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CFA 59: Risk Management Applications of Options Strategies

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Consider a call option selling for $4 in which the exercise price is $50. Determine the value at expiration and the profit for a buyer under the following outcomes: The price of the underlying at expiration is $55. The price of the underlying at expiration is $51. The price of the underlying at expiration is $48. Determine the value at expiration and the profit for a seller under the following outcomes: The price of the underlying at expiration is $49. The price of the underlying at expiration is $52. The price of the underlying at expiration is $55. Determine the following: The maximum profit to the buyer (maximum loss to the seller). The maximum loss to the buyer (maximum profit to the seller). Determine the breakeven price of the underlying at expiration. Answer- Call buyer cT=max(0,ST−X)=max(0,55−50)=5 ∏=cT−c0=5−4=1 cT=max(0,ST−X)=max(0,51−50)=1 ∏=cT−c0=1−4=−3 cT=max(0,ST−X)=max(0,48−50)=0 ∏=cT−c0=0−4=−4 Call seller Value=−cT=−max(0,ST−X)=−max(0,49−50)=0 ∏=−cT+c0=−0+4=4 Value=−cT=−max(0,ST−X)=−max(0,52−50)=−2 ∏=−cT+c0=−2+4=2 Value=−cT=−max(0,ST−X)=−max(0,55−50)=−5 ∏=−cT+c0=−5+4=−1 Maximum and minimum Maximum profit to buyer (loss to seller) = ∞ Maximum loss to buyer (profit to seller) = c0 = 4 ST* = X + c0 = 50 + 4 = 54 Suppose you believe that the price of a particular underlying, currently selling at $99, is going to increase substantially in the next six months. You decide to purchase a call option expiring in six months on this underlying. The call option has an exercise price of $105 and sells for $7. Determine the profit under the following outcomes for the price of the underlying six months from now: $99. $104. $105. $109. $112. $115. Determine the breakeven price of the underlying at expiration. Check that your answer is consistent with the solution to Part A of this problem. Answer- cT=max(0,ST−X)=max(0,99−105)=0 ∏=cT−c0=0−7=−7 cT=max(0,ST−X)=max(0,104−105)=0 ∏=cT−c0=0−7=−7 cT=max(0,ST−X)=max(0,105−105)=0 ∏=cT−c0=0−7=−7 cT=max(0,ST−X)=max(0,109−105)=4 ∏=cT−c0=4−7=−3 cT=max(0,ST−X)=max(0,112−105)=7 ∏=cT−c0=7−7=0 cT=max(0,ST−X)=max(0,115−105)=10 ∏=cT−c0=10−7=3 ST* = X + c0 = 105 + 7 = 112 Clearly, this result is consistent with our solution above, where the profit is exactly zero in Part A(v), in which the price at expiration is 112. Consider a put option on the NASDAQ 100 selling for $106.25 in which the exercise price is 2100. Determine the value at expiration and the profit for a buyer under the following outcomes: The price of the underlying at expiration is 2125. The price of the underlying at expiration is 2050. The price of the underlying at expiration is 1950. Determine the value at expiration and the profit for a seller under the following outcomes: The price of the underlying at expiration is 1975. The price of the underlying at expiration is 2150. Determine the following: The maximum profit to the buyer (maximum loss to the seller). The maximum loss to the buyer (maximum profit to the seller). Determine the breakeven price of the underlying at expiration. Answer- Put buyer pT=max(0,X−ST)=max(0,2100−2125)=0 ∏=pT−p0=0−106.25=−106.25 pT=max(0,X−ST)=max(0,2100−2050)=50 ∏=pT−p0=50−106.25=−56.25 pT=max(0,X−ST)=max(0,2100−1950)=150 ∏=pT−p0=150−106.25=43.75 Put seller Value=−pT=−max(0,X−ST)=−max(0,2100−1975)=−125 ∏=−pT+p0=−125+106.25=−18.75 Value=−pT=−max(0,X−ST)=−max(0,2100−2150)=0 ∏=−pT+p0=−0+106.25=106.25 Maximum and minimum Maximumprofittobuyer(losstoseller)=X−p0=2100−106.25=1993.75 Maximumlosstobuyer(profittoseller)=p0=106.25 ST* = X - p0 = 2100 - 106.25 = 1993.75 Suppose you believe that the price of a particular underlying, currently selling at $99, will decrease considerably in the next six months. You decide to purchase a put option expiring in six months on this underlying. The put option has an exercise price of $95 and sells for $5. Determine the profit for you under the following outcomes for the price of the underlying six months from now: $100. $95. $93. $90. $85. Determine the breakeven price of the underlying at expiration. Check that your answer is consistent with the solution to Part A of this problem. What is the maximum profit that you can have? At what expiration price of the underlying would this profit be realized? Answer- pT=max(0,X−ST)=max(0,95−100)=0 ∏=pT−p0=0−5=−5 pT=max(0,X−ST)=max(0,95−95)=0 ∏=pT−p0=0−5=−5 pT=max(0,X−ST)=max(0,95−93)=2 ∏=pT−p0=2−5=−3 pT=max(0,X−ST)=max(0,95−90)=5 ∏=pT−p0=5−5=0 pT=max(0,X−ST)=max(0,95−85)=10 ∏=pT−p0=10−5=5 ST* = X - p0 = 95 - 5 = 90 Clearly, this result is consistent with our solution above, where the