answers LATEST UPDATE RATED A++
Portage LearningCHEM 103module 3 exam with
answers LATEST UPDATE RATED A++
Question 1
Not yet graded / 10 pts
Click this link to access the Periodic Table. This may be helpful throughout
the exam.
A reaction between HCl and NaOH is being studied in a styrofoam coffee cup
with a lid and the heat given off is measured by means of a thermometer
immersed in the reaction mixture. Enter the correct thermochemistry term
to describe the item listed.
1. The type of thermochemical process
2. The calorimeter and mixture of HCl +
NaOH Your Answer:
1. The type of thermochemical process is an acid base reaction or
neutralization reaction where heat is given off called a exothermic
reaction.
2. The calorimeter and mixture of HCl + NaOH would be described
as enthalpy or the total energy of the system.
1. Heat given off = Exothermic process
2. With lid = closed system
Question 2
Not yet graded / 10 pts
Click this link to access the Periodic Table. This may be helpful throughout
the exam.
Portage LearningCHEM 103module 3 exam with
answers LATEST UPDATE RATED A++
odule 3 exam with answers
,Portage LearningCHEM 103module 3 exam with
answers LATEST UPDATE RATED A++
Portage LearningCHEM 103module 3 exam with
answers LATEST UPDATE RATED A++
1. Show the calculation of the final temperature of the mixture when a 31.6
gram sample of water at 92.3oC is added to a 40.5 gram sample of water at
25.1oC in a coffee cup calorimeter.
c (water) = 4.184 J/g oC
2. Show the calculation of the energy involved in melting 85 grams of ice
at 0oC if the Heat of Fusion for water is 0.334 kJ/g.
Your Answer:
Portage LearningCHEM 103module 3 exam with
answers LATEST UPDATE RATED A++
odule 3 exam with answers
, Portage LearningCHEM 103module 3 exam with
answers LATEST UPDATE RATED A++
Portage LearningCHEM 103module 3 exam with
answers LATEST UPDATE RATED A++
1.
- (mwarm H2o x Cwarm H2O x ∆twarm H2O) = (mcool H2O x ccool H2O x ∆tcool H2O)
- [31.6 g x 4.184 J/g°C x (Tmix - 92.3°C)] = [40.5g x 4.184 J/g°C x (Tmix -
25.1°C)]
- [132.2144 J/°C x (Tmix - 92.3°C)] = [169.452 J/°C x (Tmix - 25.1°C)]
-132.2144Tmix + 12,203.3891 = 169.452Tmix - 4,253.2452
16,456.6343 = 301.6664Tmix
Tmix = 54.55°C
2.
qI↔s = m x ∆Hfusion
qI↔s = 85 g x 0.334 kJ/g
qI↔s = 28.39 kJ and because heat is added + 28.39 kJ
1.
- (mwarn H2O x cwarn H2O x ∆twarn H2O) = (mcool H2O x ccool H2O x ∆tcool H2O)
- [31.6 g x 4.184 J/g oC x (Tmix - 92.3oC)] = [(40.5 g x 4.184 J/g oC x
(Tmix - 25.1oC)]
- [132.2144 J/oC x (Tmix - 92.3oC)] = [(169.452 J/oC x (Tmix - 25.1oC)]
Tmix = 54.6oC
2.
ql↔s = m x ∆Hfusion = 85 g x 0.334 kJ/g = 28.39 kJ (since heat is added) = +
28.39 kJ
Question 3
Not yet graded / 10 pts
Click this link to access the Periodic Table. This may be helpful throughout
the exam.
Show the calculation of the amount of heat involved if 18.3 g of S is reacted
with excess O2 to yield sulfur trioxide by the following reaction
Portage LearningCHEM 103module 3 exam with
answers LATEST UPDATE RATED A++
odule 3 exam with answers