National Elevator Industry
SMAXE • 006
NEIEP✦
✦
600
Educational Program
Elevator Electrical/Electronic · 600 Examination Series
ELEVATOR
E L E V AT O R I N D U S T R Y E X C E L L E N C E T H R O U G H E D U C AT I O N
NEIEP 600 — Examination Series
A C / D C T H E O R Y · S E M I CO N D U C TO R S · D I O D E S · T R A N S I STO R S · D I G I TA L LO G I C · P O W E R S U P P L I E S
ORGANIZATION National Elevator Industry Educational COURSE 600 — Electronics for Elevator Technicians
Program (NEIEP)
ACADEMIC YEAR TOTAL QUESTIONS 25 Questions
SUBJECT AREAS AC Waveforms · Capacitors · Inductors · FORMAT Multiple Choice — Select the Single Best
Semiconductors · Digital Answer
EXAMINATION INSTRUCTIONS
▸ Select the single best answer for each question based on the NEIEP 600 electronics curriculum for elevator technicians.
▸ Content covers: AC waveform analysis, capacitors (time constants, reactance), inductors (CEMF, reactance, saturation),
semiconductors (diodes, zener, LED, photodiode, SCR), transformers, digital logic (binary, hexadecimal), and power supplies
(rectifiers, regulators).
▸ Key formulas: T = 1/f, Vpeak = VRMS × √2, TC = R × C, XL = 2πfL, XC = 1/(2πfC), transformer turns ratio.
SECTION I — AC/DC THEORY, COMPONENTS & SEMICONDUCTOR Questions 1 –
DEVICES 25
1. What is the period of a 120 Hz AC waveform?
A. 120 seconds — the frequency value.
B. 0.00833 seconds — T = 1/f = 1/120.
C. 60 seconds — half the frequency.
D. 0.0167 seconds — 1/60.
CORRECT ANSWER B — 0.00833 seconds — T = 1/f = 1/120.
RATIONALE The period (T) is the time to complete one full cycle. T = 1/f = 1/120 Hz = 0.00833 seconds. A two-pole AC
generator produces one full AC cycle per complete revolution. A sine wave beginning at 0° reaches positive
peak at 90° and negative peak at 270°. Peak-to-peak voltage is the voltage between positive and negative
peaks. The expression 0.636 × Vpeak describes the average voltage or current.
, 2. What is the peak voltage of a waveform with 480 VAC RMS?
A. 480 volts — equal to the RMS value.
B. 679 volts — Vpeak = VRMS × 1.414.
C. 960 volts — double the RMS value.
D. 339 volts — RMS × 0.707.
CORRECT ANSWER B — 679 volts — Vpeak = VRMS × 1.414.
RATIONALE Vpeak = VRMS × √2 = 480 × 1.414 = 678.7 ≈ 679 volts. AC effective voltage is the AC voltage required to produce
the same power as an equivalent DC voltage. The term "effective voltage" is synonymous with RMS (Root
Mean Square). This relationship is fundamental for understanding AC power calculations and rectifier design.
3. What is the secondary voltage of a 5:1 step-down transformer with a primary voltage of 125 volts?
A. 625 volts — primary × turns ratio.
B. 25 volts — primary ÷ turns ratio = 125 ÷ 5.
C. 125 volts — same as primary.
D. 5 volts — equal to the ratio.
CORRECT ANSWER B — 25 volts — primary ÷ turns ratio = 125 ÷ 5.
RATIONALE For a 5:1 step-down transformer: Vsecondary = Vprimary ÷ ratio = 125V ÷ 5 = 25V. Conversely, the secondary
current will be 5 times the primary current: with 1A primary, secondary current = 5A. Three-phase voltage can
be stepped down using either a three-phase transformer or three single-phase transformers. The turns ratio
determines voltage and current transformation inversely.
4. In capacitors, what is the purpose of the dielectric?
A. To increase the physical size of the capacitor.
B. To prevent arcing within the capacitor by insulating the plates.
C. To conduct current between the plates.
D. To increase resistance to current flow.
CORRECT ANSWER B — To prevent arcing within the capacitor by insulating the plates.
RATIONALE The DIELECTRIC is the insulating material between capacitor plates that prevents arcing while allowing the
electric field to be established. In AC circuits, current LEADS voltage at all times in a purely capacitive circuit.
Capacitance describes the ability to store an electrical charge, measured in FARADS. Increasing plate area
INCREASES capacitance. Polarized electrolytic capacitors require correct voltage polarity. When capacitor
voltage equals source voltage, current flow STOPS. Current is MAXIMUM the instant power is applied.
