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Solutions Manual for Transport Phenomena, Revised 2nd Edition by Bird, Stewart & Lightfoot (All Chapters)

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This comprehensive Solutions Manual accompanies the classic textbook Transport Phenomena, Revised 2nd Edition, by R. Byron Bird, Warren E. Stewart, and Edwin N. Lightfoot. Prepared by the authors themselves, this manual provides complete, step-by-step solutions to all end-of-chapter problems, offering unparalleled insight into the fundamental principles of momentum, heat, and mass transfer. What's included: Complete solutions for all chapters (1 through 24, plus appendices) Detailed problem-solving approaches covering: Fluid Mechanics – Viscosity, laminar/turbulent flow, boundary layers, creeping flow, non-Newtonian fluids Heat Transfer – Conduction, convection, radiation, heat exchangers, transient heating/cooling Mass Transfer – Diffusion, convective mass transfer, absorption, distillation, membrane separation Advanced Topics – Rheology, turbulence, multicomponent diffusion, electrochemical transport Mathematical Methods – Dimensional analysis, vector/tensor calculus, differential equation solutions Why this manual helps you: Check your homework with confidence Master complex derivations (Navier-Stokes, energy equation, species continuity) Learn the correct methodology for solving transport phenomena problems Save hours of study time preparing for exams and qualifying tests Understand real-world applications in chemical engineering, mechanical engineering, and materials science Whether you're struggling with viscous flow in pipes, heat conduction in solids, or diffusion with chemical reaction, this manual gives you the clarity you need to succeed. Instant digital download – start studying immediately!

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Institution
Transport Phenomena,
Course
Transport Phenomena,

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All Chapters Covered
j j




SOLUTION MANUAL
j

,1A.1j Estimationj ofjdense-gasj viscosity.

a.j TablejE.1j givesjT,j=j126.2jK,jpj=j33.5jatm,j and
=j180xj10°j g/cm·sjfo
rjN.jThejreducedjconditionsjforjthejviscosityjestimationjarejthen:
P+j =P/Pej =j (1000j +j14.7)/33.5j xj 14.7j =j 2.06
T,j=T/T.j=(273.15j+j(68j-32)/1.8)/126.2j =j2.32
Atjthisjreducedjstate,jFig.j1.3-
1jgivesj,j=j1.15.j Hence,jthejpredictedjviscosityjisj=j,/,j=j1.15180x10°j=j2.071
0j g/cm·s.j ThisjresultjisjthenjconvertedjintojthejrequestedjunitsjbyjusejofjTablejF.3-4:

=2.07j10'j6.7197j xj 10j j =j 1.4j xj 10 1b,~/fts




I
I-l

,1A.2j Estimationjofjthejviscosityj ofjmethyljfluoride.

a.j CH%FjhasjMj =j 16.04--1.008+19.00j=j 34.03jg/g-mole,jT,j=j4.55+273.15j=
277.70j K,jpj=j 58.0j atm,j andj V,j=j 34.03/0.300j =j 113.4j cm/g-mole.j Thej critical
viscosityj isj thenj estimatedj as

,j=j61.6(34.03jxj277.70)/(113.4)j2/j255.6jmicropoise

fromj Eq.j 1.3-1a,j and

,j=j 7.70(34.03)/(58.0)/(277.7)j -/°263.5 micropoise
j j




fromj Eq.j 1.3-1b.
ThejreducedjconditionsjforjthejviscosityjestimatejarejT,j=j(370j4273.15)/277.70j=j2.3
2,jp,j=j120/58.0j=j2.07,jandjthejpredictedj,jfromjFig.j1.3-
1jisj1.1.j Thejresultingjpredictedjviscosityjis

=r=1.1j xj 255.6j xj 10°j =2.8j xj 10 g/cm·sjviajEq.1.3-1a,jor
1.1 263.5j xj 10°j =j 2.9j 10g/cm·sj viaj E.1.3-1b.




J-2

, lA.3j Computationj ofjthej viscositiesj ofjgasesj atj lowj density.

Equationj 1.4-
14,jwithjmolecularjparametersjfromjTablejE.1j andjcollisionjintegralsjfromjTablejE.2,jgives
jthejfollowingjresults:


Forj O: Mj =j 32.00,j oj =j 3.433A,j e/Kj =j 113j K.j Thenj atj 20°C,j Te
0

=


293.15/113j =j2.594j andj9,j =j1.086.j Equationj 1.4-14j thenj gives

=j 2.6693j xj 10-sjV32.00 293.15
(3.433) 1.086
=2.02j xj 10 g/cm·s
=2.02 10 Pas
=j2.02jxj10 mPas.

Thej reportedj valuej inj Tablej 1.1-3j isj 2.04j xj 10 mPa.s.

Forj N:j j Mj =j 28.01,j oj =j 3.667~,j e/K j =j 99.8j K.j Thenj atj 20°C,j T/ej =
293.15/99.8j=j2.937jandj9,j=j1.0447.j Equationj 1.4-14jthenjgives

= 2.6693
j 10-sj V28.01 293.15
(3.667 1.0447
=j 1.72xj 10 g/cm·s
= 1.72
j 10 Pas
=j 1.72 10 mPas.

Thej reportedj valuej inj Tablej 1.1-3j isj 1.75j xj 10 mPass.
0

Forj CH,,j Mj =j 16.04,j oj =j 3.780A,j e/Kj =j 154j K.j Thenj atj 20°C,j T/ej =
293.15/154j=j1.904j andj 9,j =j 1.197.j Equationj 1.4-14j thenj gives

= 2.6693
j 10-sj VI6.04j 293.15
(3.780)j xj 1.197
= 1.07j 10 g/cm·s
= 1.07 x 10
j j j Pa.s
=j 1.07j xj 10 mPass.

Thej reportedj valuej inj Tablej 1.1-3j isj 1.09j xj 10 mPass.




I-3

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