Chapter 5 Solution Notes of Arithmetic Progression

InIn ttu Jallauwing APs. ind the missing 3eny
in the bacus


iv , , E, , . ,6

Suk
a 6
a a t 5d
a t 5d G
-4+5d-6
5d = lo

d d2
a a+d =
-4+2 =-2
A g a +2d = -4t2a) = -4+4 =0
a 4 a +3d = -4+32) = =4+6 = 2

Qsa44d - -444(2) = =4 +8 =4



, 38,B, E,-22
Scluti -
a a +d 22
38 a t d
-q.' -21 =a t5d i
lsig iminatien Mthod
a+d 38
tsd -22

o -4d-60 15
.d 0 -15

, luting aluu o d in e4i
38 a +-15)
38 a-15

3 8+15=a
53 0




a+2d

= 53+2(-15)> 53 -30 23
4 +3d
53+3-15) 53-45 8
at4d

= 53t4E15)>53 60 -+
38, 23, 8, -7, -22,
Au AP 53,

i s 18
Which tam o tha AP: 3, 8, 13,18,

Salu AP: 3,8,13,18
a3 d 8-3=5
an 8 n?

anattn-1)d
H83+ (n-)5
'.- 3 -05
n-I




h 15+ =16
So ha terun ol A.P. is t8

, 95 Lind tha numbe ems in ach o he
Jallaaing APs

4,13,13, 19,., 205

Salu a =1. d-13-1 6
an 205 h


n a + (n-)d
205 4+ (n-1) 6
205- h-1)C
433



n-1 33
. n 334 34
Henca, hure Au 3t toms in tha gin AP


hark uhuthen -15o isa túun thu AP n,

Solu w. us assume t e -50 s n tuun oAP
anE56 n-)
a ,d 8 I=
Ona+(n-)d
-150 4 (n-i)-3
-

150-11 =
(n-1)-3
n- 16) _n-
h 6) 61t3
n ahuld be o uwhole n 3
Bd it is cgming in action '150 js hat a erm o