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PRECALCULUS FINAL EXAMss

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PRECALCULUS FINAL EXAMss

Institution
PRECALCULUS
Course
PRECALCULUS

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PRECALCULUS FINAL EXAMss

1. Simplify: 𝟑𝒙𝟐 + 𝟓𝒙𝟐

A. 8𝑥

B. 8𝑥 2

C. 15𝑥 4

D. 2𝑥 2

Answer: B

Rationale: Like terms have the same variable and exponent. Since both terms contain 𝑥 2 , add the
coefficients: 3 + 5 = 8. Therefore, the simplified expression is 8𝑥 2 .



2. Solve: 𝟐𝒙 + 𝟓 = 𝟏𝟕

A. 4

B. 5

C. 6

D. 7

Answer: C

Rationale: Subtract 5 from both sides to obtain 2𝑥 = 12. Divide by 2 to get 𝑥 = 6.



3. Factor: 𝒙𝟐 − 𝟗

A. (𝑥 − 9)(𝑥 + 1)

B. (𝑥 − 3)2

C. (𝑥 − 3)(𝑥 + 3)

D. Prime

Answer: C

Rationale: This is a difference of squares. Use the formula 𝑎2 − 𝑏 2 = (𝑎 − 𝑏)(𝑎 + 𝑏).



4. Evaluate: 𝒇(𝒙) = 𝟐𝒙 + 𝟑, find 𝒇(𝟒)

A. 8

B. 10

C. 11

,D. 13

Answer: C

Rationale: Substitute 𝑥 = 4: 2(4) + 3 = 8 + 3 = 11.



5. Find the slope between (𝟏, 𝟐)and (𝟒, 𝟖)

A. 2

B. 3

C. 4

D. 6

Answer: A

Rationale: Use the slope formula:
𝑦2 − 𝑦1
𝑚=
𝑥2 − 𝑥1
8−2 6
Substituting gives = = 2.
4−1 3




6. Solve: 𝒙𝟐 = 𝟒𝟗

A. 7

B. -7

C. ±7

D. 14

Answer: C

Rationale: Both 7 and -7 square to 49, so the solutions are ±7.



7. Evaluate 𝟑𝟒

A. 12

B. 27

C. 64

D. 81

Answer: D

Rationale: 34 = 3 × 3 × 3 × 3 = 81.

, 8. Simplify: √𝟖𝟏

A. 7

B. 8

C. 9

D. 10

Answer: C

Rationale: The principal square root of 81 is 9.



9. Solve: 𝒙𝟐 − 𝟏𝟔 = 𝟎

A. ±4

B. ±8

C. 4

D. -4

Answer: A

Rationale: Add 16 to both sides to get 𝑥 2 = 16, then take square roots.



10. What is the y-intercept of 𝒚 = 𝟑𝒙 − 𝟐?

A. 3

B. -2

C. 1

D. 2

Answer: B

Rationale: In slope-intercept form 𝑦 = 𝑚𝑥 + 𝑏, the y-intercept is 𝑏. Here, 𝑏 = −2.


𝟏
11. Find the domain of 𝒇(𝒙) =
𝒙−𝟐

A. All real numbers

B. 𝑥 ≠ 2

C. 𝑥 > 2

D. 𝑥 < 2

Answer: B

Rationale: The denominator cannot equal zero. Therefore, 𝑥 − 2 ≠ 0, so 𝑥 ≠ 2.

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Institution
PRECALCULUS
Course
PRECALCULUS

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