TEST 2026 COMPLETE QUESTIONS
AND VERIFIED ANSWERS
◉ In a chemical reaction with first order kinetics, which is true at
constant temperature?. Answer: a) Half-life and k are both constant
-k is only temperature dependent. Temp is constant so k also is, so half
life is constant.
◉ Which of the following best helps explain why an increase in
temperature increases the rate of a chemical reaction?. Answer: d) at
higher temperatures, high-energy collisions happen more frequently
-when T↑ molecules are more KE on average and therefore have more
collisions
◉ 2 NO₂(g)+F₂(g)→2 NO₂F(g)
The rate law for the reaction represented by the equation above is rate=k
[NO₂][F₂]. Which of the following could be the first elementary step of a
two-step mechanism for the reaction if the first step is slow and the
second step is fast?. Answer: b) NO₂(g)+F₂(g)→NO₂F(g)+F(g)
-rate=k[NO₂][F₂] match!
◉ A 0.35 g sample of Li(s) is placed in an Erienmeyer flask containing
100 mL of water at 25°C. A balloon is placed over the mouth of a flask
to collect the hydrogen gas that is generated. Which of the following
changes will most likely increase the rate of reaction between Li(s) and
water?. Answer: c) using a .35 g sample of Li(s) cut into small pieces
, -rate of rxn ↑ when surface area ↑
◉ The graph above shows the number of molecules that have sufficient
energy to overcome Ea at a certain temperature for a given reaction.
How would adding a catalyst change the appearance of the graph?.
Answer: d) a catalyst decrease the activation energy
◉ rate=k[X]
For the rate law given above, a plot of which of the following is a
straight line?. Answer: b)in [X] versus time
-1st order
◉ Given the data for the reaction A+B→C, determine the rate
expression for the reaction. [A], M: 0.1,0.2,0.1... [B], M: 0.2,0.2,0.1...
Rate of formation of C,M/s: 40,80,40. Answer: d) rate=k[A]
-1st order
◉ The reaction, A+B→2 C, has the following rate expression:
rate=k[A]²[B]. What are the units for the rate constant for this rate law?.
Answer: c) M²hours¹
-overall 3rd order
M¹⁻³/hours
M⁻²∙hours⁻¹