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BIOS 255 / BIOS255 EXAM | Anatomy & Physiology III Complete Guide | 100% Correct Q&A | Chamberlain | Pass Guaranteed - A+ Graded

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Pass BIOS 255 Exam 2 on your first attempt with this comprehensive complete guide featuring 100% correct questions and answers for Chamberlain University! This A+ Graded resource for Anatomy and Physiology III (BIOS 255) Exam 2 covers all essential concepts including the cardiovascular system (heart anatomy, cardiac cycle, conduction system, ECG, cardiac output, blood pressure regulation), circulatory pathways (arteries, veins, capillaries, fetal circulation), lymphatic system and immunity (innate and adaptive immunity, lymphocytes, antibodies, vaccines), respiratory system (anatomy, ventilation, gas exchange, transport, regulation), and digestive system (anatomy, motility, secretion, digestion, absorption). Each question includes detailed rationales, labeling exercises, and clinical scenarios aligned with the latest Chamberlain curriculum. With our Pass Guarantee, this is the definitive study tool for nursing and pre‑health students seeking a top score on BIOS 255 Exam 2. Download now and excel in your A&P III course with confidence!

Meer zien Lees minder
Instelling
BIOS 255 / BIOS255
Vak
BIOS 255 / BIOS255

Voorbeeld van de inhoud

​BIOS 255 / BIOS255 EXAM 2​
​2026-2027 | Anatomy &​
​Physiology III Complete Guide |​
​100% Correct Q&A |​
​Chamberlain | Pass Guaranteed​
​- A+ Graded​
​ ART A – MULTIPLE CHOICE (Q1‑55)​
P
​Q1 (Cardiovascular – Cardiac Muscle Action Potential): A cardiac pacemaker cell in the SA​
​node spontaneously depolarizes during phase 4 due to which ion channel opening?​
​A. Fast voltage-gated Na⁺ channels​
​B. Funny (HCN) channels allowing Na⁺ influx​
​C. Voltage-gated K⁺ channels​
​D. L-type Ca²⁺ channels​
​[CORRECT] B​
​Rationale: Pacemaker cells lack stable resting membrane potential; funny (HCN) channels open​
​in response to hyperpolarization, allowing Na⁺ influx and gradual depolarization during phase 4.​
​Fast Na⁺ channels (A) are found in contractile cells, not pacemaker cells. K⁺ channels (C) cause​
​repolarization, not depolarization. L-type Ca²⁺ channels (D) open during phase 0 of pacemaker​
​action potentials, not phase 4. Clinical pearl: HCN channel blockers like ivabradine reduce heart​
​rate by inhibiting phase 4 depolarization—know this drug mechanism for clinical applications.​
​Q2 (Cardiovascular – ECG): During which ECG interval does the ventricular myocardium​
​remain in an absolute refractory state?​
​A. P wave duration​
​B. PR interval​
​C. QRS complex duration​
​D. QT interval​
​[CORRECT] C​
​Rationale: The QRS complex represents ventricular depolarization; during this period and​
​immediately following, Na⁺ channels are inactivated, creating an absolute refractory period​
​preventing tetany. The P wave (A) represents atrial depolarization, not ventricular. The PR​

