Master Rigger / Special Rigger Exam 2026
Practice Test: 100 Questions with Correct
Answers & Rationales | PDF
Q1. A master rigger is planning a lift using a sling angle of 60
degrees from horizontal. The load weighs 10,000 lbs and is
being lifted by a two-leg bridle sling. What is the tension in
each leg of the sling?
A) 5,000 lbs
B) 5,774 lbs
C) 6,667 lbs
D) 10,000 lbs
Answer: B
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Rationale: Tension per leg = (Load / number of legs) × (1 / sin
of angle from horizontal). For 60°, sin 60° = 0.866. (10,000 /
2) × (.866) = 5,000 × 1.155 = 5,774 lbs per leg .
Q2. What is the sling angle factor (multiplier) for a sling angle
of 45 degrees from horizontal?
A) 1.00
B) 1.15
C) 1.41
D) 2.00
Answer: C
Rationale: The sling angle factor for 45° is 1.41. As the angle
decreases, the tension multiplier increases significantly. For a 30°
angle, the multiplier is 2.0, meaning the sling experiences double
the load weight .
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Q3. A 5,000 lb load is being lifted with two slings at a 30-
degree angle from horizontal. What is the tension in each
sling?
A) 2,500 lbs
B) 3,535 lbs
C) 5,000 lbs
D) 10,000 lbs
Answer: C
Rationale: At 30°, the angle factor is 2.0. (5,) × 2.0 =
2,500 × 2 = 5,000 lbs per leg. The slings are effectively
carrying the full load weight each due to the shallow angle .
Q4. A load weighs 8,000 lbs and is being lifted by a single
vertical sling. What is the tension in the sling?
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A) 4,000 lbs
B) 6,928 lbs
C) 8,000 lbs
D) 11,314 lbs
Answer: C
Rationale: In a vertical lift (90° from horizontal), the sling angle
factor is 1.0. Tension = Load / number of legs × 1.0 = 8,000
lbs.
Q5. For a two-leg bridle with legs at 60° from horizontal,
what percentage of the load weight is each leg carrying?
A) 50%
B) 57.7%
C) 86.6%
D) 100%