IOP2601 Assignment 2 Semester 1 2022.

, IOP 2601 ASSIGNMENT 2 SUGGESTED SOLUTIONS

QUESTION 1

1.1 Probability Self winning first prize
TOTAL NUMBER OF ENTRIES = 300
Number of entries submitted (self) = 20
20
Therefore probability = 300 = 0.067



1.2 Probability Friend winning Second prize
TOTAL NUMBER OF ENTRIES = 300 – 1=299
Number of entries submitted (Friend) = 30
30
Therefore probability = 299 = 0.1




1.3 Probability self and friend winning first and second prize =
(Prob self winning 1st prize x Prob friend winning 2nd prize) + (Prob self winning 2nd prize x
Prob friend winning 1st prize)
20 30
= (0.067 x 0.1) + ( 299 + 300 )

= (0.067 x 0.1) + (0.067 x 0.1)
=0.0067 + 0.0067
= 0.0134 or 0.013




QUESTION 2

2.1 P(X >10)


1
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