BIOLOGY 130
CHAPTER 12 STUDY
QUESTIONS
1.0/ 1.0 Points
Question 1 of 10
Determine what statements describe Huntington’s disease? Select all that apply.
A. The disease is caused by a delayed action gene
B. The diseases is autosomal dominant
C. The disease is sexlinked so it is mostly seen in men
D. Offspring have a 50% chance of inheriting the gene
E. t is recessive lethal
1.0/ 1.0 Points
Question 2 of 10
What statement describes Xlinked traits? Select all that apply.
A. Women can be carriers because they can be heterozygous for the trait
B. Xlinked traits are more common in men
C. Males are never carriers since they only receive one X chromosome
D. Males inherit Xlinked traits from their fathers
E. Women only have to have one affected gene to show the trait
1.0/ 1.0 Points
Question 3 of 10
If genes are completely linked, all the offspring will be .
A.dominant
B.hybrids
C.parental
D.recessive
E.recombinants
1.0/ 1.0 Points
Question 4 of 10
A and Z are independent events. The probability that A occurs is ¼. The probability that Z
occurs is ¼. What is the probability that both will occur?
A.1/4
B.1/8
C.1/3
D.1/2
E.1/16
1.0/ 1.0 Points
Question 5 of 10
In a monohybrid cross from heterozygous parents, of the offspring would be what genotypes?
, Select all that apply.
A. Homozygous recessive
B. Homozygous dominant
C. Heterozygotes
D. Homozygous recessives
E. Homozygous dominants
F. Heterozygote
1.0/ 1.0 Points
Question 6 of 10
Sickle cell anemia is a recessive trait. A cross between two heterozygotes would produce what
phenotypic ratio?
A.1:2:1
B.3:1
C.2:2
D.1:3
E.4:0
1.0/ 1.0 Points
Question 7 of 10
Low pitched male voices (RR) and a high pitched male voice (rr). Heterozygotes have a baritone
voice. This is an example of .
A.incomplete dominance
B.codominance
C.Mendelian genetics (dominance and recessive
D.multiple alleles
1.0/ 1.0 Points
Question 8 of 10
If a cross for widow’s peak was conducted between a homozygous dominant and a
heterozygote, it is expected that all organisms of the offspring will have widow’s peak. Even
though all have the widow’s peak, they can .
A. be phenotypically different
B. have more than one allele from a parent for the
trait C.be genotypically different
D.have the exact same alleles
1.0/ 1.0 Points
Question 9 of 10
The allele for widows peak (H) is dominant for the allele for no widows peak (h). At a different
gene locus, the allele for hitchhikers thumb (D) is dominant to the allele for nonhitchhikers
thumb (d). A man is heterozygote for the traits and marries a woman who has no widows peak
and is heterozygote for hitchhikers thumb. What is the man’s genotype?
A.HHDD
B.HhDd
CHAPTER 12 STUDY
QUESTIONS
1.0/ 1.0 Points
Question 1 of 10
Determine what statements describe Huntington’s disease? Select all that apply.
A. The disease is caused by a delayed action gene
B. The diseases is autosomal dominant
C. The disease is sexlinked so it is mostly seen in men
D. Offspring have a 50% chance of inheriting the gene
E. t is recessive lethal
1.0/ 1.0 Points
Question 2 of 10
What statement describes Xlinked traits? Select all that apply.
A. Women can be carriers because they can be heterozygous for the trait
B. Xlinked traits are more common in men
C. Males are never carriers since they only receive one X chromosome
D. Males inherit Xlinked traits from their fathers
E. Women only have to have one affected gene to show the trait
1.0/ 1.0 Points
Question 3 of 10
If genes are completely linked, all the offspring will be .
A.dominant
B.hybrids
C.parental
D.recessive
E.recombinants
1.0/ 1.0 Points
Question 4 of 10
A and Z are independent events. The probability that A occurs is ¼. The probability that Z
occurs is ¼. What is the probability that both will occur?
A.1/4
B.1/8
C.1/3
D.1/2
E.1/16
1.0/ 1.0 Points
Question 5 of 10
In a monohybrid cross from heterozygous parents, of the offspring would be what genotypes?
, Select all that apply.
A. Homozygous recessive
B. Homozygous dominant
C. Heterozygotes
D. Homozygous recessives
E. Homozygous dominants
F. Heterozygote
1.0/ 1.0 Points
Question 6 of 10
Sickle cell anemia is a recessive trait. A cross between two heterozygotes would produce what
phenotypic ratio?
A.1:2:1
B.3:1
C.2:2
D.1:3
E.4:0
1.0/ 1.0 Points
Question 7 of 10
Low pitched male voices (RR) and a high pitched male voice (rr). Heterozygotes have a baritone
voice. This is an example of .
A.incomplete dominance
B.codominance
C.Mendelian genetics (dominance and recessive
D.multiple alleles
1.0/ 1.0 Points
Question 8 of 10
If a cross for widow’s peak was conducted between a homozygous dominant and a
heterozygote, it is expected that all organisms of the offspring will have widow’s peak. Even
though all have the widow’s peak, they can .
A. be phenotypically different
B. have more than one allele from a parent for the
trait C.be genotypically different
D.have the exact same alleles
1.0/ 1.0 Points
Question 9 of 10
The allele for widows peak (H) is dominant for the allele for no widows peak (h). At a different
gene locus, the allele for hitchhikers thumb (D) is dominant to the allele for nonhitchhikers
thumb (d). A man is heterozygote for the traits and marries a woman who has no widows peak
and is heterozygote for hitchhikers thumb. What is the man’s genotype?
A.HHDD
B.HhDd
