Biochemistry Readiness Check
The 2nd OA Readiness Check is designed to give you additional practice with
new assessment-style questions to help prepare for success on the OA. Thus,
please try to mimic exam-like conditions by taking the test in one <2 hr sitting
without any study aids apart from your whiteboard/scrap paper. Note: Responses
cannot be edited. You will be able to see the results and feedback after
submitting the test. A score of 70% is required for OA approval. If you score
below 70%, please speak with a Course Instructor via appointment to discuss
next steps prior to retaking this test.
Points:
54/67
1
What is the complementary sequence to 3’ ATG CGA ATA 5’?
(1/1 Points)
3’ TAT TCG CAT 5’
The correct answer is 3' TAT TCG CAT 5'. Remember complementary means “Matching
or Pairing” You have to remember to pay attention to your numbers as well as your
letters (A-T, G-C, 5'-3'). The correct answer is 3’ ATG CGA ATA 5’ (original sequence) 5’
TAC GCT TAT 3’ (complementary sequence) But we asked for it in the 3’ direction, so
mirror answer to give correct answer: 3’ TAT TCG CAT 5’
3’ TAC GCT TAT 5’
3’ GAT AGC ATA 5’
5’ ATA AGC GTA 3’
2
Which amino acid sequence would result from this Coding DNA strand?
3’ ATG CAG ATA 5’?
(0/1 Points)
Tyr Val Tyr
The correct answer is Ile Asp Val. We are starting at the coding strand, and have to
remember the relationship between coding DNA and mRNA. These two strands are non-
complementary and parallel. So we copy the coding strand , change T ---> U, and then
write the mRNA sequence: 3’ ATG CAG ATA 5’ coding 3’ AUG CAG AUA 5’ mRNA Mirror
by changing orientation: 5’ AUA GAC GUA 3’ Read chart Ile Asp Val (chart is in direction
of 5' ---> 3') If you chose Tyr Val Tyr, this answer is incorrect because this is the amino
acid sequence that results from the mRNA 5' UAC GUC UAU 3' which would have been
complementary to the given coding strand. Coding DNA is non-complementary and
parallel to mRNA.
Ile Gln Ile
, Ile Asp Val
Leu His Lys
3
Which amino acid sequence would be made from this template DNA
strand? 5’ TAT TAC CGA 3’?
(1/1 Points)
Tyr Tyr Arg
Ile Met Ala
Ser Val Ile
The correct answer is Ser Val Ile because 5’ TAT TAC CGA 3’ template is complementary
and antiparallel so 3’ AUA AUG GCU 5’ but it is in the wrong orientation, so mirror 5’
UCG GUA AUA 3’ and read the chart Ser Val Ile
Ser His Gln
4
Which of the following are the correct components for a PCR reaction?
(1/1 Points)
dNTPs, Primer, RNA Polymerase, template RNA
dNTPs, Primer, DNA Polymerase, template DNA
The correct answer is dNTPs, Primer, DNA Polymerase, template DNA. Notice that all
components are about DNA. The Primer is even a DNA Primer.
ATP, Primer, mRNA polymerase; template mRNA
Acetyl CoA, RNA primer, DNA Ligase, Template phosphate
5
Assuming 100% reaction efficiency, how many DNA copies will be
produced after 5 PCR cycles, if we begin with 1 DNA template?
(1/1 Points)
16
32
The correct answer is 32. 2x2x2x2x2=32
64
10
6
Which of the following would represent a silent mutation if this is the
original sequence: 5’ AUC GUA ACA 3’?
(1/1 Points)
5’ AUC GGA ACA 3’
5' AUA GUA ACA 3'
The correct answer is 5' AUC GUA ACA 3' Ile Val Thr
, 5’ AUG GUA ACA 3’
5’ AUC GCA ACA 3’
7
If the original coding sequence is 5’ CGA TAC TTC AGA 3’ and it is
mutated to 5' CGA TAT TTC AGA 3', what type of mutation would have
taken place?
(0/1 Points)
Silent
Missense
The correct answer is silent mutation. The nucleotide sequence changes, but it codes for
the same amino acid. The coding sequence 5' TAC 3' corresponds to the mRNA
sequence 5' UAC 3' (Tyr), and the coding sequence 5' TAT 3' corresponds to the mRNA
sequence 5' UAU 3' (Tyr). Since the C changed to at T, this is a point mutation. If the
point mutation results in the same amino acid in the new sequence as in the original
sequence, the point mutation is a silent mutation.
Nonsense
Insertion
8
This learning objective is now tested in a different WGU course than
Biochemistry. Please select True.
True
The correct answer is Option 1 because an autosomal dominant disorder would be
inherited on numbered chromosomes, not sex chromosomes X or Y. Also, at least one
dominant allele (yellow box) needs to be present for the individual to have the dominant
disease.
False
9
This learning objective is now tested in a different WGU course than
Biochemistry. Please select True.
True
The correct answer is X- linked recessive because parents (carriers) do not have it (II-5-
6) but a child does (III-5). You will get the same result if you consider parents (carriers)
(I-1-2), who do not have the trait, but a child does (II-3). A third option that gives the
same result (X-linked recessive) is by considering parents (carriers) who do not have the
trait (III-1-2), and their child does (IV-1). The pattern is recessive because the selected
parents are carriers, and it is X-linked because only males have the trait.
False
10
This learning objective is now tested in a different WGU course than
Biochemistry. Please select True.
