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APMA 3080 Final Exam Question and answers already passed 2025/2026

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APMA 3080 Final Exam Question and answers already passed 2025/2026 How to show a set of vectors are linearly independent? - correct answer (1) B = RREF([A | 0]) (2) Check if the only answer for B is x1, x2, x3... = 0 (3) If is, it is linearly independent. Otherwise, no. difference between span, subspace and basis - correct answer Subspace and span are linear combinations of vectors. They contain infinitely many vectors. THEY ARE THE SAME! A basis is a only set of vectors. How to show subset S is a subspace? - correct answer Check 3 conditions: (1) if 0 is a part of S. (2) if closed under addition: if (u in S) and (v in S), then (u + v in S). (3) if closed under multiplication: if (u in S), the

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APMA 3080 Final Exam Question and
answers already passed 2025/2026
How to show a set of vectors are linearly independent? - correct answer ✔(1) B = RREF([A | 0])

(2) Check if the only answer for B is x1, x2, x3... = 0

(3) If is, it is linearly independent. Otherwise, no.



difference between span, subspace and basis - correct answer ✔Subspace and span are linear
combinations of vectors. They contain infinitely many vectors. THEY ARE THE SAME!

A basis is a only set of vectors.



How to show subset S is a subspace? - correct answer ✔Check 3 conditions:

(1) if 0 is a part of S.

(2) if closed under addition: if (u in S) and (v in S), then (u + v in S).

(3) if closed under multiplication: if (u in S), then (cu in S).



Shortcuts:

- If S is a null space OR S is a span, it is automatically a subspace.



How to check if a set of vectors A form a basis of a subspace S? - correct answer ✔Check 2 conditions:

(1) A spans S. (That is, A can generate every vector in S.)

(2) A is linearly independent



How to find basis for a space? - correct answer ✔Method 1: Find basis for S = span(u1, u2, u3)

(1) Use the vectors {u1, u2, u3} to form rows of a matrix A

(2) B = REF(A)

, (3) The non-zero rows of B are the basis



Method 1: Find basis for S = span(u1, u2, u3)

(1) Use the vectors {u1, u2, u3} to form columns of a matrix A

(2) B = REF(A)

(3) pB = pivot columns of B

(4) Columns of A corresponding to pB form a basis for S.



How to find dimension of subspace - correct answer ✔(1) Find the number of free variables. Example:
dim([a b 0]) == 2

(2) OR, Count the number of vectors in the subspace's basis



Can a A subspace can have multiple bases? - correct answer ✔Yes



row space - correct answer ✔the set of all linear combinations of the row vectors



Column Space - correct answer ✔the set of all linear combinations of the columns of A



How to find basis for a span of vectors - correct answer ✔TODO



rank(A) - correct answer ✔length(pivot columns)



Rank-Nullity Theorem - correct answer ✔rank(A) + nullity(A) = number of columns



How to find Eigen-values? - correct answer ✔det(A - lambda*I) = 0

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