HEM134 C002 SPRING 2026 Digital Colligative Properties
- Beyond Labs Actual Written Exam with Answers and
Rationales GRADE A+ COMPLETE Q&A ALREADY
GRADED A+
EXAM OVERVIEW
This examination covers the Colligative Properties Lab for CHEM134 C002 Spring 2026 using the
Beyond Labz virtual laboratory platform . Colligative properties are physical properties of
solutions that depend on the number of solute particles present, not their chemical identity .
This exam includes the four main colligative properties: vapor pressure lowering, boiling point
elevation, freezing point depression, and osmotic pressure .
SECTION A: MULTIPLE CHOICE QUESTIONS (25 Points)
Q1. Which of the following is NOT a colligative property?
A) Vapor pressure lowering
B) Boiling point elevation
C) Color intensity
D) Freezing point depression
E) Osmotic pressure
Answer: C) Color intensity
Rationale: Colligative properties depend only on the number of solute particles in solution, not
their chemical nature. Color intensity depends on the specific chemical identity of the solute
and varies even when particle numbers are identical .
Q2. The addition of a non-volatile solute to a solvent causes the vapor pressure to:
A) Increase
B) Decrease
C) Remain the same
D) Double
E) Become zero
, Answer: B) Decrease
Rationale: Adding a non-volatile solute reduces the number of solvent molecules at the
surface, decreasing the rate of evaporation. This results in lower vapor pressure above the
solution compared to the pure solvent .
Q3. Which aqueous solution would have the HIGHEST boiling point?
A) 0.1 m NaCl
B) 0.1 m CaCl₂
C) 0.1 m C₆H₁₂O₆ (glucose)
D) 0.1 m KNO₃
E) 0.1 m Al(NO₃)₃
Answer: E) 0.1 m Al(NO₃)₃
Rationale: For electrolytes, the boiling point elevation depends on the van't Hoff factor (i)—the
number of ions produced per formula unit. Al(NO₃)₃ dissociates into 4 ions (Al³⁺ + 3NO₃⁻),
producing the most particles and thus the greatest boiling point elevation .
Solute Dissociation i (van't Hoff factor)
Al(NO₃)₃ Al³⁺ + 3NO₃⁻ 4
CaCl₂ Ca²⁺ + 2Cl⁻ 3
NaCl Na⁺ + Cl⁻ 2
KNO₃ K⁺ + NO₃⁻ 2
C₆H₁₂O₆ Non-electrolyte 1
Q4. A 1.0 m aqueous solution of which solute would have the LOWEST freezing point?
A) Sucrose (C₁₂H₂₂O₁₁)
B) Methanol (CH₃OH)
- Beyond Labs Actual Written Exam with Answers and
Rationales GRADE A+ COMPLETE Q&A ALREADY
GRADED A+
EXAM OVERVIEW
This examination covers the Colligative Properties Lab for CHEM134 C002 Spring 2026 using the
Beyond Labz virtual laboratory platform . Colligative properties are physical properties of
solutions that depend on the number of solute particles present, not their chemical identity .
This exam includes the four main colligative properties: vapor pressure lowering, boiling point
elevation, freezing point depression, and osmotic pressure .
SECTION A: MULTIPLE CHOICE QUESTIONS (25 Points)
Q1. Which of the following is NOT a colligative property?
A) Vapor pressure lowering
B) Boiling point elevation
C) Color intensity
D) Freezing point depression
E) Osmotic pressure
Answer: C) Color intensity
Rationale: Colligative properties depend only on the number of solute particles in solution, not
their chemical nature. Color intensity depends on the specific chemical identity of the solute
and varies even when particle numbers are identical .
Q2. The addition of a non-volatile solute to a solvent causes the vapor pressure to:
A) Increase
B) Decrease
C) Remain the same
D) Double
E) Become zero
, Answer: B) Decrease
Rationale: Adding a non-volatile solute reduces the number of solvent molecules at the
surface, decreasing the rate of evaporation. This results in lower vapor pressure above the
solution compared to the pure solvent .
Q3. Which aqueous solution would have the HIGHEST boiling point?
A) 0.1 m NaCl
B) 0.1 m CaCl₂
C) 0.1 m C₆H₁₂O₆ (glucose)
D) 0.1 m KNO₃
E) 0.1 m Al(NO₃)₃
Answer: E) 0.1 m Al(NO₃)₃
Rationale: For electrolytes, the boiling point elevation depends on the van't Hoff factor (i)—the
number of ions produced per formula unit. Al(NO₃)₃ dissociates into 4 ions (Al³⁺ + 3NO₃⁻),
producing the most particles and thus the greatest boiling point elevation .
Solute Dissociation i (van't Hoff factor)
Al(NO₃)₃ Al³⁺ + 3NO₃⁻ 4
CaCl₂ Ca²⁺ + 2Cl⁻ 3
NaCl Na⁺ + Cl⁻ 2
KNO₃ K⁺ + NO₃⁻ 2
C₆H₁₂O₆ Non-electrolyte 1
Q4. A 1.0 m aqueous solution of which solute would have the LOWEST freezing point?
A) Sucrose (C₁₂H₂₂O₁₁)
B) Methanol (CH₃OH)