True
The 2nd OA Readiness Check is designed to give you additional practice with
new assessment-style questions to help prepare for success on the OA. Thus,
please try to mimic exam-like conditions by taking the test in one <2 hr sitting
without any study aids apart from your whiteboard/scrap paper. Note: Responses
cannot be edited. You will be able to see the results and feedback after
submitting the test. A score of 70% is required for OA approval. If you score
below 70%, please speak with a Course Instructor via appointment to discuss
next steps prior to retaking this test.
Points:
54/67
1
What is the complementary sequence to 3’ ATG CGA ATA 5’?
(1/1 Points)
3’ TAT TCG CAT 5’
The correct answer is 3' TAT TCG CAT 5'. Remember complementary means “Matching
or Pairing” You have to remember to pay attention to your numbers as well as your
letters (A-T, G-C, 5'-3'). The correct answer is 3’ ATG CGA ATA 5’ (original sequence) 5’
TAC GCT TAT 3’ (complementary sequence) But we asked for it in the 3’ direction, so
mirror answer to give correct answer: 3’ TAT TCG CAT 5’
3’ TAC GCT TAT 5’
3’ GAT AGC ATA 5’
5’ ATA AGC GTA 3’
2
Which amino acid sequence would result from this Coding DNA strand?
3’ ATG CAG ATA 5’?
(0/1 Points)
Tyr Val Tyr
The correct answer is Ile Asp Val. We are starting at the coding strand, and have to
remember the relationship between coding DNA and mRNA. These two strands are non-
complementary and parallel. So we copy the coding strand , change T ---> U, and then
write the mRNA sequence: 3’ ATG CAG ATA 5’ coding 3’ AUG CAG AUA 5’ mRNA Mirror
by changing orientation: 5’ AUA GAC GUA 3’ Read chart Ile Asp Val (chart is in direction
of 5' ---> 3') If you chose Tyr Val Tyr, this answer is incorrect because this is the amino
acid sequence that results from the mRNA 5' UAC GUC UAU 3' which would have been
complementary to the given coding strand. Coding DNA is non-complementary and
parallel to mRNA.
Ile Gln Ile
, Ile Asp Val
Leu His Lys
3
Which amino acid sequence would be made from this template DNA
strand? 5’ TAT TAC CGA 3’?
(1/1 Points)
Tyr Tyr Arg
Ile Met Ala
Ser Val Ile
The correct answer is Ser Val Ile because 5’ TAT TAC CGA 3’ template is complementary
and antiparallel so 3’ AUA AUG GCU 5’ but it is in the wrong orientation, so mirror 5’
UCG GUA AUA 3’ and read the chart Ser Val Ile
Ser His Gln
4
Which of the following are the correct components for a PCR reaction?
(1/1 Points)
dNTPs, Primer, RNA Polymerase, template RNA
dNTPs, Primer, DNA Polymerase, template DNA
The correct answer is dNTPs, Primer, DNA Polymerase, template DNA. Notice that all
components are about DNA. The Primer is even a DNA Primer.
ATP, Primer, mRNA polymerase; template mRNA
Acetyl CoA, RNA primer, DNA Ligase, Template phosphate
5
Assuming 100% reaction efficiency, how many DNA copies will be
produced after 5 PCR cycles, if we begin with 1 DNA template?
(1/1 Points)
16
32
The correct answer is 32. 2x2x2x2x2=32
64
10
6
Which of the following would represent a silent mutation if this is the
original sequence: 5’ AUC GUA ACA 3’?
(1/1 Points)
5’ AUC GGA ACA 3’
5' AUA GUA ACA 3'
The correct answer is 5' AUC GUA ACA 3' Ile Val Thr
, 5’ AUG GUA ACA 3’
5’ AUC GCA ACA 3’
7
If the original coding sequence is 5’ CGA TAC TTC AGA 3’ and it is
mutated to 5' CGA TAT TTC AGA 3', what type of mutation would have
taken place?
(0/1 Points)
Silent
Missense
The correct answer is silent mutation. The nucleotide sequence changes, but it codes for
the same amino acid. The coding sequence 5' TAC 3' corresponds to the mRNA
sequence 5' UAC 3' (Tyr), and the coding sequence 5' TAT 3' corresponds to the mRNA
sequence 5' UAU 3' (Tyr). Since the C changed to at T, this is a point mutation. If the
point mutation results in the same amino acid in the new sequence as in the original
sequence, the point mutation is a silent mutation.
Nonsense
Insertion
8
This learning objective is now tested in a different WGU course than
Biochemistry. Please select True.
True
The correct answer is Option 1 because an autosomal dominant disorder would be
inherited on numbered chromosomes, not sex chromosomes X or Y. Also, at least one
dominant allele (yellow box) needs to be present for the individual to have the dominant
disease.
False
9
This learning objective is now tested in a different WGU course than
Biochemistry. Please select True.
True
The correct answer is X- linked recessive because parents (carriers) do not have it (II-5-
6) but a child does (III-5). You will get the same result if you consider parents (carriers)
(I-1-2), who do not have the trait, but a child does (II-3). A third option that gives the
same result (X-linked recessive) is by considering parents (carriers) who do not have the
trait (III-1-2), and their child does (IV-1). The pattern is recessive because the selected
parents are carriers, and it is X-linked because only males have the trait.
False
10
This learning objective is now tested in a different WGU course than
Biochemistry. Please select True.
True
