NURS 6501 ADVANCED PATHOPHYSIOLOGY MIDTERM
EXAM 2026/2027 | Walden University MSN/FNP | Complete
Solutions | Verified Answers | Pass Guaranteed - A+ Graded
[Section 1: Cellular Adaptation, Injury, Death & Neoplasia (Q1-14)]
Q1. A 78-year-old patient on prolonged bed rest develops thinning of the quadriceps
muscles. This cellular adaptation is best described as:
A. Hypertrophy
B. Hyperplasia
C. Atrophy [CORRECT]
D. Metaplasia
Correct Answer: C
Rationale: Atrophy is the reduction in cell size and number due to decreased workload
or disuse, which explains muscle wasting in immobilized patients. Hypertrophy involves
increased cell size, hyperplasia involves increased cell number, and metaplasia involves
replacement of one cell type with another.
Correct Answer: C
Q2. A 35-year-old woman's uterus enlarges during pregnancy. This process involves
both cellular enlargement and increased cell number. Which adaptations are occurring?
A. Atrophy and metaplasia
B. Hypertrophy and hyperplasia [CORRECT]
C. Dysplasia and hypertrophy
D. Hyperplasia and atrophy
Correct Answer: B
,Rationale: Uterine enlargement during pregnancy involves both hypertrophy (increased
myometrial cell size) and hyperplasia (increased myometrial cell number). Atrophy and
metaplasia are not involved in normal pregnancy adaptation, and dysplasia represents
abnormal disordered growth.
Correct Answer: B
Q3. A 45-year-old smoker is found to have stratified squamous epithelium replacing the
normal pseudostratified columnar epithelium in the bronchi. This change is classified
as:
A. Dysplasia
B. Hyperplasia
C. Metaplasia [CORRECT]
D. Anaplasia
Correct Answer: C
Rationale: Metaplasia is the reversible replacement of one differentiated cell type with
another better suited to environmental stress, such as squamous epithelium in
response to chronic smoking irritation. Dysplasia involves disordered maturation,
hyperplasia is increased cell number without change in type, and anaplasia is a hallmark
of malignancy with loss of differentiation.
Correct Answer: C
Q4. A cervical Pap smear reveals disordered epithelial maturation, nuclear
hyperchromasia, and loss of polarity extending through the full thickness of the
epithelium. This is consistent with:
A. Metaplasia
B. Carcinoma in situ [CORRECT]
C. Benign hypertrophy
D. Reversible cellular injury
Correct Answer: B
,Rationale: Full-thickness dysplasia with loss of maturation and polarity constitutes
carcinoma in situ, a premalignant or malignant lesion confined to the epithelium.
Metaplasia is a reversible change in cell type, hypertrophy involves cell enlargement,
and reversible injury does not produce permanent architectural disorganization.
Correct Answer: B
Q5. A patient experiences acute myocardial ischemia. Which cellular change indicates
reversible injury?
A. Karyolysis
B. Cellular swelling and fatty change [CORRECT]
C. Calcium influx with mitochondrial calcification
D. Activation of caspases
Correct Answer: B
Rationale: Reversible ischemic injury is characterized by cellular swelling due to Na+/K+
pump failure and fatty change from impaired lipid metabolism. Karyolysis, calcium
influx with mitochondrial calcification, and caspase activation are all features of
irreversible injury or apoptosis.
Correct Answer: B
Q6. Which event marks the critical transition from reversible to irreversible cellular
injury?
A. Loss of microvilli
B. ATP depletion
C. Influx of calcium into the cytosol damaging mitochondria [CORRECT]
D. Cellular swelling
Correct Answer: C
Rationale: Massive calcium influx into the cytosol and mitochondria causes irreversible
mitochondrial dysfunction and activation of destructive enzymes, marking the point of
, no return. ATP depletion, cellular swelling, and microvilli loss are reversible changes if
blood flow is restored promptly.
Correct Answer: C
Q7. A patient dies from a myocardial infarction. Autopsy reveals firm, pale tissue with
preserved cellular outlines but loss of nuclei. This type of necrosis is:
A. Liquefactive necrosis
B. Caseous necrosis
C. Coagulative necrosis [CORRECT]
D. Fat necrosis
Correct Answer: C
Rationale: Coagulative necrosis preserves the architectural framework of dead cells for
several days due to denaturation of structural and enzymatic proteins, which is
characteristic of ischemia in solid organs like the heart. Liquefactive necrosis occurs in
the brain or with bacterial infection, caseous necrosis is seen in tuberculosis, and fat
necrosis occurs in adipose tissue.
