WGU D027 Advanced Pathopharmacological
Foundations Exam Prep Document 2026/2027 |
Advanced Practice Nursing | 60 Verified
Questions with Detailed Rationales
SECTION 1: CELLULAR ADAPTATION & INJURY
(Questions 1-10)
Q1. A patient with long-standing hypertension presents with left
ventricular hypertrophy on echocardiogram. Which type of cellular
adaptation best describes this finding?
A) Hyperplasia (increase in cell number)
B) Hypertrophy (increase in cell size)
C) Atrophy (decrease in cell size)
D) Metaplasia (change in cell type)
Correct Answer: B
Rationale: Hypertrophy is an increase in individual cell size resulting in
enlargement of the organ or tissue. Cardiac muscle cells cannot divide, so
they respond to increased workload (such as chronic hypertension) by
enlarging existing myocytes rather than proliferating. This adaptation allows
the heart to generate greater contractile force against increased afterload.
Initially compensatory, sustained hypertrophy can lead to heart failure.
Q2. A patient with chronic GERD has been found to have Barrett's
esophagus on endoscopy. The normal squamous epithelial cells of
the esophagus have been replaced by columnar epithelial cells. This
cellular change is called:
A) Dysplasia (abnormal cell size/shape/organization)
B) Hyperplasia (increased cell number)
C) Hypertrophy (increased cell size)
D) Metaplasia (reversible change of one cell type to another)
Correct Answer: D
,Rationale: Metaplasia is a reversible change in which one differentiated cell
type is replaced by another cell type better suited to withstand an adverse
environment. In Barrett's esophagus, chronic acid exposure triggers
replacement of the normal stratified squamous epithelium with intestinal-
type columnar epithelium. While protective in the short term, this
metaplastic change is associated with increased risk of dysplasia and
adenocarcinoma.
Q3. A pathologist examining a myocardial tissue sample notes that
the cardiac cells have swollen, pale cytoplasm with loss of nuclei
and preserved tissue architecture. This pattern of cell death is
characteristic of:
A) Liquefactive necrosis
B) Coagulative necrosis
C) Caseous necrosis
D) Fat necrosis
Correct Answer: B
Rationale: Coagulative necrosis is the most common pattern of necrosis,
typically resulting from ischemia/hypoxia in solid organs such as the heart,
kidney, and liver. It is characterized by denaturation of structural proteins,
preservation of tissue architecture for several days, and loss of nuclei.
Liquefactive necrosis (A) occurs in the brain and with bacterial abscesses;
caseous necrosis (C) is seen in tuberculosis; fat necrosis (D) occurs in the
breast and pancreas.
Q4. A patient with a brain injury from a cerebral infarction
undergoes imaging that shows the affected area has been replaced
by a cystic space filled with fluid and debris. This pattern of cell
death is called:
A) Coagulative necrosis
B) Caseous necrosis
C) Liquefactive necrosis
D) Fat necrosis
Correct Answer: C
Rationale: Liquefactive necrosis occurs when enzymatic digestion of dead
cells produces a viscous liquid mass. This pattern is characteristic of hypoxic
death of central nervous system tissue (cerebral infarction) as well as
bacterial abscesses. The cellular debris is digested by hydrolytic enzymes
from neutrophils and resident microglia, resulting in cyst formation.
, Q5. A 70-year-old male with Alzheimer's disease is found to have
significant brain atrophy at autopsy. Which of the following best
describes the process of atrophy?
A) Decreased cell size resulting from decreased workload, denervation,
ischemia, or endocrine stimulation
B) Increased cell size due to increased functional demand
C) Increased cell number due to hormonal stimulation
D) Replacement of one cell type with another
Correct Answer: A
Rationale: Atrophy is a decrease in cell size that results in shrinkage of the
affected organ or tissue. Causes include decreased workload (disuse
atrophy), denervation (neurogenic atrophy), ischemia, inadequate nutrition,
loss of endocrine stimulation, and aging. In Alzheimer's disease, progressive
neuronal loss and shrinkage of brain tissue result in characteristic gyral
atrophy.
Q6. A tissue sample from a patient with chronic inflammation shows
replacement of normal ciliated pseudostratified columnar
epithelium with stratified squamous epithelium in the bronchi. This
represents which type of cellular adaptation?
A) Dysplasia
B) Metaplasia
C) Anaplasia
D) Hyperplasia
Correct Answer: B
Rationale: Metaplasia is a reversible change in which one cell type is
replaced by another cell type that is better able to withstand the adverse
environment. In the respiratory tract, chronic irritation (such as smoking)
causes replacement of the normal ciliated columnar epithelium with
stratified squamous epithelium. While this change provides protection, it also
results in loss of protective functions such as mucociliary clearance.
