SOLUTIONS MANUAL Wastewater Engineering: Treatment and Resource Recovery Fifth Edition

SOLUTIONS MANUAL

Wastewater Engineering:
Treatment and Resource Recovery
Fifth Edition




McGraw-Hill Book Company, Inc.
New York

, CONTENTS
1. Wastewater Engineering: An Overview 1-1
2. Constituents in Wastewater 2-1

3. Wastewater Flowrates and Constituent Loadings 3-1

4. Process Selection and Design Considerations 4-1

5. Physical Processes 5-1

6. Chemical Processes 6-1

7. Fundamentals of Biological Treatment 7-1

8. Suspended Growth Biological Treatment Processes 8-1

9. Attached Growth and Combined Biological Treatment 9-1
Processes
10. Anaerobic Suspended and Attached Growth Biological 10-1
Treatment Processes
11. Separation Processes for Removal of Residual Constituents 11-1

12. Disinfection Processes 12-1

13. Processing and Treatment of Sludges 13-1

14. Ultimate and Reuse of Biosolids 14-1

15. Treatment of Return Flows and Nutrient Recovery 15-1

16. Treatment Plant Emissions and Their Control 16-1
17. Energy Considerations in Wastewater Management 17-1
18. Wastewater Management: Future Challenges and 18-1
Opportunities




v

,iii

, 1
INTRODUCTION TO
WASTEWATER TREATMENT
PROBLEM 1-1

Instructors Note: The first six problems are designed to illustrate the
application of the mass balance principle using examples from hydraulics with
which the students should be familiar.

Problem Statement - See text, page 53
Solution
1. Write a materials balance on the water in the tank
Accumulation = inflow – outflow + generation
dV dh
 A  Q –Q 0
in out
dt dt

2. Substitute given values for variable items and solve for h
dh  t  3
 A  0.2 m3
/ s – 0.2  1  cos





43,200 
dt m /s

A = 1000 m2
 t 
3. dh  2 x104 cos dt
  43,200 




Integrating the above expression yields:
(43,200) (2 x104)  t 
h  ho    sin 
    43,200 


4. Determine h as a function of time for a 24 hour cycle




1-1