Correct Answer: C
Q8. A patient with a history of alcohol abuse develops severe abdominal pain and a
cystic lesion in the pancreas. The necrotic fat surrounding the pancreas appears chalky
white. This is:
A. Coagulative necrosis
B. Caseous necrosis
C. Fat necrosis [CORRECT]
D. Liquefactive necrosis
Correct Answer: C
Rationale: Pancreatic enzymes lipolyze peripancreatic fat, causing fat necrosis with
calcium soap formation (saponification) that appears chalky white on gross
examination. Coagulative necrosis affects myocardium, caseous necrosis is associated
EXAM 2026/2027 | Walden University MSN/FNP | Complete
Solutions | Verified Answers | Pass Guaranteed - A+ Graded
[Section 1: Cellular Adaptation, Injury, Death & Neoplasia (Q1-14)]
Q1. A 78-year-old patient on prolonged bed rest develops thinning of the quadriceps
muscles. This cellular adaptation is best described as:
A. Hypertrophy
B. Hyperplasia
C. Atrophy [CORRECT]
D. Metaplasia
Correct Answer: C
Rationale: Atrophy is the reduction in cell size and number due to decreased workload
or disuse, which explains muscle wasting in immobilized patients. Hypertrophy involves
increased cell size, hyperplasia involves increased cell number, and metaplasia involves
replacement of one cell type with another.
Correct Answer: C
Q2. A 35-year-old woman's uterus enlarges during pregnancy. This process involves
both cellular enlargement and increased cell number. Which adaptations are occurring?
A. Atrophy and metaplasia
B. Hypertrophy and hyperplasia [CORRECT]
C. Dysplasia and hypertrophy
D. Hyperplasia and atrophy
Correct Answer: B
,Rationale: Uterine enlargement during pregnancy involves both hypertrophy (increased
myometrial cell size) and hyperplasia (increased myometrial cell number). Atrophy and
metaplasia are not involved in normal pregnancy adaptation, and dysplasia represents
abnormal disordered growth.
Correct Answer: B
Q3. A 45-year-old smoker is found to have stratified squamous epithelium replacing the
normal pseudostratified columnar epithelium in the bronchi. This change is classified
as:
A. Dysplasia
B. Hyperplasia
C. Metaplasia [CORRECT]
D. Anaplasia
Correct Answer: C
Rationale: Metaplasia is the reversible replacement of one differentiated cell type with
another better suited to environmental stress, such as squamous epithelium in
response to chronic smoking irritation. Dysplasia involves disordered maturation,
hyperplasia is increased cell number without change in type, and anaplasia is a hallmark
of malignancy with loss of differentiation.
Correct Answer: C
Q4. A cervical Pap smear reveals disordered epithelial maturation, nuclear
hyperchromasia, and loss of polarity extending through the full thickness of the
epithelium. This is consistent with:
A. Metaplasia
B. Carcinoma in situ [CORRECT]
C. Benign hypertrophy
D. Reversible cellular injury
Correct Answer: B
,Rationale: Full-thickness dysplasia with loss of maturation and polarity constitutes
carcinoma in situ, a premalignant or malignant lesion confined to the epithelium.
Metaplasia is a reversible change in cell type, hypertrophy involves cell enlargement,
and reversible injury does not produce permanent architectural disorganization.
Correct Answer: B
Q5. A patient experiences acute myocardial ischemia. Which cellular change indicates
reversible injury?
A. Karyolysis
B. Cellular swelling and fatty change [CORRECT]
C. Calcium influx with mitochondrial calcification
D. Activation of caspases
Correct Answer: B
Rationale: Reversible ischemic injury is characterized by cellular swelling due to Na+/K+
pump failure and fatty change from impaired lipid metabolism. Karyolysis, calcium
influx with mitochondrial calcification, and caspase activation are all features of
irreversible injury or apoptosis.
Correct Answer: B
Q6. Which event marks the critical transition from reversible to irreversible cellular
injury?
A. Loss of microvilli
B. ATP depletion
C. Influx of calcium into the cytosol damaging mitochondria [CORRECT]
D. Cellular swelling
Correct Answer: C
Rationale: Massive calcium influx into the cytosol and mitochondria causes irreversible
mitochondrial dysfunction and activation of destructive enzymes, marking the point of
, no return. ATP depletion, cellular swelling, and microvilli loss are reversible changes if
blood flow is restored promptly.
Correct Answer: C
Q7. A patient dies from a myocardial infarction. Autopsy reveals firm, pale tissue with
preserved cellular outlines but loss of nuclei. This type of necrosis is:
A. Liquefactive necrosis
B. Caseous necrosis
C. Coagulative necrosis [CORRECT]
D. Fat necrosis
Correct Answer: C
Rationale: Coagulative necrosis preserves the architectural framework of dead cells for
several days due to denaturation of structural and enzymatic proteins, which is
characteristic of ischemia in solid organs like the heart. Liquefactive necrosis occurs in
the brain or with bacterial infection, caseous necrosis is seen in tuberculosis, and fat
necrosis occurs in adipose tissue.
Correct Answer: C
Q8. A patient with a history of alcohol abuse develops severe abdominal pain and a
cystic lesion in the pancreas. The necrotic fat surrounding the pancreas appears chalky
white. This is:
A. Coagulative necrosis
B. Caseous necrosis
C. Fat necrosis [CORRECT]
D. Liquefactive necrosis
Correct Answer: C
Rationale: Pancreatic enzymes lipolyze peripancreatic fat, causing fat necrosis with
calcium soap formation (saponification) that appears chalky white on gross
examination. Coagulative necrosis affects myocardium, caseous necrosis is associated
