BNU1501/204/2/2022
Tutorial Letter 204/2/2022
Basic Numeracy
BNU1501
Semester 2 of 2022
Department of Decision Sciences
Solutions to Assignment 04
, BNU1501/204/2/2022
BNU1501 2019 Semester 02 Assignment 04 Solutions
Q Q1 Q2 Q3 Q4 Q5 Q6 Q7 Q8 Q9 Q10
A 1 3 4 2 3 2 2 3 4 1
Question 01
(𝑥1;𝑦1) = (−3; 1) 𝑎𝑛𝑑 (𝑥2;𝑦2) = (1; −1)
The slope, 𝑚 is calculated using the formula
𝑦2−𝑦1
𝑚=
𝑥2 − 𝑥1
1 − (−1)
=
−3 − 1
2
=
−4
1
=−
2
Because 𝑚 < 0, then the slope is descending.
The correct option is 1
Question 02
Joseph invests R36 000 (𝑃) for t years at 6% simple interest per annum. The future amount is R55 440.
𝑃 = 36000 S = 55 440 𝑖 = 6%
𝐴 = 𝑃(1 + 𝑖n)
55 440= 36 000(1 + 6% × n)
Divide both sides by 36 000
1.54 = 1 + 0.06n
Subtract 1 on both sides
0.54= 0.06n
Divide both side by 0.06
n=9
It will take Joseph’s investment of R36 000 9 years to grow to R55 440 at 6% simple interest.
The correct option is 3
Tutorial Letter 204/2/2022
Basic Numeracy
BNU1501
Semester 2 of 2022
Department of Decision Sciences
Solutions to Assignment 04
, BNU1501/204/2/2022
BNU1501 2019 Semester 02 Assignment 04 Solutions
Q Q1 Q2 Q3 Q4 Q5 Q6 Q7 Q8 Q9 Q10
A 1 3 4 2 3 2 2 3 4 1
Question 01
(𝑥1;𝑦1) = (−3; 1) 𝑎𝑛𝑑 (𝑥2;𝑦2) = (1; −1)
The slope, 𝑚 is calculated using the formula
𝑦2−𝑦1
𝑚=
𝑥2 − 𝑥1
1 − (−1)
=
−3 − 1
2
=
−4
1
=−
2
Because 𝑚 < 0, then the slope is descending.
The correct option is 1
Question 02
Joseph invests R36 000 (𝑃) for t years at 6% simple interest per annum. The future amount is R55 440.
𝑃 = 36000 S = 55 440 𝑖 = 6%
𝐴 = 𝑃(1 + 𝑖n)
55 440= 36 000(1 + 6% × n)
Divide both sides by 36 000
1.54 = 1 + 0.06n
Subtract 1 on both sides
0.54= 0.06n
Divide both side by 0.06
n=9
It will take Joseph’s investment of R36 000 9 years to grow to R55 440 at 6% simple interest.
The correct option is 3