profit is exactly zero in Part A(iv), in which the price at expiration is 90. Maximum profit (to put buyer) = X - p0 = 95 - 5 = 90. This profit would be realized in the unlikely scenario of the price of the underlying falling all the way down to zero. You simultaneously purchase an underlying priced at $77 and write a call option on it with an exercise price of $80 and selling at $6. What is the term commonly used for the position that you have taken? Determine the value at expiration and the profit for your strategy under the following outcomes: The price of the underlying at expiration is $70. The price of the underlying at expiration is $75. The price of the underlying at expiration is $80. The price of the underlying at expiration is $85. Determine the following: The maximum profit. The maximum loss. The expiration price of the underlying at which you would realize the maximum profit. The expiration price of the underlying at which you would incur the maximum loss. Determine the breakeven price at expiration. Answer- This position is commonly called a covered call. VT=ST−max(0,ST−X)=70−max(0,70−80)=70−0=70 ∏=VT−V0=70−(S0−c0)=70−(77−6)=70−71=−1 VT=ST−max(0,ST−X)=75−max(0,75−80)=75−0=75 ∏=VT−V0=75−(S0−c0)=75−(77−6)=4 VT=ST−max(0,ST−X)=80−max(0,80−80)=80−0=80 ∏=VT−V0=80−(S0−c0)=80−(77−6)=9 VT=ST−max(0,ST−X)=85−max(0,85−80)=85−5=80 ∏=VT−V0=80−(S0−c0)=80−(77−6)=9 Maximum profit = X - S0 + c0 = 80 - 77 + 6 = 9 Maximum loss = S0 - c0 = 77 - 6 = 71 The maximum profit would be realized if the expiration price of the underlying is at or above the exercise price of $80. The maximum loss would be incurred if the underlying price drops to zero. ST* = S0 - c0 = 77 - 6 = 71 Suppose you simultaneously purchase an underlying priced at $77 and a put option on it, with an exercise price of $75 and selling at $3. What is the term commonly used for the position that you have taken? Determine the value at expiration and the profit for your strategy under the following outcomes: The price of the underlying at expiration is $70. The price of the underlying at expiration is $75. The price of the underlying at expiration is $80. The price of the underlying at expiration is $85. The price of the underlying at expiration is $90. Determine the following: The maximum profit. The maximum loss. The expiration price of the underlying at which you would incur the maximum loss. Determine the breakeven price at expiration. Answer- This position is commonly called a protective put. VT=ST+max(0,X−ST)=70+max(0,75−70)=70+5=75 ∏=VT−V0=75−(S0+p0)=75−(77+3)=75−80=−5 VT=ST+max(0,X−ST)=75+max(0,75−75)=75+0=75 ∏=VT−V0=75−(S0+p0)=75−(77+3)=75−80=−5 VT=ST+max(0,X−ST)=80+max(0,75−80)=80+0=80 ∏=VT−V0=80−(S0+p0)=80−(77+3)=80−80=0 VT=ST+max(0,X−ST)=85+max(0,75−85)=85+0=85 ∏=VT−V0=85−(S0+p0)=85−(77+3)=85−80=5 VT=ST+max(0,X−ST)=90+max(0,75−90)=90+0=90 ∏=VT−V0=90−(S0+p0)=90−(77+3)=90−80=10 Maximum profit = ∞ Maximum loss = -(X - S0 - p0) = -(75 - 77 - 3) = 5 The maximum loss would be incurred if the expiration price of the underlying were at or below the exercise price of $75. ST* = S0 + p0 = 77 + 3 = 80 The recent price per share of Dragon Vacations, Inc. is $50 per share. Calls with exactly six months left to expiration are available on Dragon with strikes of $45, $50, and $55. The prices of the calls are $8.75, $6.00, and $4.00, respectively. Assume that each call contract is for 100 shares of stock and that at initiation of the strategy the investor purchases 100 shares of Dragon at the current market price. Further assume that the investor will close out the strategy in six months when the options expire, including the sale of any stock not delivered against exercise of a call, whether the stock price goes up or goes down. If the closing price of Dragon stock in six months is exactly $60, the profit to a covered call using the $50 strike call is closest to: $400. $600. $1,600. Answer- B is correct. Buying the stock at $50 and delivering it against the $50 strike call generates a payoff of zero. The premium is retained by the writer. The net profit is $6.00 per share × 100 shares or $600. The recent price per share of Win Big, Inc. is €50 per share. Verna Hillsborough buys 100 shares at €50. To protect against a fall in price, Hillsborough buys one put, covering 100 shares of Win Big, with a strike price of €40. The put premium is €1 per share. If Win Big closes at €45 per share at the expiration of the put and Hillsborough sells her shares at €45, Hillsborough's profit from the stay/put is closest to: -€1,100. -€600. €900. Answer- B is correct. The loss on her stock is (€45 - €50) × 100 = -€500. She also paid €100 for the put. The put expires worthless, making her total loss €600.

