Portage Learning MATH 110 MODULE 10 Exam
M10: Exam- Requires Respondus LockDown Browser
• Due No due date
• Points 50
• Questions 6
• Time Limit 90 Minutes
• Requires Respondus LockDown Browser
This quiz is currently locked.
Attempt History
Attempt Time Score
LATEST Attempt 1 76 minutes 45 out of 50
Score for this quiz: 45 out of 50
Submitted Jul 29 at 7:06pm
This attempt took 76 minutes.
Question 1
pts
You may find the following files helpful throughout the exam:
Statistics_Equation_Sheet (Links to an external site.)
standard normal table (Links to an external site.)
t-table (Links to an external site.)
Critical_values_chart (Links to an external site.)
Chi-square table (Links to an external site.)
F_Distribution_Table_ (Links to an external site.)
/
, Find the value of X2 for 15 degrees of freedom and an area of .050 in the right tail of the chi-square
distribution.
Your Answer:
For this problem I must calculate: (1-.050)=.95, therefore X2=7.261
Look across the top of the chi-square distribution table for .050, then look down the left column for
15. These two meet at X2 =24.996.
Question 2
pts
You may find the following files helpful throughout the exam:
Statistics_Equation_Sheet (Links to an external site.)
standard normal table (Links to an external site.)
t-table (Links to an external site.)
Critical_values_chart (Links to an external site.)
Chi-square table (Links to an external site.)
F_Distribution_Table_ (Links to an external site.)
Find the value of X2 for 17 degrees of freedom and an area of .050 in the left tail of the chi-square
distribution.
Your Answer:
For this problem, I must calculate (1-.050)=.95, therefore X2 =8.672
Since the chi-square distribution table gives the area in the right tail, we must use 1 - .05 = .95. Look
across the top of the chi-square distribution table for .95, then look down the left column for 17.
These two meet at X2 =8.672.
Question 3
pts
You may find the following files helpful throughout the exam:
Statistics_Equation_Sheet (Links to an external site.)
/
M10: Exam- Requires Respondus LockDown Browser
• Due No due date
• Points 50
• Questions 6
• Time Limit 90 Minutes
• Requires Respondus LockDown Browser
This quiz is currently locked.
Attempt History
Attempt Time Score
LATEST Attempt 1 76 minutes 45 out of 50
Score for this quiz: 45 out of 50
Submitted Jul 29 at 7:06pm
This attempt took 76 minutes.
Question 1
pts
You may find the following files helpful throughout the exam:
Statistics_Equation_Sheet (Links to an external site.)
standard normal table (Links to an external site.)
t-table (Links to an external site.)
Critical_values_chart (Links to an external site.)
Chi-square table (Links to an external site.)
F_Distribution_Table_ (Links to an external site.)
/
, Find the value of X2 for 15 degrees of freedom and an area of .050 in the right tail of the chi-square
distribution.
Your Answer:
For this problem I must calculate: (1-.050)=.95, therefore X2=7.261
Look across the top of the chi-square distribution table for .050, then look down the left column for
15. These two meet at X2 =24.996.
Question 2
pts
You may find the following files helpful throughout the exam:
Statistics_Equation_Sheet (Links to an external site.)
standard normal table (Links to an external site.)
t-table (Links to an external site.)
Critical_values_chart (Links to an external site.)
Chi-square table (Links to an external site.)
F_Distribution_Table_ (Links to an external site.)
Find the value of X2 for 17 degrees of freedom and an area of .050 in the left tail of the chi-square
distribution.
Your Answer:
For this problem, I must calculate (1-.050)=.95, therefore X2 =8.672
Since the chi-square distribution table gives the area in the right tail, we must use 1 - .05 = .95. Look
across the top of the chi-square distribution table for .95, then look down the left column for 17.
These two meet at X2 =8.672.
Question 3
pts
You may find the following files helpful throughout the exam:
Statistics_Equation_Sheet (Links to an external site.)
/