,i​nterval (B) includes atrial depolarization and AV nodal delay but not the absolute refractory​
​period of ventricles. The QT interval (D) includes both depolarization and repolarization but​
​extends beyond the absolute refractory period into relative refractoriness. Clinical pearl: A​
​prolonged QT interval increases risk for torsades de pointes; always check electrolytes (K⁺,​
​Mg²⁺, Ca²⁺) in patients with QT prolongation.​
​Q3 (Cardiovascular – Cardiac Cycle): During isovolumetric ventricular contraction, which valve​
​status is correct?​
​A. AV valves open; semilunar valves open​
​B. AV valves closed; semilunar valves closed​
​C. AV valves open; semilunar valves closed​
​D. AV valves closed; semilunar valves open​
​[CORRECT] B​
​Rationale: Isovolumetric contraction begins when ventricular pressure exceeds atrial pressure​
​(closing AV valves) but before ventricular pressure exceeds aortic/pulmonary pressure​
​(semilunar valves remain closed), creating a brief period of constant volume. Option A describes​
​the ejection phase, C describes ventricular filling, and D describes isovolumetric relaxation.​
​Clinical pearl: The "lub" (S1) heart sound occurs at the beginning of isovolumetric contraction​
​when AV valves close; understanding this timing helps distinguish systolic from diastolic​
​murmurs.​
​Q4 (Cardiovascular – Cardiac Output): A 68-year-old patient has a stroke volume of 70 mL/beat​
​and a heart rate of 72 bpm. What is the patient's cardiac output?​
​A. 4.2 L/min​
​B. 5.04 L/min​
​C. 6.3 L/min​
​D. 7.56 L/min​
​[CORRECT] B​
​Rationale: Cardiac output (CO) = Stroke Volume (SV) × Heart Rate (HR) = 70 mL × 72 bpm =​
​5,040 mL/min = 5.04 L/min. Option A incorrectly uses 60 bpm instead of 72. Option C uses 90​
​mL SV. Option D uses 90 mL SV and 84 bpm. Clinical pearl: Normal CO is 4–8 L/min; in heart​
​failure, both SV and CO decrease, while compensatory tachycardia initially maintains CO but​
​increases myocardial oxygen demand.​
​Q5 (Cardiovascular – Frank-Starling Law): According to the Frank-Starling law of the heart,​
​increased venous return results in:​
​A. Decreased stroke volume due to overstretching​
​B. Increased stroke volume due to greater sarcomere stretch​
​C. Decreased heart rate via vagal stimulation​
​D. Increased afterload on the ventricles​
​[CORRECT] B​
​Rationale: The Frank-Starling mechanism states that increased ventricular preload​
​(end-diastolic volume) stretches cardiac muscle fibers, optimizing actin-myosin overlap and​
​increasing contractile force, thereby increasing stroke volume. Option A describes the​
​descending limb of the curve, which rarely occurs physiologically. Option C confuses​
​Frank-Starling with Bainbridge reflex. Option D confuses preload with afterload. Clinical pearl: In​

,​ eart failure, the Frank-Starling curve shifts downward; diuretics reduce preload to prevent​
h
​pulmonary congestion, while positive inotropes improve contractility.​
​Q6 (Cardiovascular – Blood Pressure): Which formula correctly calculates mean arterial​
​pressure (MAP)?​
​A. MAP = Systolic BP + Diastolic BP ÷ 2​
​B. MAP = Diastolic BP + ⅓(Systolic BP − Diastolic BP)​
​C. MAP = Systolic BP − Diastolic BP​
​D. MAP = (Systolic BP × 2 + Diastolic BP) ÷ 3​
​[CORRECT] B​
​Rationale: MAP = Diastolic BP + ⅓(Systolic BP − Diastolic BP), or equivalently (2 × Diastolic +​
​Systolic) ÷ 3, because diastole lasts approximately twice as long as systole at normal heart​
​rates. Option A averages the pressures equally, ignoring the longer diastolic period. Option C​
​calculates pulse pressure, not MAP. Option D weights systolic pressure incorrectly. Clinical​
​pearl: MAP must be ≥65 mmHg for adequate tissue perfusion; in shock, vasopressors are​
​titrated to maintain MAP ≥65 mmHg to preserve organ perfusion.​
​Q7 (Cardiovascular – Baroreceptor Reflex): A patient experiences acute hemorrhage, causing​
​decreased arterial pressure. Which baroreceptor-mediated response occurs first?​
​A. Decreased sympathetic outflow to the heart​
​B. Increased parasympathetic outflow to the SA node​
​C. Increased sympathetic outflow to arterioles causing vasoconstriction​
​D. Decreased ADH secretion from the posterior pituitary​
​[CORRECT] C​
​Rationale: Baroreceptors in the carotid sinus and aortic arch detect decreased stretch, reducing​
​inhibitory signals to the medulla, which increases sympathetic outflow to arterioles​
​(vasoconstriction), increasing total peripheral resistance to maintain BP. Option A is incorrect​
​because sympathetic outflow increases, not decreases. Option B is wrong because​
​parasympathetic tone decreases, allowing heart rate to increase. Option D is incorrect because​
​ADH secretion increases, not decreases. Clinical pearl: The baroreceptor reflex responds within​
​seconds; if BP remains low after 10–20 seconds, chemoreceptors and hormonal mechanisms​
​(RAAS, ADH) are activated.​
​Q8 (Cardiovascular – RAAS): In the renin-angiotensin-aldosterone system (RAAS), angiotensin​
​II directly causes all of the following EXCEPT:​
​A. Vasoconstriction of arterioles​
​B. Stimulation of aldosterone secretion from the adrenal cortex​
​C. Increased thirst via hypothalamic stimulation​
​D. Decreased sodium reabsorption in the proximal tubule​
​[CORRECT] D​
​Rationale: Angiotensin II promotes Na⁺ and water retention by stimulating aldosterone (which​
​acts on distal tubule/collecting duct) and directly enhancing Na⁺-H⁺ exchange in the proximal​
​tubule, increasing Na⁺ reabsorption—not decreasing it. Options A, B, and C are all correct​
​actions of angiotensin II. Clinical pearl: ACE inhibitors block angiotensin II formation, causing​
​vasodilation and reduced aldosterone; however, they can cause hyperkalemia due to decreased​
​aldosterone-mediated K⁺ secretion—monitor electrolytes closely.​

