(JEE MAINS + ADVANCED)
RACE # 01 (Regular Analysis through Continuous Exercise)
Only one option is correct:-
cosec 4 x−2 cosec 2 x +1
1. Let f(x) = cosecx ( cosecx −sinx )+
sinx−cosx
+ cotx the sum all the solutions of
sinx
f(x) = 0 in [0, 100π] is –
(a) 2550π (b) 2500π (c) 5000π (d) 5050π
2. Set of values of x in (-π, π) for which |4sinx-1|<√5 is given by –
(a) ( π 3π
,
10 10 ) (b)( 10 , 10 )
−π 3 π
(c)( 10 ,− 10 )
π 3π
(d)( 10 ,− 10 )
−π 3π
3. Number of values of x satisfying the equation
log ( sinx ) +¿ log (−cosx )=0 ¿ in the interval (-π π)is equal to –
2 1
2
(a) 0 (b) 1 (c) 2 (d)3
cos 3 x 0 1 sin 3 x
4. If cosx = 3 for some angle x, 0≤x≤π/2, then the value of sinx for
some x, is
(a) 7/3 (b) 5/3 (c) 1 (d)2/3
5. The set of values of x satisfying simultaneously the inequalities
√( x−8 ) ( 2−x ) ≥0 and x−1
2 −31> 0is :−¿
log ¿ ¿ ¿
0.3
(a) A unit set