4/19/202 Southern New Hampshire University -
1 Gradebook
Question
√ 2⋅9 - Cancel the common factors of 18 and 16 which would be 2
2⋅8
√9 - Rewrite
8
√9
- as
√8
3
- The squareroot of 9 = 3, factor 4 out of 8
√4(2)
3
- The squareroot of 4 = 2, remove 2 from radical
2√2
( 2√2
3
) ⋅ √2
( √2 ) - Multiply togther and simplify
(3⋅√2)
2
2(√2)
(3⋅√2) x 1
n
1 2 - use √a x = a n to rewrite √2 as 2 2 and simplify
( )
2 22
(3√2)
2⋅2
(3√2)
4
Ungraded Grade: 0/1.0
,4/19/202 Southern New Hampshire University -
1 Gradebook
Question
Total grade: 1.0×1/2 + 0.0×1/2 = 50% + 0%
√ 18 = √ 2⋅9
Feedback:
Factor perfect squares from the radicand.
16 16
= 3 √2 Simplify.
4
View Original Response Unfiltered Response
Q2 0/0.0
Solve for x.
6 (x + 3) − 37 = x + 6
Enter the exact answer.
x=
Your response Correct response
5 5
Auto graded Grade: 1/1.0
Show your work and explain, in your own words, how you arrived at your answer. Answers
with no relevant explanations may receive reduced or no credit.
, 4/19/202 Southern New Hampshire University -
1 Gradebook
Question
6 (x + 3) − 37 - Simplify the left side of the equaiton
6 x + 18 − 37 - 6*x and 6*3
6 x − 19 = x + 6
6 x − 19 − x = 6 - move x to the left side of the equation by subtracting from both sides
5 x − 19 = 6 - subtract x from 6x
5 x = 6 + 19 - Move 19 to the right side of the equation by adding 19 to both sides
5 x = 25 - Add 6+19
25
x = - Move 5 to the right side by dividing by 5
5
x=5
Ungraded Grade: 0/1.0
Total grade: 1.0×1/2 + 0.0×1/2 = 50% + 0%
Feedback:
Apply standard algebraic properties.
6 (x + 3) − 37 = x + 6
6x + 18 − 37 = x + 6 Apply the distributive
6x − 19 = x + 6
property. Combine like terms.
5x = 25
25 Place x- terms on one side and simplify.
x=
5
Multiply both sides by 1 , the reciprocal of 5.
x=5 5
Q3
View Original Response Unfiltered Response
0/0.0
1 Gradebook
Question
√ 2⋅9 - Cancel the common factors of 18 and 16 which would be 2
2⋅8
√9 - Rewrite
8
√9
- as
√8
3
- The squareroot of 9 = 3, factor 4 out of 8
√4(2)
3
- The squareroot of 4 = 2, remove 2 from radical
2√2
( 2√2
3
) ⋅ √2
( √2 ) - Multiply togther and simplify
(3⋅√2)
2
2(√2)
(3⋅√2) x 1
n
1 2 - use √a x = a n to rewrite √2 as 2 2 and simplify
( )
2 22
(3√2)
2⋅2
(3√2)
4
Ungraded Grade: 0/1.0
,4/19/202 Southern New Hampshire University -
1 Gradebook
Question
Total grade: 1.0×1/2 + 0.0×1/2 = 50% + 0%
√ 18 = √ 2⋅9
Feedback:
Factor perfect squares from the radicand.
16 16
= 3 √2 Simplify.
4
View Original Response Unfiltered Response
Q2 0/0.0
Solve for x.
6 (x + 3) − 37 = x + 6
Enter the exact answer.
x=
Your response Correct response
5 5
Auto graded Grade: 1/1.0
Show your work and explain, in your own words, how you arrived at your answer. Answers
with no relevant explanations may receive reduced or no credit.
, 4/19/202 Southern New Hampshire University -
1 Gradebook
Question
6 (x + 3) − 37 - Simplify the left side of the equaiton
6 x + 18 − 37 - 6*x and 6*3
6 x − 19 = x + 6
6 x − 19 − x = 6 - move x to the left side of the equation by subtracting from both sides
5 x − 19 = 6 - subtract x from 6x
5 x = 6 + 19 - Move 19 to the right side of the equation by adding 19 to both sides
5 x = 25 - Add 6+19
25
x = - Move 5 to the right side by dividing by 5
5
x=5
Ungraded Grade: 0/1.0
Total grade: 1.0×1/2 + 0.0×1/2 = 50% + 0%
Feedback:
Apply standard algebraic properties.
6 (x + 3) − 37 = x + 6
6x + 18 − 37 = x + 6 Apply the distributive
6x − 19 = x + 6
property. Combine like terms.
5x = 25
25 Place x- terms on one side and simplify.
x=
5
Multiply both sides by 1 , the reciprocal of 5.
x=5 5
Q3
View Original Response Unfiltered Response
0/0.0
