This documents will help you to overcome weaknesses and ace the test. Use
this study guide review in conjunction with your textbook and you will find
that this study guide review is a great complement to your textbook which
you have studied in your school.
If you are looking for an ultrasound physics exam review with only questions
and answers to study for, you will be glad you made an excellent choice by
buying this study guide review.
The study guide review is comprehensive and does not go into much detail
but provides sound foundation to prepare for ARDMS SPI exam. This study
guide review is in question and answer format with over 300 questions with
detailed easy to understand answers. It is designed to help you prepare for the
questions which appear on the ARDMS SPI exam.
After studying this study guide review you will feel confident and will be
able to answer most of the questions easily which appear on the ARDMS SPI
board exam.
The content is broken down in an easy-to-understand format and all content
is based on the current outline of the ARDMS Sonography Principles and
Instrumentation Exam.
You’ll find that this is the best study guide review available in the market to
help you prepare and pass ultrasound physics exam. Consider this study
guide review as an additional help for the ARDMS SPI examination.
To take full advantage of this review study these questions and answers at least
three times and memorize them.
,Q1. The maximum value of the density of an acoustic wave is 60 lb/in2
while the minimum density is 20 lb/in2. What is the peak to peak
amplitude of the wave?
Answer: The amplitude of the wave is 20 lb/in2.
The difference between maximum and minimum values of an acoustic
variable is called the peak to peak amplitude. Amplitude is half of the
peak to peakamplitude.
Peak to peak amplitude = 60 lb/in2 – 20 lb/in2 = 40 lb/in2
Amplitude =
Amplitude =
Amplitude = 20 lb/in2
Q2. If the level of an acoustic variable ranges from 55 to 105, what is
the peak to peak amplitude?
Answer: 25
Amplitude is half of the peak to peak amplitude.
Peak to peak amplitude = 105 – 55 = 50
Amplitude =
Amplitude =
Amplitude = 25
Q3. With standard diagnostic imaging instrumentation, the
sonographer has the ability to vary the amplitude of a sound wave
produced by the transducer.
Answer: True
The sonographer has the ability to vary the amplitude of a sound wave
produced by the transducer by changing the output power.
Q4. If a wave’s amplitude is doubled, what happens to the power?
Answer: If a wave’s amplitude is doubled, the power is quadrupled.
Power = (Amplitude)2
,If a wave’s amplitude is doubled, the power is quadrupled.
Q5. If the intensity of a sound beam remains unchanged while the
beam area is reduced in half, what has happened to the power?
Answer: The power doubles.
Intensity is the power in a wave divided by the area of the beam.
If the intensity of a sound beam remains unchanged while the beam area is
reduced in half, the power in the sound beam will increase and will be
doubled.
Q6. If the amplitude is doubled the intensity is ______?
Answer: If the amplitude is doubled the intensity is increased 4 times.
Power = (Amplitude)2
If a wave’s amplitude is doubled, the power is quadrupled.
Intensity is directly proportional to power.
When power goes up, the intensity goes up.
If the power is quadrupled, the intensity is also quadrupled.
Q7. What happens to the intensity of an ultrasound beam when the
beam’s cross-sectional area remains unchanged while the amplitude
of the wave triples?
Answer: Intensity of ultrasound beam increases by nine fold.
When amplitude is tripled, the power increases by nine fold
Power = (Amplitude)2
Power = (3)2
Power = (3 × 3)
Power = (9)
Intensity is directly proportional to the power. When power increases by
nine fold, the intensity increases by nine fold if the beam’s cross sectional
area remains unchanged.
, Q8. What happens to an acoustic beam’s intensity when the power in
the beam increases by 25% whiles the cross sectional area of the beam
remains the same?
Answer: The intensity also increases by 25%
Intensity is directly proportional to power. If intensity increases, the
power also increases if the beam area is not changed.
Q9. If the power in an ultrasound beam is unchanged, while at the
same time, the beam area doubles, and then the beam’s intensity is
______?
Answer: The beam’s intensity is halved.
The beam area and intensity are inversely proportional. If the beam area is
increased, the intensity will decrease if the power remains the same.
Q10. What determines the intensity of an ultrasound beam after it has
traveled through the body?
Answer:
Intensity decreases as the sound travels (propagates) through the body.
The sound wave’s source and the medium through which the sound travels
both determine the intensity of an ultrasound beam after it has traveled
through the body.
Q11. What are the units of intensity?
Answer:
The unit of intensity is watts/cm2
Q12. The amplitude of an acoustic wave decreases from 27 pascals to 9
pascals. If the initial power in the wave was 27 watts, what is the
wave’s final power?
Answer: The wave’s final power is 3 watts.
