BNU1501 ASSIGNMENT-03-SOLUTIONS SEMESTER 2 - 2022
BNU1501 ASSIGNMENT-03-SOLUTIONS SEMESTER 2 - 2022 Perimeter = 14 + 14 + 2π x 7 = 71.98 1m2 = 100 x 100 = 10 000cm2 = 40 x 40/2 = 800 = 0.5 x 1 x 1 = 0.5cm2 area of the remaining sheet = (25 x 20) – (π x 102
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bnu1501 assignment 03 solutions semester 2 2022
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bnu1501 assignment 03 solutions semester 2 2022 perimeter 14 14 2π x 7 7198 1m2 100 x 100 10 000cm2 40 x 402 800 05 x 1 x 1 0