NR507 ADVANCED PATHOPHYSIOLOGY FINAL EXAM
REVIEW 2026/2027 | 100% Correct | Grade A | Chamberlain
University | Questions & Verified Answers | Pass Guaranteed
- A+ Graded
Section 1: Cellular Adaptation, Injury & Neoplasia (Q1-12)
Q1. A 65-year-old male with a history of heavy alcohol use presents with hepatic
steatosis. Which cellular adaptation best describes the accumulation of fat within
hepatocytes?
A. Hypertrophy
B. Hyperplasia
C. Metaplasia
D. Steatosis (fatty change)
Correct Answer: D. Steatosis (fatty change) [CORRECT]
Rationale: Steatosis is the intracellular accumulation of triglycerides within parenchymal
cells, most commonly hepatocytes. It represents a reversible cellular adaptation to
metabolic stress. REVIEW NOTE: Hypertrophy = increased cell size; hyperplasia =
increased cell number; metaplasia = change in cell type.
Q2. A patient with chronic gastric reflux develops Barrett's esophagus. Which type of
cellular adaptation has occurred?
A. Dysplasia
B. Metaplasia
C. Hyperplasia
D. Anaplasia
Correct Answer: B. Metaplasia [CORRECT]
,Rationale: Barrett's esophagus is the replacement of normal squamous epithelium with
columnar epithelium (intestinal metaplasia) due to chronic acid exposure. Metaplasia is
a reversible adaptation where one differentiated cell type replaces another. REVIEW
NOTE: Dysplasia = disordered growth; anaplasia = loss of differentiation (malignant).
Q3. A patient with myocardial infarction shows coagulative necrosis on biopsy. Which
characteristic distinguishes coagulative necrosis from liquefactive necrosis?
A. Preservation of tissue architecture despite cell death
B. Complete liquefaction of tissue into pus
C. Caseous granular debris
D. Fatty acid saponification
Correct Answer: A. Preservation of tissue architecture despite cell death [CORRECT]
Rationale: Coagulative necrosis (typical of ischemia in solid organs except brain)
preserves the structural outline of dead cells for days due to denatured proteins.
Liquefactive necrosis (brain, abscess) involves enzymatic digestion. REVIEW NOTE:
Caseous = TB; fat necrosis = pancreatitis/trauma.
Q4. A patient with acute pancreatitis develops areas of chalky white deposits in the
peripancreatic fat. Which pathologic process is responsible?
A. Coagulative necrosis
B. Liquefactive necrosis
C. Fat necrosis with calcium soap formation (saponification)
D. Caseous necrosis
Correct Answer: C. Fat necrosis with calcium soap formation (saponification)
[CORRECT]
Rationale: Pancreatic lipase release digests peripancreatic fat into fatty acids, which
combine with calcium to form insoluble calcium soaps (chalky white deposits). This is
pathognomonic for fat necrosis. REVIEW NOTE: Saponification requires calcium; visible
on imaging and gross examination.
,Q5. A cell undergoing programmed cell death demonstrates cell shrinkage, chromatin
condensation, and formation of apoptotic bodies without inflammation. Which
mechanism initiates this process?
A. ATP depletion and cell membrane rupture
B. Activation of caspases via intrinsic or extrinsic pathways
C. Lysosomal enzyme release
D. Coagulation of cytoplasmic proteins
Correct Answer: B. Activation of caspases via intrinsic or extrinsic pathways [CORRECT]
Rationale: Apoptosis is energy-dependent programmed cell death mediated by caspase
cascades. The intrinsic pathway (mitochondrial) involves Bcl-2 family proteins and
cytochrome c; the extrinsic pathway involves Fas/FasL. REVIEW NOTE: Necrosis =
ATP-depleted, inflammatory; apoptosis = ATP-dependent, non-inflammatory.
Q6. A tumor biopsy shows cells with marked nuclear pleomorphism, high
nuclear-to-cytoplasmic ratio, hyperchromatic nuclei, and numerous atypical mitotic
figures. These features best describe:
A. Differentiation
B. Anaplasia
C. Metaplasia
D. Hypertrophy
Correct Answer: B. Anaplasia [CORRECT]
Rationale: Anaplasia is the hallmark of malignancy, characterized by loss of
differentiation, nuclear pleomorphism, high N/C ratio, and atypical mitoses. These
features indicate aggressive, poorly differentiated tumor behavior. REVIEW NOTE:
Anaplasia = no differentiation; dysplasia = disordered but not yet malignant.
