are least precise. Graduated cylinders (1) have
±1% error. Burets (2) deliver variable volumes with ±0.01 mL precision. Volumetric pipets (3) are
designed for a single volume with highest precision (±0.02 mL for Class A). The order from least to most
precise: beaker → graduated cylinder → buret → volumetric pipet.
Q7 (Module 1): [CALCULATION] A metal cube measures 2.50 cm on each side and has a mass of 42.2 g.
What is the density of the metal in g/cm³?
A. 2.70 g/cm³
B. 4.22 g/cm³
C. 6.75 g/cm³
D. 16.9 g/cm³
Correct Answer: A [CORRECT]
Rationale: Volume of cube = (2.50 cm)³ = 15.625 cm³. Density = mass/volume = 42.2 g / 15.625 cm³ =
2.7008 g/cm³. Rounded to three significant figures (limited by 2.50 and 42.2): 2.70 g/cm³. This density
identifies the metal as aluminum.
Q8 (Module 1): Convert 298 K to degrees Fahrenheit.
A. 25.0 °F
B. 77.0 °F
C. 571 °F
D. 537 °F
Correct Answer: B [CORRECT]
Rationale: Step 1: Convert K to °C: °C = K – 273 = 298 – 273 = 25 °C. Step 2: Convert °C to °F: °F = (°C ×
9/5) + 32 = (25 × 1.8) + 32 = 45 + 32 = 77 °F. To three significant figures: 77.0 °F.
Learning Modules 1-6 & Final Exam
ACTUAL EXAM 2026/2027 | Portage CHEM
103 Complete | Verified Q&A | Pass
Guaranteed - A+ Graded
Total Questions: 125 | Time Suggested for Full Set: 3 hours
MODULE 1 EXAM: Measurement, Significant Figures, Dimensional Analysis, Density,
Temperature Conversions (15 Questions)
Q1 (Module 1): How many significant figures are in the measurement 0.0040500 L?
A. 3
B. 4
C. 5
D. 6
Correct Answer: C [CORRECT]
Rationale: Leading zeros are never significant. The significant digits begin at the 4. The captive zero
between 4 and 5 is significant. The trailing zeros after the decimal (the last two zeros) are significant
because they are after a non-zero digit and after the decimal point. Therefore: 0.0040500 has significant
figures: 4, 0, 5, 0, 0 → 5 significant figures.
Q2 (Module 1): Convert 68.0 °F to degrees Celsius.
A. 15.0 °C
B. 20.0 °C
C. 24.0 °C
D. 154.4 °C
Correct Answer: B [CORRECT]
Rationale: Use the formula °C = (°F – 32) × 5/9. Substitute 68.0: (68.0 – 32) = 36.0. Then 36.0 × 5/9 =
36.0 × 0.5556 = 20.0 °C. The result to three significant figures is 20.0 °C.
,Q3 (Module 1): A liquid has a density of 0.785 g/mL. What is the mass of 45.0 mL of this liquid?
A. 0.0174 g
B. 35.3 g
C. 57.3 g
D. 45.8 g
Correct Answer: B [CORRECT]
Rationale: Density formula rearranged: mass = density × volume. Mass = (0.785 g/mL) × (45.0 mL) =
35.325 g. Rounded to three significant figures (limited by 45.0 mL having three and 0.785 having three)
is 35.3 g.
Q4 (Module 1): *CALCULATION+ Convert 2.45 × 10⁻? km to nanometers (nm).
A. 2.45 × 10⁻;; nm
B. 2.45 × 10⁻; nm
C. 2.45 × 10¹ nm
D. 2.45 × 10A nm
Correct Answer: D [CORRECT]
Rationale: Step 1: Convert km to m: 2.45 × 10⁻? km × (10= m/1 km) = 2.45 × 10⁻< m. Step 2: Convert m to
nm: 2.45 × 10⁻< m × (10C nm/1 m) = 2.45 × 10A nm. Alternatively: km → m → nm involves 10= × 10C =
10;<, so 2.45 × 10⁻? × 10;< = 2.45 × 10A nm.
Q5 (Module 1): [SELECT-ALL-THAT-APPLY] Which of the following are SI base units?
A. Meter (m)
B. Gram (g)
C. Kelvin (K)
D. Liter (L)
E. Mole (mol)
F. Second (s)
Correct Answers: A, C, E, F [CORRECT]
Rationale: The seven SI base units are: meter (m) for length, kilogram (kg) for mass, second (s) for time,
kelvin (K) for temperature, mole (mol) for amount of substance, ampere (A) for electric current, and
candela (cd) for luminous intensity. Gram (B) is a derived metric unit (10⁻= kg), not a base unit. Liter (D)
is a derived volume unit (10⁻= m=).
Q6 (Module 1): [ORDERED RESPONSE] Rank the following measurements from LEAST precise to MOST
precise:
, 1. 25 mL (graduated cylinder)
2. 25.0 mL (buret)
3. 25.00 mL (volumetric pipet)
4. 25 mL (beaker)
A. 4 → 1 → 2 → 3
B. 1 → 4 → 3 → 2
C. 3 → 2 → 1 → 4
D. 2 → 3 → 1 → 4
Correct Answer: A [CORRECT]
Rationale: Precision is indicated by the number of decimal places (significant figures) and the quality of
the measuring device. Beakers (4) have ±5-10% error and are least precise. Graduated cylinders (1) have
±1% error. Burets (2) deliver variable volumes with ±0.01 mL precision. Volumetric pipets (3) are
designed for a single volume with highest precision (±0.02 mL for Class A). The order from least to most
precise: beaker → graduated cylinder → buret → volumetric pipet.
Q7 (Module 1): [CALCULATION] A metal cube measures 2.50 cm on each side and has a mass of 42.2 g.
What is the density of the metal in g/cm³?
A. 2.70 g/cm³
B. 4.22 g/cm³
C. 6.75 g/cm³
D. 16.9 g/cm³
Correct Answer: A [CORRECT]
Rationale: Volume of cube = (2.50 cm)³ = 15.625 cm³. Density = mass/volume = 42.2 g / 15.625 cm³ =
2.7008 g/cm³. Rounded to three significant figures (limited by 2.50 and 42.2): 2.70 g/cm³. This density
identifies the metal as aluminum.
Q8 (Module 1): Convert 298 K to degrees Fahrenheit.
A. 25.0 °F
B. 77.0 °F
C. 571 °F
D. 537 °F
Correct Answer: B [CORRECT]
Rationale: Step 1: Convert K to °C: °C = K – 273 = 298 – 273 = 25 °C. Step 2: Convert °C to °F: °F = (°C ×
9/5) + 32 = (25 × 1.8) + 32 = 45 + 32 = 77 °F. To three significant figures: 77.0 °F.