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Voorbeeld van de inhoud

CFA 59: Risk Management Applications
of Options Strategies

Consider a call option selling for $4 in which the exercise price is $50.

Determine the value at expiration and the profit for a buyer under the following
outcomes:

The price of the underlying at expiration is $55.

The price of the underlying at expiration is $51.

The price of the underlying at expiration is $48.

Determine the value at expiration and the profit for a seller under the following
outcomes:

The price of the underlying at expiration is $49.

The price of the underlying at expiration is $52.

The price of the underlying at expiration is $55.

Determine the following:

The maximum profit to the buyer (maximum loss to the seller).

The maximum loss to the buyer (maximum profit to the seller).

Determine the breakeven price of the underlying at expiration. Answer- Call buyer

cT=max(0,ST−X)=max(0,55−50)=5
∏=cT−c0=5−4=1

cT=max(0,ST−X)=max(0,51−50)=1
∏=cT−c0=1−4=−3

cT=max(0,ST−X)=max(0,48−50)=0
∏=cT−c0=0−4=−4

Call seller

, Value=−cT=−max(0,ST−X)=−max(0,49−50)=0
∏=−cT+c0=−0+4=4

Value=−cT=−max(0,ST−X)=−max(0,52−50)=−2
∏=−cT+c0=−2+4=2

Value=−cT=−max(0,ST−X)=−max(0,55−50)=−5
∏=−cT+c0=−5+4=−1

Maximum and minimum

Maximum profit to buyer (loss to seller) = ∞

Maximum loss to buyer (profit to seller) = c0 = 4

ST* = X + c0 = 50 + 4 = 54

Suppose you believe that the price of a particular underlying, currently selling at $99, is
going to increase substantially in the next six months. You decide to purchase a call
option expiring in six months on this underlying. The call option has an exercise price of
$105 and sells for $7.

Determine the profit under the following outcomes for the price of the underlying six
months from now:

$99.

$104.

$105.

$109.

$112.

$115.

Determine the breakeven price of the underlying at expiration. Check that your answer
is consistent with the solution to Part A of this problem. Answer-
cT=max(0,ST−X)=max(0,99−105)=0
∏=cT−c0=0−7=−7

cT=max(0,ST−X)=max(0,104−105)=0
∏=cT−c0=0−7=−7

cT=max(0,ST−X)=max(0,105−105)=0

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