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STA1501 Exam Revision OCT/NOV 2026 Questions & Answers Past Papers 2026 |Descriptive Statistics and Probability|

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This exam revision paper is more than just a set of questions and answers. It’s designed to help you understand how each answer is reached, so you’re not just memorising but actually learning the concepts behind them. The solutions are clear, accurate, and supported by reliable academic references. It also includes predicted questions that are likely to appear, giving you a practical sense of what to expect and how to approach them with confidence. Whether you’re revising last minute or using it to strengthen your understanding over time, it’s structured in a way that aligns with what examiners look for. The explanations are straightforward and focused, making it easier to follow and apply. If you take the time to work through it properly, achieving high grades is a realistic outcome.

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⋆ ˆ ⋆



STA1501: Descriptive Statistics and Probability

OCT/NOV Examination 2026 Preparation
Covers Past Papers: 2023 – 2024 – 2025

⋆ ⋄ ⋆ ⋄ ⋆ ⋄ ⋆ ⋄ ⋆

Statistics – Economic & Management Sciences




Exam Revision Guide


STA1501
Module Code:

Descriptive Statistics and Probability
Module Name:

OCT/NOV 2026 Prep – Covers 2023 to 2025
Paper / Exam:

University of South Africa (UNISA)
Institution:

100 (typical paper)
Total Marks:


Use this guide to revise thoroughly. Focus on understanding, not memorisation.




Exam Revision Notes | STA1501 | 2023–2025

,STA1501 | Exam Revision 2023–2025 Descriptive Statistics & Probability



Question 1 – Data Types, Frequency Distributions & Graphical Displays [20
marks]


(a) [4 marks]


Question: Distinguish between qualitative and quantitative data. Give one example of
each in the context of a business survey.


Answer:

Key Concept
Qualitative (Categorical) data describes characteristics or categories that cannot
be measured numerically. Quantitative data represents numerical measurements or
counts.


• Qualitative data: Values are labels or names that place observations into categories.
They may be nominal (no order, e.g. gender, colour, preferred mobile network) or ordinal
(ordered categories, e.g. customer satisfaction rating: poor / fair / good / excellent).
• Quantitative data: Values are numerical and arithmetic operations are meaningful.
They may be discrete (countable, e.g. number of employees) or continuous (measurable
on a scale, e.g. monthly income in rands).

Business context examples:

• Qualitative: The preferred mobile service provider of a respondent (Vodacom, MTN, Cell
C, Telkom).
• Quantitative: The monthly salary (in rands) of an employee (e.g. R18 500).

Exam Tip
In the exam, always state both the type AND a valid example. Award marks are split
equally. Ordinal vs. nominal distinction often earns an extra mark.



(b) [8 marks]


Question: The following data represents the ages (in years) of 20 employees at a com-
pany:

23, 35, 27, 41, 29, 33, 38, 25, 47, 31, 36, 28, 42, 30, 26, 39, 44, 34, 29, 37.




Page 2 of 26

,STA1501 | Exam Revision 2023–2025 Descriptive Statistics & Probability



(i) Construct a frequency distribution table using 5 classes. (ii) Draw a histogram based
on the table. (iii) Comment on the shape of the distribution.


Answer:

Step 1: Determine class width.

 
24
Range = max − min = 47 − 23 = 24, Class width = =5
5

Step 2: Frequency Distribution Table.


Class Interval Tally Frequency Rel. Freq.
(f ) (%)

23 – 27 |||| 4 20.0%
28 – 32 ||||| 5 25.0%
33 – 37 ||||| 5 25.0%
38 – 42 |||| 4 20.0%
43 – 47 || 2 10.0%

Total 20 100%


Step 3: Histogram (TikZ).

Age Distribution of Employees
7
6
5
Frequency




4
3
2
1
0
23 28 33 38 43
Age (years)


Step 4: Shape of distribution.

The distribution is slightly positively skewed (skewed to the right) – the majority of em-
ployees are aged 28–37, with a tail extending toward the older ages (43–47). The distribution
is roughly bell-shaped with a slight right skew.

Page 3 of 26

,STA1501 | Exam Revision 2023–2025 Descriptive Statistics & Probability



(c) [8 marks]


Question: Using the same data set from (b), calculate the (i) mean, (ii) median, (iii)
mode, and (iv) standard deviation.


Answer:

Raw data (sorted): 23, 25, 26, 27, 28, 29, 29, 30, 31, 33, 34, 35, 36, 37, 38, 39, 41, 42, 44, 47.

(i) Mean
P
xi 23 + 25 + 26 + 27 + 28 + 29 + 29 + 30 + 31 + 33 + 34 + 35 + 36 + 37 + 38 + 39 + 41 + 42 + 44 + 4
x̄ = =
n 20


(ii) Median (n = 20, even number)

x10 + x11 33 + 34
Median = = = 33.5 years
2 2


(iii) Mode

The value 29 appears twice; all others appear once. Mode = 29 years.

(iv) Standard Deviation


x2i − nx̄2
P
2
s =
n−1



X
x2i = 232 +252 +262 +272 +282 +292 +292 +302 +312 +332 +342 +352 +362 +372 +382 +392 +412 +422 +442 +472


= 529+625+676+729+784+841+841+900+961+1089+1156+1225+1296+1369+1444+1521+1681+1764+193



23 376 − 20 × (33.65)2 23 376 − 22 650.45 725.55
s2 = = = ≈ 38.187
19 19 19



s≈ 38.187 ≈ 6.18 years




Page 4 of 26

,STA1501 | Exam Revision 2023–2025 Descriptive Statistics & Probability


Exam Tip
Always show the formula, substitution, and final answer. Partial marks are awarded
at each step. Use n − 1 (sample standard deviation) unless told the data is the entire
population.




Page 5 of 26

, STA1501 | Exam Revision 2023–2025 Descriptive Statistics & Probability



Question 2 – Measures of Position, Percentiles & Box-and-Whisker Plot [20
marks]


(a) [6 marks]


Question: The monthly salaries (in thousands of rands) of 10 employees at a firm are
listed below (already sorted in ascending order):

8, 11, 14, 17, 20, 23, 27, 32, 38, 45.

Calculate: (i) the first quartile Q1 , (ii) the third quartile Q3 , (iii) the interquartile range
(IQR), and (iv) the 60th percentile P60 .


Answer:

n = 10. The sorted data: 8, 11, 14, 17, 20, 23, 27, 32, 38, 45.

(i) First Quartile Q1 (25th percentile):

25
L25 = × 10 = 2.5 ⇒ round up to position 3 ⇒ Q1 = 14
100


(ii) Third Quartile Q3 (75th percentile):

75
L75 = × 10 = 7.5 ⇒ round up to position 8 ⇒ Q3 = 32
100


(iii) Interquartile Range:


IQR = Q3 − Q1 = 32 − 14 = 18 thousand rands


(iv) 60th Percentile P60 :

60 23 + 27
L60 = × 10 = 6 ⇒ whole number, so average positions 6 and 7 ⇒ P60 = = 25
100 2


Watch Out
p
UNISA uses the Lp = 100 × n method. If Lp is a whole number, average positions Lp
and Lp + 1. If Lp is a decimal, round up to the next whole number. Do not confuse this
with other percentile formulas.




Page 6 of 26

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