Exam (elaborations) TEST BANK FOR Introduction to Elementary Particles 2nd Edition By Griffiths D.J. (Solution manual)

Exam (elaborations) TEST BANK FOR Introduction to Elementary Particles 2nd Edition By Griffiths D.J. (Solution manual) Introduction to Elementary Particles Instructor’s Solution Manual 29th August 2008 VI Contents 1 Historical Introduction to the Elementary Particles 1 2 Elementary Particle Dynamics 9 3 Relativistic Kinematics 17 4 Symmetries 37 5 Bound States 57 6 The Feynman Calculus 79 7 Quantum Electrodynamics 97 8 Electrodynamics and Chromodynamics of Quarks 147 9 Weak Interactions 171 10 Gauge Theories 209 Contents VII 11 Neutrino Oscillations 233 12 What’s Next 237 A The Dirac Delta Function 247 1 1 Historical Introduction to the Elementary Particles Problem 1.1 For an undeflected charged particle, qE = qvB =) v = E B . With just a magnetic field, qvB = m v2 R =) q m = v BR = E B2R . Problem 1.2 r0 = 10−15 m; ¯h = 6.58 × 10−22 MeV s; c = 3.00 × 108 m/s; so m = ¯h 2r0c =  ¯hc 2r0  1 c2 = 98.7 MeV/c2 . Observed mp = 138 MeV/c2. Off by a factor of 1.4. Problem 1.3 r0 = 10−15 m; ¯h = 6.58 × 10−22 MeV s; c = 3.00 × 108 m/s; me = 0.511 MeV/c2. DxDp  ¯h 2 so pmin = ¯h 2r0 =  ¯hc 2r0  1 c = 98.7 MeV/c . Emin = q p2 minc2 + m2e c4 = 98.7 MeV . The energy of an electron emitted in the beta decay of tritium is 17 keV. 2 1 Historical Introduction to the Elementary Particles Problem 1.4 mL = 1 3 [2 (mN + mX) − mS] . mN = 938.9; mX = 1318.1; mS = 1190.5. So mL = 1 3 [2 (2257.0) − 1190.5] = 1107.8 MeV/c2. Observed mL = 1115.7 MeV/c2. Off by 0.7%. Problem 1.5 m2 h = 1 3 h 2  m2 K + m2 K  − m2 p i = 1 3  4m2 K − m2 p  . mK = 495.67; mp = 138.04. m2 h = 1 3 h 9.637 × 105 i = 3.212 × 105 ) mh = 566.8 MeV/c2. Actually mh = 547.3 MeV/c2. Off by 3.5%. Problem 1.6 MD − MS = 1232 − 1385 = −153 MS − MX = 1385 − 1533 = −148. Average: −151. ) MW = MX + 151 = 1533 + 151 = 1684 MeV/c2. Actually MW = 1672 MeV/c2. Off by 0.7%. Problem 1.7 (a) D− −! n + p− or S− + K0 S+ −! p + K¯0; S+ + p0; S+ + h; S0 + p+; L + p+; X0 + K+ X− −! S0 + K−; S− + K¯0; L + K−; X0 + p−; X− + p0; X− + h 3 (b) Kinematically allowed: D− −! n + p− S+ −! S+ + p0; S0 + p+; L + p+ X− −! X0 + p−; X− + p0 Problem 1.8 (a) With a strangeness of −3, the W− would have to go to