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Principles of Medical Biochemistry, Meisenberg - Exam Preparation Test Bank (Downloadable Doc)

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Description: Test Bank for Principles of Medical Biochemistry, Meisenberg, 3e prepares you efficiently for your upcoming exams. It contains practice test questions tailored for your textbook. Principles of Medical Biochemistry, Meisenberg, 3e Test bank allow you to access quizzes and multiple choice questions written specifically for your course. The test bank will most likely cover the entire textbook. Thus, you will get exams for each chapter in the book. You can still take advatange of the test bank even though you are using newer or older edition of the book. Simply because the textbook content will not significantly change in ne editions. In fact, some test banks remain identical for all editions. Disclaimer: We take copyright seriously. While we do our best to adhere to all IP laws mistakes sometimes happen. Therefore, if you believe the document contains infringed material, please get in touch with us and provide your electronic signature. and upon verification the doc will be deleted.

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Meisenberg: Principles of Medical Biochemistry, 3rd Edition


Chapter 1: Introduction to Biomolecules



Test Bank



MULTIPLE CHOICE


1. β Linkages are important in structural polysaccharides because:

a. They are easily hydrolyzed by glycosidase enzymes.

b. They allow the chains to form compact coils.

c. They cause the chains to exist in an extended form, thus allowing them to form fibers.

d. They cause the chains to absorb more water.

e. They can be formed by any hydroxy group in the monomer, whereas  linkages can
be formed only by C-1.



ANS: C

Cellulose, chitin, and peptidoglycan are examples of fibrous polysaccharides that are formed from
β-linked units.



2. What is the difference between α-D-glucose and α-D-galactose?

a. They are mirror images of each other.

b. They differ in the configuration of substituents at C-4.

c. One is an aldose and the other is a ketose.

d. They are anomers.

e. One forms only O-glycosidic bonds, and the other forms only N-glycosidic bonds.

,ANS: B

Galactose is a C-4 epimer of glucose (and vice versa). Epimers are not mirror images of one
another because other asymmetrical carbons are also present in the molecule.



3. What is the major difference between glycogen and amylose?

a. Glycogen contains only glucose, and amylose contains some fructose in addition to
glucose.

b. Glycogen is a storage polysaccharide, and amylose is a structural polysaccharide of
the extracellular matrix.

c. Glycogen is branched, and amylose is not.

d. Glycogen contains some β linkages, but amylose contains only α linkages.

e. Glycogen is stored in the liver, and amylose is stored in skeletal muscle.



ANS: C

Glycogen is a branched polysaccharide similar to amylopectin, a form of starch that is found
together with unbranched amylose in the starch granules of plants.



4. Unlike covalent bonds, all noncovalent interactions are:

a. Formed in irreversible reactions.

b. Constantly forming and breaking on the molecular time scale.

c. Susceptible to cleavage by strong acids and bases.

d. Classified as energy-rich, because they are cleaved easily.

e. Independent of the solvent that surrounds the bond-forming groups.



ANS: B

Because noncovalent bonds form and break constantly, all noncovalent interactions are
reversible.

,Meisenberg: Principles of Medical Biochemistry, 3rd Edition


Chapter 2: Introduction to Protein Structure



Test Bank



MULTIPLE CHOICE


1. Which of the following is true about the tertiary structure of proteins?

a. Disulfide bonds are part of the tertiary structure.

b. Only proteins with more than one polypeptide subunit have a tertiary structure.

c. Proteins with tertiary structure do not contain α helix or β-pleated sheet.

d. Van der Waals interactions play no role in the tertiary structure.

e. Interactions between hydrophobic amino acid side chains are important for hold the
tertiary structure together.



ANS: E

Hydrophobic groups associate with one another to minimize the thermodynamically
unfavorable interface between lipid and water. Hydrophobic interactions and van der Waals
interactions prevail in the core of globular proteins.



2. Amino acids at the isoelectric point in the titration curve have a net charge of:

a. 1.

b. +1.

c. +2.

d. 0.

e. –2.

, ANS: D

This is the definition of the isoelectric point.



3. Which amino acid residues are used as attachment sites for covalently bound
oligosaccharides in glycoproteins?

a. Asparagine and serine.

b. Tryptophan and glutamic acid.

c. Alanine and lysine.

d. Arginine and proline.

e. Leucine and histidine.



ANS: A

N-linked carbohydrate is bound to asparagine, and O-linked carbohydrate is bound to serine
or threonine (or, in collagen, to hydroxylysine).



4. Which of the following is true regarding the structure shown?

-CH2-CH2-COO–

a. Side chain of glutamine; normally found in the interior of globular proteins.

b. Side chain of glutamine; normally found on the surface of globular proteins.

c. Side chain of glutamate; normally found in the interior of globular proteins.

d. Side chain of glutamate; normally found on the surface of globular proteins.

e. Side chain of the “nonstandard” amino acid -carboxyglutamate, found only in some
clotting factors.



ANS: D

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