j j
SOLUTION MANUAL
j
,1A.1j Estimationj ofjdense-gasj viscosity.
a.j TablejE.1j givesjT,j=j126.2jK,jpj=j33.5jatm,j and
=j180xj10°j g/cm·sjfo
rjN.jThejreducedjconditionsjforjthejviscosityjestimationjarejthen:
P+j =P/Pej =j (1000j +j14.7)/33.5j xj 14.7j =j 2.06
T,j=T/T.j=(273.15j+j(68j-32)/1.8)/126.2j =j2.32
Atjthisjreducedjstate,jFig.j1.3-
1jgivesj,j=j1.15.j Hence,jthejpredictedjviscosityjisj=j,/,j=j1.15180x10°j=j2.071
0j g/cm·s.j ThisjresultjisjthenjconvertedjintojthejrequestedjunitsjbyjusejofjTablejF.3-4:
=2.07j10'j6.7197j xj 10j j =j 1.4j xj 10 1b,~/fts
I
I-l
,1A.2j Estimationjofjthejviscosityj ofjmethyljfluoride.
a.j CH%FjhasjMj =j 16.04--1.008+19.00j=j 34.03jg/g-mole,jT,j=j4.55+273.15j=
277.70j K,jpj=j 58.0j atm,j andj V,j=j 34.03/0.300j =j 113.4j cm/g-mole.j Thej critical
viscosityj isj thenj estimatedj as
,j=j61.6(34.03jxj277.70)/(113.4)j2/j255.6jmicropoise
fromj Eq.j 1.3-1a,j and
,j=j 7.70(34.03)/(58.0)/(277.7)j -/°263.5 micropoise
j j
fromj Eq.j 1.3-1b.
ThejreducedjconditionsjforjthejviscosityjestimatejarejT,j=j(370j4273.15)/277.70j=j2.3
2,jp,j=j120/58.0j=j2.07,jandjthejpredictedj,jfromjFig.j1.3-
1jisj1.1.j Thejresultingjpredictedjviscosityjis
=r=1.1j xj 255.6j xj 10°j =2.8j xj 10 g/cm·sjviajEq.1.3-1a,jor
1.1 263.5j xj 10°j =j 2.9j 10g/cm·sj viaj E.1.3-1b.
J-2
, lA.3j Computationj ofjthej viscositiesj ofjgasesj atj lowj density.
Equationj 1.4-
14,jwithjmolecularjparametersjfromjTablejE.1j andjcollisionjintegralsjfromjTablejE.2,jgives
jthejfollowingjresults:
Forj O: Mj =j 32.00,j oj =j 3.433A,j e/Kj =j 113j K.j Thenj atj 20°C,j Te
0
=
293.15/113j =j2.594j andj9,j =j1.086.j Equationj 1.4-14j thenj gives
=j 2.6693j xj 10-sjV32.00 293.15
(3.433) 1.086
=2.02j xj 10 g/cm·s
=2.02 10 Pas
=j2.02jxj10 mPas.
Thej reportedj valuej inj Tablej 1.1-3j isj 2.04j xj 10 mPa.s.
Forj N:j j Mj =j 28.01,j oj =j 3.667~,j e/K j =j 99.8j K.j Thenj atj 20°C,j T/ej =
293.15/99.8j=j2.937jandj9,j=j1.0447.j Equationj 1.4-14jthenjgives
= 2.6693
j 10-sj V28.01 293.15
(3.667 1.0447
=j 1.72xj 10 g/cm·s
= 1.72
j 10 Pas
=j 1.72 10 mPas.
Thej reportedj valuej inj Tablej 1.1-3j isj 1.75j xj 10 mPass.
0
Forj CH,,j Mj =j 16.04,j oj =j 3.780A,j e/Kj =j 154j K.j Thenj atj 20°C,j T/ej =
293.15/154j=j1.904j andj 9,j =j 1.197.j Equationj 1.4-14j thenj gives
= 2.6693
j 10-sj VI6.04j 293.15
(3.780)j xj 1.197
= 1.07j 10 g/cm·s
= 1.07 x 10
j j j Pa.s
=j 1.07j xj 10 mPass.
Thej reportedj valuej inj Tablej 1.1-3j isj 1.09j xj 10 mPass.
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