MEMO FOR MAY/JUNE 2016
SECTION 1 (suggested solutions)
1 .True
𝑁+1 8+1
2. Median = = =4.5
2 2
9+11
Therefore median = =10
2
3.range of the distribution =highest score – lowest score=13-4
Therefore range = 9
4.N=8
5.True
20
6. prob friend winning first price =150 =0.13
35
7. prob self winning first price=150 =0.23
8.True
9.dependable variable
10.∑x² = 195
11. .∑y² =306
12.mode for X distribution = 7
13. False
14.False
15. Sample
16. Null hypothesis
17. critical value of t0.01 (39)=2.7079
18. Yes
19. Interval
20.negative
, SECTION 2 (suggested solutions)
QUESTION 1
(a) 0.62 moderate positive relationship
(b) deduction : If students perform well in assignment 1 ,they can also perfom well in
assignment 2.
(c) common variance:
/ r = 0.62
r²= 0.3844 x 100%
r²= 38.44%
38.44%
(d) intercept: a = Ÿ -bX
= 4.67-(0.53)(6.91)
= 4.67-3.6623
= 1.0077
= 1.01
(e) regression : Ŷ= bX + a
= (0.53)(6) +1.01
=3.18+1.01
=3.21
SECTION 1 (suggested solutions)
1 .True
𝑁+1 8+1
2. Median = = =4.5
2 2
9+11
Therefore median = =10
2
3.range of the distribution =highest score – lowest score=13-4
Therefore range = 9
4.N=8
5.True
20
6. prob friend winning first price =150 =0.13
35
7. prob self winning first price=150 =0.23
8.True
9.dependable variable
10.∑x² = 195
11. .∑y² =306
12.mode for X distribution = 7
13. False
14.False
15. Sample
16. Null hypothesis
17. critical value of t0.01 (39)=2.7079
18. Yes
19. Interval
20.negative
, SECTION 2 (suggested solutions)
QUESTION 1
(a) 0.62 moderate positive relationship
(b) deduction : If students perform well in assignment 1 ,they can also perfom well in
assignment 2.
(c) common variance:
/ r = 0.62
r²= 0.3844 x 100%
r²= 38.44%
38.44%
(d) intercept: a = Ÿ -bX
= 4.67-(0.53)(6.91)
= 4.67-3.6623
= 1.0077
= 1.01
(e) regression : Ŷ= bX + a
= (0.53)(6) +1.01
=3.18+1.01
=3.21