, ​ 9 (Cardiovascular – Capillary Exchange): At the arterial end of a capillary, net filtration occurs​
Q
​primarily because:​
​A. Hydrostatic pressure is less than oncotic pressure​
​B. Hydrostatic pressure exceeds oncotic pressure​
​C. Oncotic pressure exceeds hydrostatic pressure​
​D. Interstitial fluid pressure exceeds capillary pressure​
​[CORRECT] B​
​Rationale: At the arterial end, capillary hydrostatic pressure (≈35 mmHg) exceeds plasma​
​oncotic pressure (≈25 mmHg), creating a net outward force that filters fluid into interstitial​
​spaces. At the venous end, oncotic pressure exceeds hydrostatic pressure, promoting​
​reabsorption. Options A, C, and D describe conditions favoring reabsorption, not filtration.​
​Clinical pearl: In liver disease (decreased albumin synthesis) or nephrotic syndrome (albumin​
​loss), decreased oncotic pressure causes edema because less fluid is reabsorbed at the​
​venous end.​
​Q10 (Cardiovascular – Shock): A patient presents with hypotension, warm flushed skin, and​
​bounding pulses after a severe allergic reaction. This describes which type of shock?​
​A. Hypovolemic shock​
​B. Cardiogenic shock​
​C. Anaphylactic (distributive) shock​
​D. Obstructive shock​
​[CORRECT] C​
​Rationale: Anaphylactic shock is a form of distributive shock characterized by massive​
​vasodilation (warm, flushed skin), increased capillary permeability, and hypotension due to​
​histamine and other mediators. Hypovolemic shock (A) presents with cold, clammy skin due to​
​compensatory vasoconstriction. Cardiogenic shock (B) shows signs of pump failure (cool​
​extremities, JVD). Obstructive shock (D) results from physical obstruction (tamponade, tension​
​pneumothorax). Clinical pearl: First-line treatment for anaphylactic shock is epinephrine IM​
​(0.3–0.5 mg of 1:1000), which causes α₁-mediated vasoconstriction and β₂-mediated​
​bronchodilation.​
​Q11 (Cardiovascular – ECG Intervals): A prolonged PR interval (>0.20 seconds) on ECG​
​indicates:​
​A. Delayed conduction through the AV node​
​B. Bundle branch block​
​C. Ventricular hypertrophy​
​D. Atrial fibrillation​
​[CORRECT] A​
​Rationale: The PR interval represents the time from atrial depolarization onset to ventricular​
​depolarization onset, primarily reflecting AV nodal conduction; prolongation indicates​
​first-degree AV block. Bundle branch block (B) widens the QRS complex, not the PR interval.​
​Ventricular hypertrophy (C) alters QRS amplitude and axis. Atrial fibrillation (D) shows absent P​
​waves and irregular rhythm, not PR prolongation. Clinical pearl: First-degree AV block is often​
​benign and asymptomatic; however, if it progresses to second- or third-degree block, a​
​pacemaker may be indicated—monitor progression.​

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Vak
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