and Nolation
1. What is a Funtion?
pecial sulaion. whune
Cvery input (o) has otadly one output y).Tint
of t like a vanding madine :yu pr ona One
sjecife snack
|toutpt).
* Domain: The sot f all polble input values
(all x- vaes)
* Range :The st of al posible output valus
(ally- valan)
2.Funcion Notation:
Sastead =20+3, We wite:
wibng y-2042,
22+3
Pronbunced as of
Note : towdoes not man tmultiplad by X.
fust meaNs the atput vale of the
t
fonreton
, Page : 2
3.Evatualng Evaluating. Eunciong.lSblved
Paoblem)
Example 1 : Gilven the uncton fea)= 3a-542.,
find the vale of f-2).
Soluton:
To find t-2), we nad to &ubstituto X=-2
eywhee in he unclion.
fo-2) = 3(-9 -5-42
step 1: squaNe tie input first -2'= 4.
f-2)= 3t4) - 5(-2) +2
step2: Multiply the terns
Tp: Be carshul vth negative sgrns! student
Remem bex that (-sl-) = t10. Man
make mistakes he
Step 3: Add the numbors togcther
fr-)=24
Answer: Pt-) = 24
tnd
Solutton:
Substitute = 4 into the funclion
g4)=204)41
4-2
, the numer aton l top part)
2(4)4|= 8+l= 9
Hhe donominalon (bátlom part)
|siep2 : Simplity
4-3 =
Jteps: Divide the 1RAua
Answer:gc4)=9
4.The Vortoal Line Test (Gihphical approach)
what is the Vertical Line Test?
down)
you draw a vetioal tine Cup and
on te gaph a labon;
angue the at ony one
* 1ķ the ine touches
point,then the relation is a function
* te ine toucles te graph at marL
than one point, than te elaticn is not aa tuneli on
Example a: Ddeumine whetan the olouing ap
naevond a furcton y
Soluton:
Case A:
A Poabela P
1. What is a Funtion?
pecial sulaion. whune
Cvery input (o) has otadly one output y).Tint
of t like a vanding madine :yu pr ona One
sjecife snack
|toutpt).
* Domain: The sot f all polble input values
(all x- vaes)
* Range :The st of al posible output valus
(ally- valan)
2.Funcion Notation:
Sastead =20+3, We wite:
wibng y-2042,
22+3
Pronbunced as of
Note : towdoes not man tmultiplad by X.
fust meaNs the atput vale of the
t
fonreton
, Page : 2
3.Evatualng Evaluating. Eunciong.lSblved
Paoblem)
Example 1 : Gilven the uncton fea)= 3a-542.,
find the vale of f-2).
Soluton:
To find t-2), we nad to &ubstituto X=-2
eywhee in he unclion.
fo-2) = 3(-9 -5-42
step 1: squaNe tie input first -2'= 4.
f-2)= 3t4) - 5(-2) +2
step2: Multiply the terns
Tp: Be carshul vth negative sgrns! student
Remem bex that (-sl-) = t10. Man
make mistakes he
Step 3: Add the numbors togcther
fr-)=24
Answer: Pt-) = 24
tnd
Solutton:
Substitute = 4 into the funclion
g4)=204)41
4-2
, the numer aton l top part)
2(4)4|= 8+l= 9
Hhe donominalon (bátlom part)
|siep2 : Simplity
4-3 =
Jteps: Divide the 1RAua
Answer:gc4)=9
4.The Vortoal Line Test (Gihphical approach)
what is the Vertical Line Test?
down)
you draw a vetioal tine Cup and
on te gaph a labon;
angue the at ony one
* 1ķ the ine touches
point,then the relation is a function
* te ine toucles te graph at marL
than one point, than te elaticn is not aa tuneli on
Example a: Ddeumine whetan the olouing ap
naevond a furcton y
Soluton:
Case A:
A Poabela P