SMAXE • 006
NEIEP✦
✦
600
Educational Program
Elevator Electrical/Electronic · 600 Examination Series
ELEVATOR
E L E V AT O R I N D U S T R Y E X C E L L E N C E T H R O U G H E D U C AT I O N
NEIEP 600 — Examination Series
A C / D C T H E O R Y · S E M I CO N D U C TO R S · D I O D E S · T R A N S I STO R S · D I G I TA L LO G I C · P O W E R S U P P L I E S
ORGANIZATION National Elevator Industry Educational COURSE 600 — Electronics for Elevator Technicians
Program (NEIEP)
ACADEMIC YEAR TOTAL QUESTIONS 25 Questions
SUBJECT AREAS AC Waveforms · Capacitors · Inductors · FORMAT Multiple Choice — Select the Single Best
Semiconductors · Digital Answer
EXAMINATION INSTRUCTIONS
▸ Select the single best answer for each question based on the NEIEP 600 electronics curriculum for elevator technicians.
▸ Content covers: AC waveform analysis, capacitors (time constants, reactance), inductors (CEMF, reactance, saturation),
semiconductors (diodes, zener, LED, photodiode, SCR), transformers, digital logic (binary, hexadecimal), and power supplies
(rectifiers, regulators).
▸ Key formulas: T = 1/f, Vpeak = VRMS × √2, TC = R × C, XL = 2πfL, XC = 1/(2πfC), transformer turns ratio.
SECTION I — AC/DC THEORY, COMPONENTS & SEMICONDUCTOR Questions 1 –
DEVICES 25
1. What is the period of a 120 Hz AC waveform?
A. 120 seconds — the frequency value.
B. 0.00833 seconds — T = 1/f = 1/120.
C. 60 seconds — half the frequency.
D. 0.0167 seconds — 1/60.
CORRECT ANSWER B — 0.00833 seconds — T = 1/f = 1/120.
RATIONALE The period (T) is the time to complete one full cycle. T = 1/f = 1/120 Hz = 0.00833 seconds. A two-pole AC
generator produces one full AC cycle per complete revolution. A sine wave beginning at 0° reaches positive
peak at 90° and negative peak at 270°. Peak-to-peak voltage is the voltage between positive and negative
peaks. The expression 0.636 × Vpeak describes the average voltage or current.
, 2. What is the peak voltage of a waveform with 480 VAC RMS?
A. 480 volts — equal to the RMS value.
B. 679 volts — Vpeak = VRMS × 1.414.
C. 960 volts — double the RMS value.
D. 339 volts — RMS × 0.707.
CORRECT ANSWER B — 679 volts — Vpeak = VRMS × 1.414.
RATIONALE Vpeak = VRMS × √2 = 480 × 1.414 = 678.7 ≈ 679 volts. AC effective voltage is the AC voltage required to produce
the same power as an equivalent DC voltage. The term "effective voltage" is synonymous with RMS (Root
Mean Square). This relationship is fundamental for understanding AC power calculations and rectifier design.
3. What is the secondary voltage of a 5:1 step-down transformer with a primary voltage of 125 volts?
A. 625 volts — primary × turns ratio.
B. 25 volts — primary ÷ turns ratio = 125 ÷ 5.
C. 125 volts — same as primary.
D. 5 volts — equal to the ratio.
CORRECT ANSWER B — 25 volts — primary ÷ turns ratio = 125 ÷ 5.
RATIONALE For a 5:1 step-down transformer: Vsecondary = Vprimary ÷ ratio = 125V ÷ 5 = 25V. Conversely, the secondary
current will be 5 times the primary current: with 1A primary, secondary current = 5A. Three-phase voltage can
be stepped down using either a three-phase transformer or three single-phase transformers. The turns ratio
determines voltage and current transformation inversely.
4. In capacitors, what is the purpose of the dielectric?
A. To increase the physical size of the capacitor.
B. To prevent arcing within the capacitor by insulating the plates.
C. To conduct current between the plates.
D. To increase resistance to current flow.
CORRECT ANSWER B — To prevent arcing within the capacitor by insulating the plates.
RATIONALE The DIELECTRIC is the insulating material between capacitor plates that prevents arcing while allowing the
electric field to be established. In AC circuits, current LEADS voltage at all times in a purely capacitive circuit.
Capacitance describes the ability to store an electrical charge, measured in FARADS. Increasing plate area
INCREASES capacitance. Polarized electrolytic capacitors require correct voltage polarity. When capacitor
voltage equals source voltage, current flow STOPS. Current is MAXIMUM the instant power is applied.
