Summary MA270 - Financial Math WEBWORK 1 Q&A

Dhari Gandhi MA270 W21
Assignment WebWork 1 due 01/19/2021 at 11:59pm EST



(correct)
1. (1 point) Correct Answers:
What nominal interest rate compounded semi-annually is • 11.8235
equivalent to j12 = 12
5. (1 point)
If )"
"
Answer: 12.304 ?
( g- + ( ITE ) What nominal interest rate compounded quarterly is equiva-
.
=

Answer(s) submitted: lent to j• = 15
• 12.3040
• Percent
( Itd .KZ/2--(1tJII Answer:
is -28% dial
"
=
(1tJyI)4
Answer(s) submitted: "
(correct)
Correct Answers:
jz = 0.123040 • 15.28 eats =
(Itsy )
• 12.3040301202 (correct)
• PERCENT jz-12.3040.IT
✓ Correct Answers: jy =
0.1528

jy=1S.28
-
2. (1 point) • 15.2848
Pepper earns interest at a nominal rate of 7.5
" 6. (1 point)
7. 297
'
(Itsy ) Determine the accumulated value of $1650 in 20 months if
µ
Answer:
.

=
-
expense
Answer(s) submitted: interest is 8 compounded continuously .




"

@ -0.975--0.001)
)
• 7.291284
(correct)
ztj , = t Answer: $ 1885.34
Answer(s) submitted:
g=peJaCn " 084%)
Correct Answers: 0.0-129
j -_
• 1885.34 5=1650 @
• 7.28337808282853 ,
-


3. (1 point) j,=7o29%# (correct)
Correct Answers:
-



S=$l885o34#
Determine the number of regular semi annual payments for • 1885.34083946294
a $20000 loan if the interest rate is j2 = 11% and the payments
are: 7. (1 point)
G How much would need to be invested today in order to have
a)Semi annual payments of $3800: $15000 in 18 months time if interest can be earned at 9 x. compounde

b)Semi annual payments of $4100:
g continuously
Answer: $ .nu peioocn )
g=
Answer(s) submitted:


igggo-p@JoCl8lklS-PSn.y
c)Semi annual payments of $2400: l l
• 13105.74
Answer(s) submitted:
(correct) -




ftp.go.FI/a:p=t3I05.7#
• 6 Correct Answers:
• 5
• 13105.7
• 11
20000Gt 143800
(correct) 8. (1 point)
Correct Answers: n = 6.38 .
. .


What nominal rate compounded continuously will increase
your investment by 125 over loners
/!LnIT
• 6 .




• 5
petrol
.

-
• 11 g =

8. 1093
4. (1 point) Answer: Joao )
What nominal interest rate compounded continuously is Answer(s) submitted:
Ptl .2s =p @
equivalent to j4 = 12 • 8.1093

ppcit.es/=fpei*
" ( co )

did "=(It # )
.




ii. 82% (correct)
Answer: Correct Answers:
Answer(s) submitted: • 8.10930216216329
• 11.82
em =
@ t 14 1 Its .zs=eJad0 )
-




joo-8.1093.LI/Joo=Ll.82I
j = 0.1182


-