4/19/2021 Southern New Hampshire University - Gradebook
Question
−−−
2⋅9
√ - Cancel the common factors of 18 and 16 which would be 2
2⋅8
−
−
9
√ - Rewrite
8
–
√9
–
- as
√8
3
−−−−
- The squareroot of 9 = 3, factor 4 out of 8
√4(2)
3
–
- The squareroot of 4 = 2, remove 2 from radical
2√2
–
3 √2
(
–
) ⋅ (
–
) - Multiply togther and simplify
2√2 √2
–
(3⋅√2)
– 2
2(√2)
– 1
(3⋅√2) x
n −
−− –
- use √a x = a n to rewrite √2 as 2 2 and simplify
2
1
2(2 2 )
–
(3√2)
2⋅2
–
(3√2)
4
Ungraded Grade: 0/1.0
,4/19/2021 Southern New Hampshire University - Gradebook
Question
Total grade: 1.0×1/2 + 0.0×1/2 = 50% + 0%
Feedback:
−−
− −−−
18 2⋅9
√ = √ Factor perfect squares from the radicand.
16 16
3 –
= √2 Simplify.
4
View Original Response Unfiltered Response
Q2 0/0.0
Solve for x .
6 (x + 3) − 37 = x + 6
Enter the exact answer.
x =
Your response Correct response
5 5
Auto graded Grade: 1/1.0
Show your work and explain, in your own words, how you arrived at your answer. Answers
with no relevant explanations may receive reduced or no credit.
, 4/19/2021 Southern New Hampshire University - Gradebook
Question
6 (x + 3) − 37 - Simplify the left side of the equaiton
6 x + 18 − 37 - 6*x and 6*3
6 x − 19 = x + 6
6 x − 19 − x = 6 - move x to the left side of the equation by subtracting from both sides
5 x − 19 = 6 - subtract x from 6x
5 x = 6 + 19 - Move 19 to the right side of the equation by adding 19 to both sides
5 x = 25 - Add 6+19
25
x = - Move 5 to the right side by dividing by 5
5
x = 5
Ungraded Grade: 0/1.0
Total grade: 1.0×1/2 + 0.0×1/2 = 50% + 0%
Feedback:
Apply standard algebraic properties.
6 (x + 3) − 37 = x + 6
6x + 18 − 37 = x + 6 Apply the distributive property.
6x − 19 = x + 6 Combine like terms.
5x = 25 Place x - terms on one side and simplify.
25
x = Multiply both sides by 1
, the reciprocal of 5.
5 5
x = 5
View Original Response Unfiltered Response
Q3 0/0.0
Question
−−−
2⋅9
√ - Cancel the common factors of 18 and 16 which would be 2
2⋅8
−
−
9
√ - Rewrite
8
–
√9
–
- as
√8
3
−−−−
- The squareroot of 9 = 3, factor 4 out of 8
√4(2)
3
–
- The squareroot of 4 = 2, remove 2 from radical
2√2
–
3 √2
(
–
) ⋅ (
–
) - Multiply togther and simplify
2√2 √2
–
(3⋅√2)
– 2
2(√2)
– 1
(3⋅√2) x
n −
−− –
- use √a x = a n to rewrite √2 as 2 2 and simplify
2
1
2(2 2 )
–
(3√2)
2⋅2
–
(3√2)
4
Ungraded Grade: 0/1.0
,4/19/2021 Southern New Hampshire University - Gradebook
Question
Total grade: 1.0×1/2 + 0.0×1/2 = 50% + 0%
Feedback:
−−
− −−−
18 2⋅9
√ = √ Factor perfect squares from the radicand.
16 16
3 –
= √2 Simplify.
4
View Original Response Unfiltered Response
Q2 0/0.0
Solve for x .
6 (x + 3) − 37 = x + 6
Enter the exact answer.
x =
Your response Correct response
5 5
Auto graded Grade: 1/1.0
Show your work and explain, in your own words, how you arrived at your answer. Answers
with no relevant explanations may receive reduced or no credit.
, 4/19/2021 Southern New Hampshire University - Gradebook
Question
6 (x + 3) − 37 - Simplify the left side of the equaiton
6 x + 18 − 37 - 6*x and 6*3
6 x − 19 = x + 6
6 x − 19 − x = 6 - move x to the left side of the equation by subtracting from both sides
5 x − 19 = 6 - subtract x from 6x
5 x = 6 + 19 - Move 19 to the right side of the equation by adding 19 to both sides
5 x = 25 - Add 6+19
25
x = - Move 5 to the right side by dividing by 5
5
x = 5
Ungraded Grade: 0/1.0
Total grade: 1.0×1/2 + 0.0×1/2 = 50% + 0%
Feedback:
Apply standard algebraic properties.
6 (x + 3) − 37 = x + 6
6x + 18 − 37 = x + 6 Apply the distributive property.
6x − 19 = x + 6 Combine like terms.
5x = 25 Place x - terms on one side and simplify.
25
x = Multiply both sides by 1
, the reciprocal of 5.
5 5
x = 5
View Original Response Unfiltered Response
Q3 0/0.0
