JEE PHYSICS
COMPREHENSIVE FORMUL A HANDBOOK
Ebook Edition
Compiled from structured high-yield revision notes
JEE Physics Formula Handbook 1
, Chapter 1: Electrostatics ( स्थिरवैद्यु तिकी)
1. Basic Principles & Coulomb's Law
• Quantization of Charge: q = ±ne
• Coulomb's Force: F = (πε₀) · (q₁q₂ / r²)
• Position of Equilibrium (x):
x = √q₁ / (√q₁ + √q₂) · r
• For Equilibrium of third charge: q = -q₁q₂ / (√q₁ + √q₂)²
• Note: विद्युत क्षेत्र एक स दिश रा श है (Electric Field is a vector quantity).
2. Charge Densities
Linear Charge Density (λ) Surface Charge Density (σ) Volume Charge Density (ρ)
λ = q / l = dq / dl σ = q / A = q / πr² ρ = q / V = q / ((4/3)πr³)
3. Electric Field Intensity due to Continuous Charge Distributions
A. Uniformly Charged Ring (समरूप आवे शित वलय)
• At an Axial Point (अक्षीय स्थि ति पर):
Eअक्षीय = Kqx / (R² + x²)3/2 [यहाँ q = λ · 2πR]
◦ If x << R: E
अक्षीय = Kqx / R³ = λx / 2ε₀R²
• At the Center (केन्द्र पर): E = 0
• Maximum Electric Field Intensity (अ धिकतिम वद्युति क्षेत्र की तिीव्रतिा):
x = ± R / √2
B. Ring Segment / Arc (वलय का खण्ड)
E = (2Kλ / R) · sin(α / 2) [यहाँ λ = q / (Rα)]
JEE Physics Formula Handbook 2
COMPREHENSIVE FORMUL A HANDBOOK
Ebook Edition
Compiled from structured high-yield revision notes
JEE Physics Formula Handbook 1
, Chapter 1: Electrostatics ( स्थिरवैद्यु तिकी)
1. Basic Principles & Coulomb's Law
• Quantization of Charge: q = ±ne
• Coulomb's Force: F = (πε₀) · (q₁q₂ / r²)
• Position of Equilibrium (x):
x = √q₁ / (√q₁ + √q₂) · r
• For Equilibrium of third charge: q = -q₁q₂ / (√q₁ + √q₂)²
• Note: विद्युत क्षेत्र एक स दिश रा श है (Electric Field is a vector quantity).
2. Charge Densities
Linear Charge Density (λ) Surface Charge Density (σ) Volume Charge Density (ρ)
λ = q / l = dq / dl σ = q / A = q / πr² ρ = q / V = q / ((4/3)πr³)
3. Electric Field Intensity due to Continuous Charge Distributions
A. Uniformly Charged Ring (समरूप आवे शित वलय)
• At an Axial Point (अक्षीय स्थि ति पर):
Eअक्षीय = Kqx / (R² + x²)3/2 [यहाँ q = λ · 2πR]
◦ If x << R: E
अक्षीय = Kqx / R³ = λx / 2ε₀R²
• At the Center (केन्द्र पर): E = 0
• Maximum Electric Field Intensity (अ धिकतिम वद्युति क्षेत्र की तिीव्रतिा):
x = ± R / √2
B. Ring Segment / Arc (वलय का खण्ड)
E = (2Kλ / R) · sin(α / 2) [यहाँ λ = q / (Rα)]
JEE Physics Formula Handbook 2