DSRT 734-ELRE 734 MIDTERM STUDY GUIDE. Questions and Answers

DSRT 734-ELRE 734 MIDTERM STUDY GUIDE. Questions and Answers ELRE/OL 734 MIDTERM STUDY GUIDE A superintendent wanted to know if there was a difference among staff retention at elementary, middle, and high schools in her district. Here are the data: Elementa Middle Secondar ry y 17 17 10 15 12 12 20 10 14 12 8 16 14 5 18 15 20 10 What test should she conduct to determine if there is a difference among the levels? What do the results mean? Please write up your results according to the handbook and describe any follow up or additional statistical analysis, if necessary. as we fail to reject Ho and conclude that there was a difference among staff retention at elementary, middle, and high schools in her district Explanation: given that, level of significance, alpha = 0.05 degrees of freedom treatment = k - 1 = 3 - 1 = 2 degrees of freedom error = n - k = 18 - 3 = 15 degrees of freedom total F( k-1,n - k,) at 0.05 is = f crit = 3.68232 & reject Ho, if fo 3.68232 ELRE/OL 734 MIDTERM STUDY GUIDE null, Ho: μ1 =μ2 =μ3 alternate, H1: at least one mean is different from each other from the table calculations, grand mean = G / N = 13.61111 sum of squares of total = Σ ( Xi - grand mean)^2 = (17-13.61111)^2 + (15- 13.61111)^2 + (20-13.61111)^2 + ......... & so on = 286.27778 sum of squares of error = Σ (Xi - M of Xi ) ^2 =,(17-14.71429)^2 + (15- 14.71429)^2 + (20-14.71429)^2 + ......... & so on = 214.7 sum of squares treatments = sum of squares of total - sum of squares of error sum of squares treatments = 71.64921 mean square treatments = sum of squares of treatments / df treatment = 71.64921/2 = 35.8246 mean square error = sum of squares of error / df within = 214.7/15 = 14.30857 fo = mean squares of treatments / mean squares of error = 35.8246/14.30857 = 2.50372 make decision we got |fo| = 2.50372 & |f crit| =3.68232 hence value of |fo| |f crit|and here we fail to reject Ho p-value : ( p = 2.50372 ) = 0.11528 Assume level of significance- alpha = 0.05 A researcher wanted to know if there was a significant difference in cyber security breaches between cities on two different continents. What test should he conduct to determine if there is a significant difference in cyber security breaches between the continents? Write up the results and determine what do the results mean? Here is the data set: Asia Ho: u1 - u2 =0 H1: u1 - u2 ≠ 0 test statistic: 1.6075 critical value: -2.306 , 2.306 Europe 40 25 52 35 63 20 70 18 25 19 19 14 11 9