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CHEM 120 EXAM 3 INTRODUCTION TO GENERAL ORGANIC AND BIOLOGICAL CHEMISTRY NEW UPDATE COMPREHENSIVE TEST PAPER 2026 QUESTIONS WITH ANSWERS GRADED A+

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CHEM 120 EXAM 3 INTRODUCTION TO GENERAL ORGANIC AND BIOLOGICAL CHEMISTRY NEW UPDATE COMPREHENSIVE TEST PAPER 2026 QUESTIONS WITH ANSWERS GRADED A+

Institution
CHEM 120
Course
CHEM 120

Content preview

CHEM 120 EXAM 3 INTRODUCTION TO
GENERAL ORGANIC AND BIOLOGICAL
CHEMISTRY NEW UPDATE
COMPREHENSIVE TEST PAPER 2026
QUESTIONS WITH ANSWERS GRADED A+

⫸ Reduction Answer: Gaining of Electrons is Reduction (GER)


⫸ Fe2+ → Fe0 Answer: Fe is reduced as the charge is becoming more
negative (meaning that the Fe gained e-)


⫸ O2- → O0 Answer: O is being oxidized as the charge is becoming
more positive (loosing e-)


⫸ Cu+1 → Cu2+ Answer: Cu is being oxidized as the charge is
becoming more positive (loosing e-)


⫸ Oxidizing agent Answer: Contains the species being reduced.
Oxidizes another species in the reaction by accepting electrons
(becoming reduced in the process).


⫸ Reducing agent Answer: Contains the species being oxidized.
Reduces another species in the reaction by donating electrons (becoming
oxidized in the process).

, ⫸ Cu2+ in Cu2+ + Zn0 → Cu0 + Zn2+ Answer: Cu2+ is the oxidizing
agent as this species accepted electrons from the Zn0, and in the process,
became reduced.


⫸ Cu+ in V4+ + Cu+ → Cu+5 + V0 Answer: Cu+ is the reducing
agent, as this species donated electrons to the V4+, and in the process,
became oxidized.


⫸ Oxidation numbers in 2 H2 + O2 → 2 H2O Answer: 2 H20 + O20 →
2 H+12O2-


⫸ H2 in 2 H2 + O2 → 2 H2O Answer: H2 is the reducing agent as this
species reduced the O from 0 to -2.


⫸ O2 in V + O2 → VO2 Answer: O2 is the oxidizing agent because the
O2 accepted electrons from the V, causing the V to become oxidized.


⫸ Organic compound Answer: Based on and containing Carbon atoms.


⫸ GOLDEN RULE OF ORGANIC CHEMISTRY Answer: CARBON
MAKES 4 BONDS


⫸ Hydrocarbon Answer: Contains ONLY H and C atoms.


⫸ Alkanes Answer: Contain only single C-C bonds.

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CHEM 120

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