Q7. A patient with retinoblastoma has a mutation in the RB tumor suppressor gene.
Which cellular function is impaired by loss of this gene?
, A. DNA repair mechanisms
B. Cell cycle checkpoint control (G1/S transition)
C. Apoptosis initiation
D. Telomerase activation
Correct Answer: B. Cell cycle checkpoint control (G1/S transition) [CORRECT]
Rationale: The Rb protein normally binds E2F transcription factors, preventing G1/S
progression. Loss of Rb allows uncontrolled cell cycle entry. p53 regulates DNA damage
checkpoints; telomerase is an oncogene target. REVIEW NOTE: Rb = "gatekeeper" of
G1/S; p53 = "guardian of the genome."
Q8. A patient develops paraneoplastic syndrome with hypercalcemia from a lung
squamous cell carcinoma. Which substance is most likely secreted by the tumor?
A. Adrenocorticotropic hormone (ACTH)
B. Parathyroid hormone-related peptide (PTHrP)
C. Antidiuretic hormone (ADH)
D. Erythropoietin
Correct Answer: B. Parathyroid hormone-related peptide (PTHrP) [CORRECT]
Rationale: PTHrP mimics PTH, causing humoral hypercalcemia of malignancy—most
common with squamous cell carcinomas (lung, head/neck, cervix, esophagus). It
activates bone resorption and renal calcium reabsorption. REVIEW NOTE: PTHrP is the
most common cause of malignancy-related hypercalcemia.
Q9. A patient with familial adenomatous polyposis (FAP) has a mutation in the APC
gene. Which cellular pathway is disrupted?
A. p53-mediated apoptosis
B. Wnt/β-catenin signaling pathway
C. Ras/MAPK signaling
D. HER2/neu receptor signaling
Correct Answer: B. Wnt/β-catenin signaling pathway [CORRECT]
REVIEW 2026/2027 | 100% Correct | Grade A | Chamberlain
University | Questions & Verified Answers | Pass Guaranteed
- A+ Graded
Section 1: Cellular Adaptation, Injury & Neoplasia (Q1-12)
Q1. A 65-year-old male with a history of heavy alcohol use presents with hepatic
steatosis. Which cellular adaptation best describes the accumulation of fat within
hepatocytes?
A. Hypertrophy
B. Hyperplasia
C. Metaplasia
D. Steatosis (fatty change)
Correct Answer: D. Steatosis (fatty change) [CORRECT]
Rationale: Steatosis is the intracellular accumulation of triglycerides within parenchymal
cells, most commonly hepatocytes. It represents a reversible cellular adaptation to
metabolic stress. REVIEW NOTE: Hypertrophy = increased cell size; hyperplasia =
increased cell number; metaplasia = change in cell type.
Q2. A patient with chronic gastric reflux develops Barrett's esophagus. Which type of
cellular adaptation has occurred?
A. Dysplasia
B. Metaplasia
C. Hyperplasia
D. Anaplasia
Correct Answer: B. Metaplasia [CORRECT]
,Rationale: Barrett's esophagus is the replacement of normal squamous epithelium with
columnar epithelium (intestinal metaplasia) due to chronic acid exposure. Metaplasia is
a reversible adaptation where one differentiated cell type replaces another. REVIEW
NOTE: Dysplasia = disordered growth; anaplasia = loss of differentiation (malignant).
Q3. A patient with myocardial infarction shows coagulative necrosis on biopsy. Which
characteristic distinguishes coagulative necrosis from liquefactive necrosis?
A. Preservation of tissue architecture despite cell death
B. Complete liquefaction of tissue into pus
C. Caseous granular debris
D. Fatty acid saponification
Correct Answer: A. Preservation of tissue architecture despite cell death [CORRECT]
Rationale: Coagulative necrosis (typical of ischemia in solid organs except brain)
preserves the structural outline of dead cells for days due to denatured proteins.
