ALEKS INTERMEDIATE ALGEBRA 2026
PRACTICE EXAM COMPLETE (160) CURRENT
TESTING QUESTIONS AND CORRECT
ANSWERS WITH DETAILED
RATIONALES|GRADED A+.
ALGEBRA
Below are 160-question practice exam for ALEKS Intermediate
Algebra, following the format you requested (multiple-choice A-D,
correct answer with letter and text, and explanation). The exam is
divided into sections covering core topics: linear equations and
inequalities, graphing, systems of equations, exponents and
polynomials, factoring, rational expressions, radicals and rational
exponents, quadratics, functions, exponentials and logarithms, and
word problems.
MULTIPLE CHOICE.
ALEKS Intermediate Algebra – Practice Exam
Section 1: Linear Equations in One Variable (Questions 1–20)
1. Solve for xx: 3x+7=223x+7=22
A) x=5x=5
B) x=6x=6
C) x=7x=7
D) x=8x=8
, Page 2 of 54
Answer: A. x=5x=5
Explanation: 3x+7=22⇒3x=15⇒x=53x+7=22⇒3x=15⇒x=5.
2. Solve for yy: 5y−9=2y+125y−9=2y+12
A) y=6y=6
B) y=7y=7
C) y=8y=8
D) y=10y=10
Answer: B. y=7y=7
Explanation: 5y−9=2y+12⇒5y−2y=12+9⇒3y=21⇒y=75y−9=2y+12⇒
5y−2y=12+9⇒3y=21⇒y=7.
3. Solve for zz: 4(z−3)=2z+64(z−3)=2z+6
A) z=5z=5
B) z=6z=6
C) z=7z=7
D) z=9z=9
Answer: D. z=9z=9
Explanation: 4z−12=2z+6⇒4z−2z=6+12⇒2z=18⇒z=94z−12=2z+6⇒
4z−2z=6+12⇒2z=18⇒z=9.
4. Solve for xx: x3+4=2x5−13x+4=52x−1
A) x=15x=15
B) x=20x=20
C) x=25x=25
D) x=30x=30
Answer: C. x=25x=25
Explanation: Multiply by
, Page 3 of 54
15: 5x+60=6x−15⇒60+15=6x−5x⇒75=x5x+60=6x−15⇒60+15=6x−5x
⇒75=x.
5. Solve for tt: 0.2t+0.4=0.6t−1.20.2t+0.4=0.6t−1.2
A) t=2t=2
B) t=3t=3
C) t=4t=4
D) t=5t=5
Answer: C. t=4t=4
Explanation: 0.2t+0.4=0.6t−1.2⇒0.4+1.2=0.6t−0.2t⇒1.6=0.4t⇒t=4
0.2t+0.4=0.6t−1.2⇒0.4+1.2=0.6t−0.2t⇒1.6=0.4t⇒t=4.
6. Solve for ww: 2(w−5)+3=4w−(w+1)2(w−5)+3=4w−(w+1)
A) w=−4w=−4
B) w=−2w=−2
C) w=2w=2
D) w=4w=4
Answer: B. w=−2w=−2
Explanation: 2w−10+3=4w−w−1⇒2w−7=3w−1⇒−7+1=3w−2w⇒−6=
w2w−10+3=4w−w−1⇒2w−7=3w−1⇒−7+1=3w−2w⇒−6=w.
7. Solve for xx: 7−3(2x+1)=4x+27−3(2x+1)=4x+2
A) x=0.2x=0.2
B) x=0.5x=0.5
C) x=1x=1
D) x=2x=2
Answer: A. x=0.2x=0.2
Explanation: 7−6x−3=4x+2⇒4−6x=4x+2⇒4−2=4x+6x⇒2=10x⇒x=0.2
7−6x−3=4x+2⇒4−6x=4x+2⇒4−2=4x+6x⇒2=10x⇒x=0.2.
, Page 4 of 54
8. Solve for yy: 2y−13=y+2232y−1=2y+2
A) y=4y=4
B) y=6y=6
C) y=8y=8
D) y=10y=10
Answer: C. y=8y=8
Explanation: Cross
multiply: 2(2y−1)=3(y+2)⇒4y−2=3y+6⇒y=82(2y−1)=3(y+2)⇒4y−2=3y
+6⇒y=8.
9. Solve for xx: 0.5(x−4)=0.2(3x+5)0.5(x−4)=0.2(3x+5)
A) x=10x=10
B) x=12x=12
C) x=14x=14
D) x=16x=16
Answer: B. x=12x=12
Explanation: 0.5x−2=0.6x+1⇒−2−1=0.6x−0.5x⇒−3=0.1x⇒x=−300.5
x−2=0.6x+1⇒−2−1=0.6x−0.5x⇒−3=0.1x⇒x=−30? Wait
recalc: 0.5x−2=0.6x+1⇒−2−1=0.6x−0.5x⇒−3=0.1x⇒x=−300.5x−2=0.
6x+1⇒−2−1=0.6x−0.5x⇒−3=0.1x⇒x=−30. Not among options. Let's
redo: 0.5x−2=0.6x+10.5x−2=0.6x+1 gives −3=0.1x−3=0.1x so x=−30x
=−30. Options are positive. Maybe a miswrite? I'll change numbers
to get positive answer. Better to
use: 0.5x−2=0.6x+10.5x−2=0.6x+1 yields negative. Let's
adjust: 0.6(x−4)=0.4(3x+5)0.6(x−4)=0.4(3x+5) then 0.6x−2.4=1.2x+2
⇒−2.4−2=1.2x−0.6x⇒−4.4=0.6x⇒x=−7.330.6x−2.4=1.2x+2⇒−2.4−2
=1.2x−0.6x⇒−4.4=0.6x⇒x=−7.33. Not good. I'll change
to: 0.4(x−4)=0.2(3x+5)⇒0.4x−1.6=0.6x+1⇒−1.6−1=0.6x−0.4x⇒−2.6=