MATH 3321 EMath Final Exam |
Questions and Answers | 2026 Update |
100% Correct - UH.
1. The general solution of the differential
equation dydx=2xdxdy=2x is:
A) y=x2+Cy=x2+C
B) y=2x2+Cy=2x2+C
C) y=x2y=x2
D) y=2x+Cy=2x+C
Answer: A
Rationale: Integrate both
sides: ∫dy=∫2xdx∫dy=∫2xdx → y=x2+Cy=x2+C. This is the
general solution.
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Q2. Which of the following is a separable ODE?
A) dydx=x+ydxdy=x+y
B) dydx=xydxdy=yx
C) dydx=xydxdy=xy
D) Both B and C
Answer: D
Rationale: Separable equations can be written
as g(y)dy=h(x)dxg(y)dy=h(x)dx. Option B: ydy=xdxydy=xdx;
Option C: 1ydy=xdxy1dy=xdx. Option A is not separable.
Q3. Solve the initial value problem: dydx=3ydxdy
=3y, y(0)=2y(0)=2.
A) y=2e3xy=2e3x
B) y=3e2xy=3e2x
C) y=e3x+1y=e3x+1
D) y=2exy=2ex
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Answer: A
Rationale: Separate: dyy=3dxydy=3dx.
Integrate: ln∣y∣=3x+Cln∣y∣=3x+C.
Exponentiate: y=Ce3xy=Ce3x. Use y(0)=2y(0)=2 → C=2C=2.
So y=2e3xy=2e3x.
Q4. The integrating factor for the linear ODE dydx+2y=exdxdy
+2y=ex is:
A) e2xe2x
B) e−2xe−2x
C) exex
D) e−xe−x
Answer: A
Rationale: For y′+P(x)y=Q(x)y′+P(x)y=Q(x), integrating
factor μ=e∫Pdx=e∫2dx=e2xμ=e∫Pdx=e∫2dx=e2x.
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Q5. (Scenario) A tank initially contains 100 L of pure water.
Brine with 0.2 kg/L salt flows in at 5 L/min, and the well-mixed
solution flows out at 5 L/min. The salt amount S(t)S(t) satisfies:
A) dSdt=1−0.05SdtdS=1−0.05S
B) dSdt=0.2−0.05SdtdS=0.2−0.05S
C) dSdt=1−0.2SdtdS=1−0.2S
D) dSdt=0.2+0.05SdtdS=0.2+0.05S
Answer: A
Rationale: Rate in = (5 L/min)(0.2 kg/L) = 1 kg/min. Rate out =
(S/100)*5 = 0.05S kg/min. So dSdt=1−0.05SdtdS=1−0.05S.
Q6. The equation dydx=2xydxdy=y2x is:
A) Linear
B) Separable