BIOD 171 Essential Microbiology Portage Learning Module 5 Exam
Questions and Answers
Attempt Time Score
LATEST Attempt 1 36 minutes 96 out of 100
Scoreforthisqu
iz:96outof10
SubmitedAug1
at1 :24pm
Thisatempto
k36minutes.
Question1
3/3pts
Theconceptoftreatingalsamples,whe
therknownorunknown,aspotentialy
hazardous(orpathogenic)materialsi
sknownas .
YourAnswer
:
universalp
recautions
Universalp
recautions
Question2
3/3pts
Listatleast3observationsaresearcher
wouldbesuretonotewhileassessingan
unknownmicrobialsample.
YourAnswer:
1.anym
otilit
y
2.size/
shape
3. gram status(gram-
positiveorgram-
negative)
4.presenseofanychemi
calreactions
5.changesincolor
Alabresearcherwouldbecertaintonote:
,BIOD 171 Essential Microbiology Portage Learning Module 5 Exam
Questions and Answers
1. Sizeandshape
2.Anyobservablemo
tility 3.Gram
status(positiveor
negative)
, BIOD 171 Essential Microbiology Portage Learning Module 5 Exam
Questions and Answers
4.Thepresenceofanychemicalreac
tions
5.Changesincolorlocalizedtotheo
rganism orthesurounding
media
6.Capture(ordraw)imagesofanyofthe
characteristicsdescribed above
Question3
10/10pts
Whileobservinganunknownsampleoflimited
amounts,aresearchermustdetermine
thefolowingobservations:
(1)thepresenceofanymotilityand(2)itsG
ram statususing thesamesample—
theliquidsamplecan
otbedivided.Whichwouldyoudeterminefirst
andwhy?
YourAnswer:
Youwouldne dtodeterminethemotilitybeforegram
status.Youcanobservemotility
onawetmountandthenheatfixyoursampletogram
stainyoursample.Ifyouwereto
beginwithusinggram
staining,youwouldkilyoursamplewithheatfixing
youwould notbeabletoobserveanymotility.
Youmustdeterminemotilitybeforedeterminingth
eGram status.Motilityrequires
awetmount,whileGram
stainingrequiresheatfixingthesample.Ifonewer
eto beginwiththeGram
staintheheatfixationproces
wouldkiltheorganism,
makinganyobservationsregardingmotilityimpos
ible.Thecorectap roach
wouldbetoplacetheliquidcultureonaglas
slideanddetermineitsmotility
status.Next,thesameliquidculturecanbeheatfix
edandGram stained.
Question4
3/3pts
Afacultativeanaerobeisamicro rganism
capableofgrowthunderwhatconditions?
YourAnswer:
aerobicandanaerobicconditions
Afacultativeanaerobeiscapableofgrow
thunderaerobic(withoxygen)and
anaerobic(withoutoxygen)conditions.
Questions and Answers
Attempt Time Score
LATEST Attempt 1 36 minutes 96 out of 100
Scoreforthisqu
iz:96outof10
SubmitedAug1
at1 :24pm
Thisatempto
k36minutes.
Question1
3/3pts
Theconceptoftreatingalsamples,whe
therknownorunknown,aspotentialy
hazardous(orpathogenic)materialsi
sknownas .
YourAnswer
:
universalp
recautions
Universalp
recautions
Question2
3/3pts
Listatleast3observationsaresearcher
wouldbesuretonotewhileassessingan
unknownmicrobialsample.
YourAnswer:
1.anym
otilit
y
2.size/
shape
3. gram status(gram-
positiveorgram-
negative)
4.presenseofanychemi
calreactions
5.changesincolor
Alabresearcherwouldbecertaintonote:
,BIOD 171 Essential Microbiology Portage Learning Module 5 Exam
Questions and Answers
1. Sizeandshape
2.Anyobservablemo
tility 3.Gram
status(positiveor
negative)
, BIOD 171 Essential Microbiology Portage Learning Module 5 Exam
Questions and Answers
4.Thepresenceofanychemicalreac
tions
5.Changesincolorlocalizedtotheo
rganism orthesurounding
media
6.Capture(ordraw)imagesofanyofthe
characteristicsdescribed above
Question3
10/10pts
Whileobservinganunknownsampleoflimited
amounts,aresearchermustdetermine
thefolowingobservations:
(1)thepresenceofanymotilityand(2)itsG
ram statususing thesamesample—
theliquidsamplecan
otbedivided.Whichwouldyoudeterminefirst
andwhy?
YourAnswer:
Youwouldne dtodeterminethemotilitybeforegram
status.Youcanobservemotility
onawetmountandthenheatfixyoursampletogram
stainyoursample.Ifyouwereto
beginwithusinggram
staining,youwouldkilyoursamplewithheatfixing
youwould notbeabletoobserveanymotility.
Youmustdeterminemotilitybeforedeterminingth
eGram status.Motilityrequires
awetmount,whileGram
stainingrequiresheatfixingthesample.Ifonewer
eto beginwiththeGram
staintheheatfixationproces
wouldkiltheorganism,
makinganyobservationsregardingmotilityimpos
ible.Thecorectap roach
wouldbetoplacetheliquidcultureonaglas
slideanddetermineitsmotility
status.Next,thesameliquidculturecanbeheatfix
edandGram stained.
Question4
3/3pts
Afacultativeanaerobeisamicro rganism
capableofgrowthunderwhatconditions?
YourAnswer:
aerobicandanaerobicconditions
Afacultativeanaerobeiscapableofgrow
thunderaerobic(withoxygen)and
anaerobic(withoutoxygen)conditions.
