Page 1 of 208
HESI RADIOGRAPHY PRACTICE EXAM PREP
BANK | {LATEST 2026/ 2027 UPDATE}
COMPLETE ACTUAL AND AUTHENTIC EXAM |
BRAND NEW!
Which is the primary advantage of using the Camp Coventry method
instead of the Holmblad method when obtaining a tunnel view of the
knee?
A. Greater ease for the radiographer.
B. Increased patient comfort.
C. Less image distortion.
D. Decreased time.
B. Increased patient comfort.
The Camp Coventry method is considerably easier for the patient than
the Holmblad method (try kneeling on a sore knee). The Camp
Coventry method does not necessarily take less time to perform than
the Holmblad method. Some longitudinal distortion is acceptable with
the Camp Coventry method due to the central ray angle. In fact, lack
of distortion is the only advantage for using the Holmblad method.
The Camp Coventry method is not easier for the radiographer to
perform than the Holmblad method.
,Page 2 of 208
If a radiographer receives an exposure of 550 milliroentgens (mR) at a
distance of 1.5 feet from the tube of a portable x-ray unit, what will
the exposure be at a distance of 6 feet from the tube?
A. 34.4 mR
B. 20.6 mR
C. 88.0 mR
D. 137.5 mR
A. 34.4 mR
The inverse square law formula is used to solve this problem: I1 / I2 =
(D2 / D1) squared.
On an accurately positioned posteroanterior (PA) chest radiograph,
the manubrium of the sternum is seen at the level of which thoracic
vertabrae when the patient is sthenic?
A. 3rd
,Page 3 of 208
B. 2nd
C. 4th
D. 5th
C. 4th
The manubrium of the sternum is projected at the level of the fourth
thoracic vertebra on a properly positioned PA chest radiograph.
Which condition represents the most likely indication for an
anteroposterior (AP) chest projection with the patient in the left
lateral decubitus position?
A. Pneumothorax in left lung.
B. Effusion in left lung.
C. Pulmonary embolism in right lung.
D. Sarcoidosis in right lung.
A. Pneumothorax in left lung.
The lateral decubitus chest position demonstrates fluid in the pleural
cavity when the affected side is down, or small amounts of air when
the affected side is up. The left lateral decubitus position
, Page 4 of 208
demonstrates pleural effusions in the left lung, which appear as air-
fluid levels in the pleural space.
Which describes the correct positioning for a posteroanterior (PA)
chest projection? (Select the three that apply.)
A. The shoulders are depressed.
B. The clavicles are elevated.
C. The arms and shoulders are rotated posteriorly.
D. The shoulders are at equal distances from the image receptor (IR).
E. The chin is extended.
A. The shoulders are depressed.
D. The shoulders are at equal distances from the image receptor (IR).
E. The chin is extended.
An anteroposterior (AP) oblique mortise joint projection demonstrates
the distal fibula without talar superimposition and an open talofibular
joint. What should the radiographer do next?
A. Increase external rotation.
HESI RADIOGRAPHY PRACTICE EXAM PREP
BANK | {LATEST 2026/ 2027 UPDATE}
COMPLETE ACTUAL AND AUTHENTIC EXAM |
BRAND NEW!
Which is the primary advantage of using the Camp Coventry method
instead of the Holmblad method when obtaining a tunnel view of the
knee?
A. Greater ease for the radiographer.
B. Increased patient comfort.
C. Less image distortion.
D. Decreased time.
B. Increased patient comfort.
The Camp Coventry method is considerably easier for the patient than
the Holmblad method (try kneeling on a sore knee). The Camp
Coventry method does not necessarily take less time to perform than
the Holmblad method. Some longitudinal distortion is acceptable with
the Camp Coventry method due to the central ray angle. In fact, lack
of distortion is the only advantage for using the Holmblad method.
The Camp Coventry method is not easier for the radiographer to
perform than the Holmblad method.
,Page 2 of 208
If a radiographer receives an exposure of 550 milliroentgens (mR) at a
distance of 1.5 feet from the tube of a portable x-ray unit, what will
the exposure be at a distance of 6 feet from the tube?
A. 34.4 mR
B. 20.6 mR
C. 88.0 mR
D. 137.5 mR
A. 34.4 mR
The inverse square law formula is used to solve this problem: I1 / I2 =
(D2 / D1) squared.
On an accurately positioned posteroanterior (PA) chest radiograph,
the manubrium of the sternum is seen at the level of which thoracic
vertabrae when the patient is sthenic?
A. 3rd
,Page 3 of 208
B. 2nd
C. 4th
D. 5th
C. 4th
The manubrium of the sternum is projected at the level of the fourth
thoracic vertebra on a properly positioned PA chest radiograph.
Which condition represents the most likely indication for an
anteroposterior (AP) chest projection with the patient in the left
lateral decubitus position?
A. Pneumothorax in left lung.
B. Effusion in left lung.
C. Pulmonary embolism in right lung.
D. Sarcoidosis in right lung.
A. Pneumothorax in left lung.
The lateral decubitus chest position demonstrates fluid in the pleural
cavity when the affected side is down, or small amounts of air when
the affected side is up. The left lateral decubitus position
, Page 4 of 208
demonstrates pleural effusions in the left lung, which appear as air-
fluid levels in the pleural space.
Which describes the correct positioning for a posteroanterior (PA)
chest projection? (Select the three that apply.)
A. The shoulders are depressed.
B. The clavicles are elevated.
C. The arms and shoulders are rotated posteriorly.
D. The shoulders are at equal distances from the image receptor (IR).
E. The chin is extended.
A. The shoulders are depressed.
D. The shoulders are at equal distances from the image receptor (IR).
E. The chin is extended.
An anteroposterior (AP) oblique mortise joint projection demonstrates
the distal fibula without talar superimposition and an open talofibular
joint. What should the radiographer do next?
A. Increase external rotation.
