Chem 103 portage learning General Chemistry I Exam 3 2021

6/29/2021 M3: Exam - Requires Respondus LockDown Browser + Webcam: General Chemistry I w/Lab-2021- Kozminski M3: Exam - Requires Respondus LockDown Browser + Webcam Due No due date Points 100 Questions 10 Time Limit 120 Minutes Requires Respondus LockDown Browser Instructions Please read the following before beginning the exam: You must show your work for calculations or give an explanation for short answer questions in order to receive credit. You may only use the methods and explanations provided by this course for your answers. The use of a method or explanation that was not taught in this course is a violation of the Academic Integrity Policy. You MUST only use the Periodic Table provided within the exam. You MUST only use the equation bank that is provided within the exam. The use of printed versions of the Periodic Table and equation bank will be considered a violation of the Academic Integrity Policy. Any equation or constant used on an exam that is not from the equation bank and is different from the method taught in this course will be considered an outside source and a violation of the Academic Integrity Policy. During module exams you may not use any outside source of information such as the module, problem sets, notes, Internet, tutor, etc. You may ONLY copy and paste from within the exam itself, from the equation bank, or from the provided calculator but not from an outside source. The only items you should have in front of you are your computer, 1-2 pieces of blank scratch paper, a calculator (non-cell phone), and a pen/pencil. 6/29/2021 M3: Exam - Requires Respondus LockDown Browser + Webcam: General Chemistry I w/Lab-2021- Kozminski Attempt History Attempt Time Score LATEST Attempt 1 91 minutes 97 out of 100 Score for this quiz: 97 out of 100 Submitted Jun 5 at 9:18am This attempt took 91 minutes. Ques 10 / 10 pts tion 1 Your Answer: You may find the following resources helpful: Scientific Calculator ( Periodic Table ( Equation Table ( download_frd=1) A reaction between HCl and NaOH is being studied in a styrofoam coffee cup with NO lid and the heat given off is measured by means of a thermometer immersed in the reaction mixture. Enter the correct thermochemistry term to describe the item listed. 1. The type of thermochemical process 2. The amount of heat released in the reaction of HCl with NaOH 1) This is an EXOTHERMIC REACTION. We know this because in the problem it states "the amount of heat given off", which tells us this will be an exothermic reaction giving off heat. 6/29/2021 M3: Exam - Requires Respondus LockDown Browser + Webcam: General Chemistry I w/Lab-2021- Kozminski 2) The amount of heat released in the reaction would be known as the Heat of Reaction, which is defined as the amount of heat gained or lost in a thermochemical reaction. This type of system is an OPEN SYSTEM because there is no lid, allowing the contents to interact with the environment. 1. Heat given off = Exothermic process 2. The amount of heat released = Heat of reaction Ques 10 / 10 pts tion 2 Your Answer: You may find the following resources helpful: Scientific Calculator ( Periodic Table ( Equation Table ( download_frd=1) 1. Show the calculation of the final temperature of the mixture when a 31.6 gram sample of water at 92.3 C is added to a 40.5 gram sample of water at 25.1 C in a coffee cup calorimeter. c (water) = 4.184 J/g C 2. Show the calculation of the energy involved in melting 85 grams of ice at 0 C if the Heat of Fusion for water is 0.334 kJ/g. o o o o 6/29/2021 M3: Exam - Requires Respondus LockDown Browser + Webcam: General Chemistry I w/Lab-2021- Kozminski 1) -(m * C * (Tmix - Tinitial) = (m * C * (Tmix - Tinitial) T = 54.55 C rounded to 54.6 C -(31.6 g * 4.184 kJ/g * (Tmix - 92.3 C) = (40.5 g * 4.184 kJ/g * (Tmix - 25.1 C) -132.2144 * (Tmix - 92.3 C) = 169.452 * (Tmix - 25.1 C) -132.2144Tmix + 12203.38912 = 169.452Tmix - 4253.2452 16456.63432 = 301.6664Tmix 16456.63432 / 301.6664 = T mix T mix = 54.552 C rounded to 54.6 C 2) Energy Involved in Melting 85g of ice = +28.39 kJ. m * ΔH = 85 g * 0.334 kJ/g = +23.89 kJ; the + sign makes sense because the process is melting; which is absorbing heat to melt the ice; making it an endothermic reaction. warm cool mix o o o o o o o o fusion 1. - (m x c x ∆t ) = (m x c x ∆t ) - [31.6 g x 4.184 J/g C x (T - 92.3 C)] = [(40.5 g x 4.184 J/g C x (T - 25.1 C)] - [132.2144 J/ C x (T - 92.3 C)] = [(169.452 J/ C x (T - 25.1 C)] T = 54.6 C 2. q = m x ∆H = 85 g x 0.334 kJ/g = 28.39 kJ (since heat is added) = + 28.39 kJ warn H2O warn H2O warn H2O cool H2O cool H2O cool H2O o mix o o mix o o mix o o mix o mix o l↔s fusion 6/29/2021 M3: Exam - Requires Respondus LockDown Browser + Webcam: General Chemistry I w/Lab-2021- Kozminski Ques 10 / 10 pts tion 3 Your Answer: You may find the following resources helpful: Scientific Calculator ( Periodic Table ( Equation Table ( download_frd=1) Show the calculation of the ΔH of the reaction if 10.4 g of C