Liquefactive necrosis (brain, abscess) involves enzymatic digestion. REVIEW NOTE:
Caseous = TB; fat necrosis = pancreatitis/trauma.
Q4. A patient with acute pancreatitis develops areas of chalky white deposits in the
peripancreatic fat. Which pathologic process is responsible?
A. Coagulative necrosis
B. Liquefactive necrosis
C. Fat necrosis with calcium soap formation (saponification)
D. Caseous necrosis
Correct Answer: C. Fat necrosis with calcium soap formation (saponification)
[CORRECT]
Rationale: Pancreatic lipase release digests peripancreatic fat into fatty acids, which
combine with calcium to form insoluble calcium soaps (chalky white deposits). This is
pathognomonic for fat necrosis. REVIEW NOTE: Saponification requires calcium; visible
on imaging and gross examination.
,Q5. A cell undergoing programmed cell death demonstrates cell shrinkage, chromatin
condensation, and formation of apoptotic bodies without inflammation. Which
mechanism initiates this process?
A. ATP depletion and cell membrane rupture
B. Activation of caspases via intrinsic or extrinsic pathways
C. Lysosomal enzyme release
D. Coagulation of cytoplasmic proteins
Correct Answer: B. Activation of caspases via intrinsic or extrinsic pathways [CORRECT]
Rationale: Apoptosis is energy-dependent programmed cell death mediated by caspase
cascades. The intrinsic pathway (mitochondrial) involves Bcl-2 family proteins and
cytochrome c; the extrinsic pathway involves Fas/FasL. REVIEW NOTE: Necrosis =
ATP-depleted, inflammatory; apoptosis = ATP-dependent, non-inflammatory.
Q6. A tumor biopsy shows cells with marked nuclear pleomorphism, high
nuclear-to-cytoplasmic ratio, hyperchromatic nuclei, and numerous atypical mitotic
figures. These features best describe:
A. Differentiation
B. Anaplasia
C. Metaplasia
D. Hypertrophy
Correct Answer: B. Anaplasia [CORRECT]
Rationale: Anaplasia is the hallmark of malignancy, characterized by loss of
differentiation, nuclear pleomorphism, high N/C ratio, and atypical mitoses. These
features indicate aggressive, poorly differentiated tumor behavior. REVIEW NOTE:
Anaplasia = no differentiation; dysplasia = disordered but not yet malignant.
Q7. A patient with retinoblastoma has a mutation in the RB tumor suppressor gene.
Which cellular function is impaired by loss of this gene?
, A. DNA repair mechanisms
B. Cell cycle checkpoint control (G1/S transition)
C. Apoptosis initiation
D. Telomerase activation
Correct Answer: B. Cell cycle checkpoint control (G1/S transition) [CORRECT]
Rationale: The Rb protein normally binds E2F transcription factors, preventing G1/S
progression. Loss of Rb allows uncontrolled cell cycle entry. p53 regulates DNA damage
checkpoints; telomerase is an oncogene target. REVIEW NOTE: Rb = "gatekeeper" of
G1/S; p53 = "guardian of the genome."
Q8. A patient develops paraneoplastic syndrome with hypercalcemia from a lung
squamous cell carcinoma. Which substance is most likely secreted by the tumor?
A. Adrenocorticotropic hormone (ACTH)
B. Parathyroid hormone-related peptide (PTHrP)
C. Antidiuretic hormone (ADH)
D. Erythropoietin
Correct Answer: B. Parathyroid hormone-related peptide (PTHrP) [CORRECT]
Rationale: PTHrP mimics PTH, causing humoral hypercalcemia of malignancy—most
common with squamous cell carcinomas (lung, head/neck, cervix, esophagus). It
activates bone resorption and renal calcium reabsorption. REVIEW NOTE: PTHrP is the
most common cause of malignancy-related hypercalcemia.
Q9. A patient with familial adenomatous polyposis (FAP) has a mutation in the APC
gene. Which cellular pathway is disrupted?
A. p53-mediated apoptosis
B. Wnt/β-catenin signaling pathway
C. Ras/MAPK signaling
D. HER2/neu receptor signaling
Correct Answer: B. Wnt/β-catenin signaling pathway [CORRECT]
