Probability & Statistics – lecture summary.pdf Probability & Statistics – lecture summary.pdf Probability & Statistics – lecture summary.pdf
Probability &
Statistics – lecture
summary
Probability & Statistics – lecture summary.pdf Probability & Statistics – lecture summary Probability & Statistics – lecture summary.pdf
,Probability & Statistics.pdf Probability & Statistics.pdf Probability & Statistics.pdf
D
binomial OR complement probability
P(at least 1 head) = 1 − P(no heads)
P(no heads) = (1/2)³ = 1/8
P(at least 1 head) = 1 − 1/8 = 7/8 = 0.875 ≈ 0.88
Answer: D
Probability & Statistics.pdf Probability & Statistics Probability & Statistics.pdf
, Probability & Statistics.pdf Probability & Statistics.pdf Probability & Statistics.pdf
B
normal distribution OR z-score
First find mean and std dev:
x̄ = 2402 s = 50.82
Z = (x − μ) / σ
Z = (2350 − 2402) / 50.82 = −1.0
P(X < 2350) = P(Z < −1.0) = 0.1587 ≈ 0.16
Answer: B
Probability & Statistics.pdf Probability & Statistics Probability & Statistics.pdf
Probability &
Statistics – lecture
summary
Probability & Statistics – lecture summary.pdf Probability & Statistics – lecture summary Probability & Statistics – lecture summary.pdf
,Probability & Statistics.pdf Probability & Statistics.pdf Probability & Statistics.pdf
D
binomial OR complement probability
P(at least 1 head) = 1 − P(no heads)
P(no heads) = (1/2)³ = 1/8
P(at least 1 head) = 1 − 1/8 = 7/8 = 0.875 ≈ 0.88
Answer: D
Probability & Statistics.pdf Probability & Statistics Probability & Statistics.pdf
, Probability & Statistics.pdf Probability & Statistics.pdf Probability & Statistics.pdf
B
normal distribution OR z-score
First find mean and std dev:
x̄ = 2402 s = 50.82
Z = (x − μ) / σ
Z = (2350 − 2402) / 50.82 = −1.0
P(X < 2350) = P(Z < −1.0) = 0.1587 ≈ 0.16
Answer: B
Probability & Statistics.pdf Probability & Statistics Probability & Statistics.pdf
