Exam (elaborations) TEST BANK FOR Mechanics of Fluids 4TH Edition By Merle C. Potter, David C. Wiggert, Bassem H. Ramadan (solution manual)

FE-type Exam Review Problems: Problems 1-1 to 1-14. 1.1 (C) m = F/a or kg = N/m/s2 = N.s2/m. 1.2 (B) [μ [τ du/dy] = (F/L2)/(L/T)/L = F.T/L2. 1.3 (A) 2.36 10 8 23.6 10 9 23.6 nPa. 1.4 (C) The mass is the same on earth and the moon: du [4(8r)] 32 r. dr 1.5 (C) Fshear F sin 4200sin30 2100 N. shear 3 4 2 = 2100 N 84 10 Pa or 84 kPa 250 10 m F A 1.6 (B) 1.7 (D) 2 2 3 water 1000 ( 4) 1000 (80 4) 968 kg/m 180 180 T 1.8 (A) du [10 5000r] .02 1 Pa. dr 1.9 (D) 3 2 6 4 cos 4 0.0736 N/m 1 3 m or 300 cm. 1000 kg/m 9.81 m/s 10 10 m h gD We used kg = N·s2/m 1.10 (C) 1.11 (C) m pV 800 kN/m2 4 m3 59.95 kg RT 0.1886 kJ/(kg K) (10 273) K Chapter 1 / Basic Considerations © 2012 Cengage Learning. All Rights Reserved. May not be scanned, copied or duplicated, or posted to a publicly accessible we bsite, in whole or in part. 2 1.12 (B) ice E Ewater . mice 320 mwater cwater T. 5 (40 10 6) 1000 320 (2 10 3) 1000 4.18 T. T 7.66 C. We assumed the density of ice to be equal to that of water, namely 1000 kg/m3. Ice is actually slightly lighter than water, but it is not necessary for such accuracy in this problem. 1.13 (D) For this high-frequency wave, c RT m/s. Chapter 1 Problems: Dimensions, Units, and Physical Quantities 1.14 Conservation of mass — Mass — density Newton’s second law — Momentum — velocity The first law of thermodynamics — internal energy — temperature 1.15 a) density = mass/volume = M / L3 b) pressure = force/area = F / L2 ML / T2L2 M / LT2 c) power = force velocity = F L / T ML / T2 L / T ML2 / T3 d) energy = force distance = ML / T2 L ML2 / T2 e) mass flux = ρAV = M/L3 × L2 × L/T = M/T f) flow rate = AV = L2 × L/T = L3/T 1.16 a) density = M L FT L L FT L 3 2 3 / 2 / 4 b) pressure = F/L2 c) power = F × velocity = F L/T = FL/T d) energy = F×L = FL e) mass flux = M T FT L T FT L 2 / / f) flow rate = AV = L2 L/T = L3/T 1.17 a) L = [C] T2. [C] = L/T2 b) F = [C]M. [C] = F/M = ML/T2 M = L/T2 c) L3/T = [C] L2 L2/3. [C] = L3 / T L2 L2/3 L1/3T Note: the slope S0 has no dimensions. 1.18 a) m = [C] s2. [C] = m/s2 b) N = [C] kg. [C] = N/kg = kg m/s2 kg = m/s2 c) m3/s = [C] m2 m2/3. [C] = m3/s m2 m2/3 = m1/3/s Chapter 1/ Basic Considerations © 2012 Cengage Learning. All Rights Reserved. May not be scanned, copied or duplicated, or posted to a publicly accessible website, in whole or in part. 3 1.19 a) pressure: N/m2 = kg m/s2/m2 = kg/m s2 b) energy: N m = kg m/s2 m = kg m2/s2 c) power: N m/s = kg m2/s3 d) viscosity: N s/m2 = kg m s s 1 m kg / m s 2 2 e) heat flux: J/s = N m s kg m s m