Q7. A woman undergoing endometrial biopsy for abnormal uterine
bleeding is found to have an increased number of endometrial
glands. The cells themselves are normal in size and shape. This
finding best describes:
A) Hypertrophy
B) Hyperplasia
C) Metaplasia
D) Dysplasia
Foundations Exam Prep Document 2026/2027 |
Advanced Practice Nursing | 60 Verified
Questions with Detailed Rationales
SECTION 1: CELLULAR ADAPTATION & INJURY
(Questions 1-10)
Q1. A patient with long-standing hypertension presents with left
ventricular hypertrophy on echocardiogram. Which type of cellular
adaptation best describes this finding?
A) Hyperplasia (increase in cell number)
B) Hypertrophy (increase in cell size)
C) Atrophy (decrease in cell size)
D) Metaplasia (change in cell type)
Correct Answer: B
Rationale: Hypertrophy is an increase in individual cell size resulting in
enlargement of the organ or tissue. Cardiac muscle cells cannot divide, so
they respond to increased workload (such as chronic hypertension) by
enlarging existing myocytes rather than proliferating. This adaptation allows
the heart to generate greater contractile force against increased afterload.
Initially compensatory, sustained hypertrophy can lead to heart failure.
Q2. A patient with chronic GERD has been found to have Barrett's
esophagus on endoscopy. The normal squamous epithelial cells of
the esophagus have been replaced by columnar epithelial cells. This
cellular change is called:
A) Dysplasia (abnormal cell size/shape/organization)
B) Hyperplasia (increased cell number)
C) Hypertrophy (increased cell size)
D) Metaplasia (reversible change of one cell type to another)
Correct Answer: D
,Rationale: Metaplasia is a reversible change in which one differentiated cell
type is replaced by another cell type better suited to withstand an adverse
environment. In Barrett's esophagus, chronic acid exposure triggers
replacement of the normal stratified squamous epithelium with intestinal-
type columnar epithelium. While protective in the short term, this
metaplastic change is associated with increased risk of dysplasia and
adenocarcinoma.
Q3. A pathologist examining a myocardial tissue sample notes that
the cardiac cells have swollen, pale cytoplasm with loss of nuclei
and preserved tissue architecture. This pattern of cell death is
characteristic of:
A) Liquefactive necrosis
B) Coagulative necrosis
C) Caseous necrosis
D) Fat necrosis
Correct Answer: B
Rationale: Coagulative necrosis is the most common pattern of necrosis,
typically resulting from ischemia/hypoxia in solid organs such as the heart,
kidney, and liver. It is characterized by denaturation of structural proteins,
preservation of tissue architecture for several days, and loss of nuclei.
Liquefactive necrosis (A) occurs in the brain and with bacterial abscesses;
caseous necrosis (C) is seen in tuberculosis; fat necrosis (D) occurs in the
breast and pancreas.
Q4. A patient with a brain injury from a cerebral infarction
undergoes imaging that shows the affected area has been replaced
by a cystic space filled with fluid and debris. This pattern of cell
death is called:
A) Coagulative necrosis
B) Caseous necrosis
C) Liquefactive necrosis
D) Fat necrosis
Correct Answer: C
Rationale: Liquefactive necrosis occurs when enzymatic digestion of dead
cells produces a viscous liquid mass. This pattern is characteristic of hypoxic
death of central nervous system tissue (cerebral infarction) as well as
bacterial abscesses. The cellular debris is digested by hydrolytic enzymes
from neutrophils and resident microglia, resulting in cyst formation.
, Q5. A 70-year-old male with Alzheimer's disease is found to have
significant brain atrophy at autopsy. Which of the following best
describes the process of atrophy?
A) Decreased cell size resulting from decreased workload, denervation,
ischemia, or endocrine stimulation
B) Increased cell size due to increased functional demand
C) Increased cell number due to hormonal stimulation
D) Replacement of one cell type with another
Correct Answer: A
Rationale: Atrophy is a decrease in cell size that results in shrinkage of the
affected organ or tissue. Causes include decreased workload (disuse
atrophy), denervation (neurogenic atrophy), ischemia, inadequate nutrition,
loss of endocrine stimulation, and aging. In Alzheimer's disease, progressive
neuronal loss and shrinkage of brain tissue result in characteristic gyral
atrophy.
Q6. A tissue sample from a patient with chronic inflammation shows
replacement of normal ciliated pseudostratified columnar
epithelium with stratified squamous epithelium in the bronchi. This
represents which type of cellular adaptation?
A) Dysplasia
B) Metaplasia
C) Anaplasia
D) Hyperplasia
Correct Answer: B
Rationale: Metaplasia is a reversible change in which one cell type is
replaced by another cell type that is better able to withstand the adverse
environment. In the respiratory tract, chronic irritation (such as smoking)
causes replacement of the normal ciliated columnar epithelium with
stratified squamous epithelium. While this change provides protection, it also
results in loss of protective functions such as mucociliary clearance.
Q7. A woman undergoing endometrial biopsy for abnormal uterine
bleeding is found to have an increased number of endometrial
glands. The cells themselves are normal in size and shape. This
finding best describes:
A) Hypertrophy
B) Hyperplasia
C) Metaplasia
D) Dysplasia