The amplitude is decreased by (from 27 pascals to 9 pascals)
this study guide review in conjunction with your textbook and you will find
that this study guide review is a great complement to your textbook which
you have studied in your school.
If you are looking for an ultrasound physics exam review with only questions
and answers to study for, you will be glad you made an excellent choice by
buying this study guide review.
The study guide review is comprehensive and does not go into much detail
but provides sound foundation to prepare for ARDMS SPI exam. This study
guide review is in question and answer format with over 300 questions with
detailed easy to understand answers. It is designed to help you prepare for the
questions which appear on the ARDMS SPI exam.
After studying this study guide review you will feel confident and will be
able to answer most of the questions easily which appear on the ARDMS SPI
board exam.
The content is broken down in an easy-to-understand format and all content
is based on the current outline of the ARDMS Sonography Principles and
Instrumentation Exam.
You’ll find that this is the best study guide review available in the market to
help you prepare and pass ultrasound physics exam. Consider this study
guide review as an additional help for the ARDMS SPI examination.
To take full advantage of this review study these questions and answers at least
three times and memorize them.
,Q1. The maximum value of the density of an acoustic wave is 60 lb/in2
while the minimum density is 20 lb/in2. What is the peak to peak
amplitude of the wave?
Answer: The amplitude of the wave is 20 lb/in2.
The difference between maximum and minimum values of an acoustic
variable is called the peak to peak amplitude. Amplitude is half of the
peak to peakamplitude.
Peak to peak amplitude = 60 lb/in2 – 20 lb/in2 = 40 lb/in2
Amplitude =
Amplitude =
Amplitude = 20 lb/in2
Q2. If the level of an acoustic variable ranges from 55 to 105, what is
the peak to peak amplitude?
Answer: 25
Amplitude is half of the peak to peak amplitude.
Peak to peak amplitude = 105 – 55 = 50
Amplitude =
Amplitude =
Amplitude = 25
Q3. With standard diagnostic imaging instrumentation, the
sonographer has the ability to vary the amplitude of a sound wave
produced by the transducer.
Answer: True
The sonographer has the ability to vary the amplitude of a sound wave
produced by the transducer by changing the output power.
Q4. If a wave’s amplitude is doubled, what happens to the power?
Answer: If a wave’s amplitude is doubled, the power is quadrupled.
Power = (Amplitude)2
,If a wave’s amplitude is doubled, the power is quadrupled.
Q5. If the intensity of a sound beam remains unchanged while the
beam area is reduced in half, what has happened to the power?
Answer: The power doubles.
Intensity is the power in a wave divided by the area of the beam.
If the intensity of a sound beam remains unchanged while the beam area is
reduced in half, the power in the sound beam will increase and will be
doubled.
Q6. If the amplitude is doubled the intensity is ______?
Answer: If the amplitude is doubled the intensity is increased 4 times.
Power = (Amplitude)2
If a wave’s amplitude is doubled, the power is quadrupled.
Intensity is directly proportional to power.
When power goes up, the intensity goes up.
If the power is quadrupled, the intensity is also quadrupled.
Q7. What happens to the intensity of an ultrasound beam when the
beam’s cross-sectional area remains unchanged while the amplitude
of the wave triples?
Answer: Intensity of ultrasound beam increases by nine fold.
When amplitude is tripled, the power increases by nine fold
Power = (Amplitude)2
Power = (3)2
Power = (3 × 3)
Power = (9)
Intensity is directly proportional to the power. When power increases by
nine fold, the intensity increases by nine fold if the beam’s cross sectional
area remains unchanged.
, Q8. What happens to an acoustic beam’s intensity when the power in
the beam increases by 25% whiles the cross sectional area of the beam
remains the same?
Answer: The intensity also increases by 25%
Intensity is directly proportional to power. If intensity increases, the
power also increases if the beam area is not changed.
Q9. If the power in an ultrasound beam is unchanged, while at the
same time, the beam area doubles, and then the beam’s intensity is
______?
Answer: The beam’s intensity is halved.
The beam area and intensity are inversely proportional. If the beam area is
increased, the intensity will decrease if the power remains the same.
Q10. What determines the intensity of an ultrasound beam after it has
traveled through the body?
Answer:
Intensity decreases as the sound travels (propagates) through the body.
The sound wave’s source and the medium through which the sound travels
both determine the intensity of an ultrasound beam after it has traveled
through the body.
Q11. What are the units of intensity?
Answer:
The unit of intensity is watts/cm2
Q12. The amplitude of an acoustic wave decreases from 27 pascals to 9
pascals. If the initial power in the wave was 27 watts, what is the
wave’s final power?
Answer: The wave’s final power is 3 watts.
The amplitude is decreased by (from 27 pascals to 9 pascals)
