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CHEM 103 EXAM Questions and Answers-Portage Learning Latest Versions Top Rated

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CHEM 103 EXAM Questions and Answers-Portage Learning Latest Versions Top Rated

Institution
CHEM 103.
Course
CHEM 103.

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CHEM 103 EXAM Questions and
Answers-Portage Learning Latest
Versions Top Rated
MODULE 1 EXAM
Question 1
Click this link to access the Periodic table This may be helpful throughout the exam.


1. Convert 845.3 to exponential form and explain your answer.
2. Convert 3.21 x 10-5 to ordinary form and explain your answer.


1. Convert 845.3 = larger than 1 = positive exponent, move decimal 2 places = 8.453 x
102
2. Convert 3.21 x 10-5 = negative exponent = smaller than 1, move decimal 5 places =
0.0000321

Question 2
Click this link to access the Periodic table This may be helpful throughout the exam.




Using the following information, do the conversions shown below, showing all work:


1 ft = 12 inches 1 pound = 16 oz 1 gallon = 4 quarts

1 mile = 5280 feet 1 ton = 2000 pounds 1 quart = 2 pints
kilo (= 1000) milli (= 1/1000) centi (=
1/100) deci (= 1/10)


1. 24.6 grams = ? kg

2. 6.3 ft = ? inches


1. 24.6 grams x 1 kg / 1000 g = 0.0246 kg

2. 6.3 ft x 12 in / 1 ft = 75.6 inches

please always use the correct units in your final answer

,Question 3

,Click this link to access the Periodic table This may be helpful throughout the exam.




Do the conversions shown below, showing all work:

1. 28oC = ? oK
2. 158oF = ? oC
3. 343oK = ? oF

1. 28oC + 273 = 301 oK o C → oK (make larger)
+273
2. 158oF - 32 ÷ 1.8 = 70 oC o F → oC (make smaller)
-32 ÷1.8
3. 343oK - 273 = 70 oC x 1.8 + 32 = 158 oF o K → oC → oF

Question 4
Click this link to access the Periodic table This may be helpful throughout the exam.




Be sure to show the correct number of significant figures in each calculation.


1. Show the calculation of the mass of a 18.6 ml sample of freon with density
of 1.49 g/ml

2. Show the calculation of the density of crude oil if 26.3 g occupies 30.5
ml.

1. M = D x V = 1.49 x 18.6 = 27.7 g
2. D = M / V = 26..5 = 0.862 g/ml

Question 5
Click this link to access the Periodic table This may be helpful throughout the exam.




1. 3.0600 contains ? significant figures.
2. 0.0151 contains ? significant figures.

, 3. 3.0600 ÷ 0.0151 = ? (give answer to correct number of significant figures)


1. 3.0600 contains 5 significant figures.

2. 0.0151 contains 3 significant figures.
3. 3.0600 ÷ 0.0151 = 202.649 = 203 (to 3 significant figures for 0.0151)


Question 6
Click this link to access the Periodic table This may be helpful throughout the exam.


Classify each of the following as an element, compound, solution or
heterogeneous mixture and explain your answer.
1. Coca cola

2. Calcium
3. Chili


1. Coca cola - is not on (not element) - no element names (not compound)
appears to be one substance = Solution

2. Calcium - is on = Element

3. Chili - is not on (not element) - no element names (not compound)
appears as more than one substance (meat, beans,
sauce) = Hetero Mix

Question 7
Click this link to access the Periodic table This may be helpful throughout the exam.




Classify each of the following as a chemical change or a physical change


1. Charcoal burns
2. Mixing cake batter with water

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Institution
CHEM 103.
Course
CHEM 103.

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