TUTOR / AL4A :
LEWIS STRUCTURE
2. NANI ?
arrange the following elements by increasing lewis structure of CH O 2
electronegativity. f- lowest electronegativity : - middle element
O, Na, P, Si, N numberofvaience.ec if
" :
: 1×4=4 e-
C
increasing small -10 big H 2×1=28 H H
- -
__ :
Tacwssaperioa.tdownagwupo.li/6--6e:-Na.Si,P.N.O
electronegativity trend :
I2E
-
-
lewis structure for HCN
lewis structure for NO 3 number of valence e-
-
total number of valence electrons present : H :
1×1=19
H -
[ EN :
N :
1×5=5 e- total e- used in bonds C :
1×4=45
i
0 N 1×5=58
-
3×6=188
'
3. bonds 29
-
: = :
✗
o -
N -
o
be 105
- -
charge : ie =
249
lewis structure of CH NH
-
i.
remaining e- =
24-6=168 3 2
* ifyouareunabletocomple-eanpairsonapen.PHratatom
ofvaiencee-ooctetrule.changeoreoftheionbonainge.am
created
number
C 1×4=48
'
:
multiple bond between the peripheral atom and the
central atom
ly
H : 5×1=58
y -
C -
N -
H
: lewis structure of N0J : N :
1×5=58 1 I
H
-
H
14g
:|
- -
I :p
:
-N= :O lewis structure of N H • a
number of valence e-
" "
lewis structure for NOI N :
2×5=108 in -
N
?
/ '
total number of valence e- : H :
4×1=48 H H
149
.
N : 1×5=5
0 :
2×6 = 12 what are the formal charges on each atom in the
I :& I carbonate ion CO 5-
charge : I
µ
-
"
*e Coi
.
lewis structure of
.
:
µ :
lewis structure of NF 3 chas4valenc.ee -4 associated electrons
-
-_ 0
singlebonaedohasovalenc.ee
-
to-alnumberofvalenc.ee associated e-
'
-
7- = -1
1×5=5 e-
:Ij bassociatede =O
-
N donblebonaedohasbvalenc.ee
-
: : -
F
'
:
3×7=219
N
:
: - -
.
268 formal charge of
5=+1
?
lewis structure of PO43
-
0=-1
3-
:|
-
|
total valence e- : j :
P
It
: 1×5=5 e-
:O:-p -
ii
0 :
4×6=24 e- I
charge : 3 e- :
total valence e- shown __
26
32 e- S :
1×6=68
0
-
:
3×6=189
+
lewis structure for NO
ZENcharge :
269
-
:
1×5=5 e-
+
0 :
1×6=68 [ NE0 :/ ??
-
lewis structure of XeF 2
Charge : -
le
toe
-
✗ ei 1×8=88
:& .
-
.
.ie:-& :
F :
2×7=148
228
LEWIS STRUCTURE
2. NANI ?
arrange the following elements by increasing lewis structure of CH O 2
electronegativity. f- lowest electronegativity : - middle element
O, Na, P, Si, N numberofvaience.ec if
" :
: 1×4=4 e-
C
increasing small -10 big H 2×1=28 H H
- -
__ :
Tacwssaperioa.tdownagwupo.li/6--6e:-Na.Si,P.N.O
electronegativity trend :
I2E
-
-
lewis structure for HCN
lewis structure for NO 3 number of valence e-
-
total number of valence electrons present : H :
1×1=19
H -
[ EN :
N :
1×5=5 e- total e- used in bonds C :
1×4=45
i
0 N 1×5=58
-
3×6=188
'
3. bonds 29
-
: = :
✗
o -
N -
o
be 105
- -
charge : ie =
249
lewis structure of CH NH
-
i.
remaining e- =
24-6=168 3 2
* ifyouareunabletocomple-eanpairsonapen.PHratatom
ofvaiencee-ooctetrule.changeoreoftheionbonainge.am
created
number
C 1×4=48
'
:
multiple bond between the peripheral atom and the
central atom
ly
H : 5×1=58
y -
C -
N -
H
: lewis structure of N0J : N :
1×5=58 1 I
H
-
H
14g
:|
- -
I :p
:
-N= :O lewis structure of N H • a
number of valence e-
" "
lewis structure for NOI N :
2×5=108 in -
N
?
/ '
total number of valence e- : H :
4×1=48 H H
149
.
N : 1×5=5
0 :
2×6 = 12 what are the formal charges on each atom in the
I :& I carbonate ion CO 5-
charge : I
µ
-
"
*e Coi
.
lewis structure of
.
:
µ :
lewis structure of NF 3 chas4valenc.ee -4 associated electrons
-
-_ 0
singlebonaedohasovalenc.ee
-
to-alnumberofvalenc.ee associated e-
'
-
7- = -1
1×5=5 e-
:Ij bassociatede =O
-
N donblebonaedohasbvalenc.ee
-
: : -
F
'
:
3×7=219
N
:
: - -
.
268 formal charge of
5=+1
?
lewis structure of PO43
-
0=-1
3-
:|
-
|
total valence e- : j :
P
It
: 1×5=5 e-
:O:-p -
ii
0 :
4×6=24 e- I
charge : 3 e- :
total valence e- shown __
26
32 e- S :
1×6=68
0
-
:
3×6=189
+
lewis structure for NO
ZENcharge :
269
-
:
1×5=5 e-
+
0 :
1×6=68 [ NE0 :/ ??
-
lewis structure of XeF 2
Charge : -
le
toe
-
✗ ei 1×8=88
:& .
-
.
.ie:-& :
F :
2×7=148
228
